Project 3 Momentum and Energy

docx

School

Southern New Hampshire University *

*We aren’t endorsed by this school

Course

131

Subject

Physics

Date

Dec 6, 2023

Type

docx

Pages

Uploaded by SuperHumanMole4612

SNHU PHY150 Joshua Kays 02/25/2023 Module 7 Project 3 Energy and Momentum

Mass 500 kg Height Peak 1: 75m Valley 1: 0m Peak 2: 45m Valley 2: 0m Peak 3: 15m Potential Energy 367,500 J 0J 220,500 J 0 J 73,500 J Kinetic Energy 0 J 367,500 J 147,000 J 367,500 J 294,000 J Velocity 0 m/s 38.34 m/s 24.25 m/s 38.34 m/s 34.29 m/s Momentum 0 kg m/s 19,170 kg m/s 12,125 kg m/s 19,170 kg m/s 17,145 kg m/s Calculations When we look at this problem we have to write out our known values to see what we can use to calculate the rest of the equation. In the Table above I highlighted those values in green . Next, we look at what we have been asked and need to calculate here as follows: Kinetic Energy Potential Energy Velocity of the Cart Momentum of the Cart v

Formulas PE = mgh This is the straightforward way of calculating the potential energy for each peak and valley that we have in the diagram. KE = TE – PE When looking at what values we have available we can remember that Total Energy is just Potential Energy added to Kinetic Energy. So, we can take the Total Energy and subtract Potential Energy to yield the Kinetic Energy. KE = ½ mv 2 Now we can use the Kinetic Energy formula to determine the velocity of the cart at each point in the track. Since we have already solved to find the kinetic energy previously, we can simply plug in the values that we have and solve for v (velocity). p = mv Finally we can use all of the values that we have determined in order to solve for the momentum at each point in the process. Below is a photo of all my calculations done during this process. Energy Transfer Description The cart starts at the top of the first peak at a height of 75m and we are able to see that until the cart moves all we have is potential energy. When the cart goes down into the first valley that potential energy turns into kinetic energy. This shows us the law of conservation of energy as the potential energy turns into kinetic energy. Then when we reach the second peak we can see in the calculations that the kinetic energy of the cart starts to decrease but the potential energy begins to increase. The total energy of the cart is consistent throughout the entire track as the cart moves toward the second valley and final peak. The energy is just transforming between potential and kinetic energy throughout the entire movement.

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

The Collision The collision is inelastic and therefore the total momentum is carried across the collision and conserved. However, with an inelastic collision the total kinetic energy is not conserved and can only be transformed. Calculations We are asked to calculate the following values for before and after the collision. Momentum Before Collision ( Already Calculated Above ) Momentum After Collision ( Same as Momentum Before Collision) Kinetic Energy Before Collision ( Already Calculated Above) Kinetic Energy After Collision ( Kinetic Energy is not Conserved in Inelastic Collisions) Formulas We already have information about the momentum and initial velocity. Mv i + Mv i = 2Mv f We can plug in the information that we have currently to determine what the final velocity will be. ( Since the momentum is carried throughout the system the momentum after the collision will be the same.)

During the collision as you can see from the calculations the Kinetic Energy is not the same before and after the collision. Cart A has kinetic energy while Cart B had none initially. On impact the two carts become one mass and the momentum is carried through. The Kinetic Energy does not carry through on impact. This is because a portion of that kinetic energy is transformed into thermal energy when the carts impact and become one singular unit. The total system now has less kinetic energy to affect movement and due to the impact it has slowed to velocity of combined mass. In this example conservation of energy is show by how the kinetic energy turns into thermal energy but is can not be destroyed.

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Friction The carts continue along the track, and they will hit the friction portion of the track. They begin to slow down to ultimately come to a complete stop over 20 meters. Let’s look at the known values at this point to calculate the work done due to friction. Mass = 1000 kg Velocity = 17.145 m/s Displacement = 20 m Final Velocity = 0 m/s We can use the work-energy theorem to help us solve this part of the problem. It states that any change in kinetic energy is a result of work done on the system. Now we just need to look at the work being done by friction in this instance. The kinetic energy is transformed into thermal energy through friction during the stopping of the cart. Again this is an example of how the energy is transformed but never destroyed allowing for the law of conservation of energy. Work Formula

Related Documents

Physics Lab 7.pdf

E-Field+Plotting+manual.pdf

Lesson_8_Problem_Set4 (2).docx

Activity 2- Forces Oscillating Systems.docx

Lab 5 Pendulum.docx

Walker Renewable.docx

PHY 132 - Magnetic Field worksheet.pdf

PHY 132 - e_m of the Electron worksheet.pdf

E-Field Plotting worksheet.pdf

Fall2023 Thin Lenses Lab Online (New Simulator)-1.pdf

Fall2023 Reflection and Refraction Lab Online-1.pdf

L10 Refraction of Light.docx

Recommended textbooks for you

Principles of Physics: A Calculus-Based Text

Physics

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Cengage Learning

University Physics Volume 1

Physics

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:OpenStax - Rice University

Physics for Scientists and Engineers: Foundations...

Physics

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Cengage Learning

Physics for Scientists and Engineers

Physics

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Cengage Learning

Physics for Scientists and Engineers with Modern ...

Physics

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Cengage Learning

Physics for Scientists and Engineers, Technology ...

Physics

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Cengage Learning

SEE MORE TEXTBOOKS

Recommended textbooks for you

Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning