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William Rainey Harper College *

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MISC

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Physics

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Oct 30, 2023

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2

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'7'!‘7,",1 ‘,2 \L il 2023 Written Homework: Chapler 8 Problem 1. Charged sheets I}:’;‘r) ,léifg;’. parallel sheet.s have both an area of 1 m?. The left sheet has a total AP " 01 =10 mC and is located at x = 10 cm. The right sheet has a total c¢harge of +10 mC and is located at x = 15 cm. Both sheets are uniformly charged. Points A,BandCareatx =75cm, x = 125cmand x = 17.5 c—m A. A} cach of the marked points draw vectors that indicate the magnitude and A B « f direction of the electric field due only to the positively charged sheet. § i a ; The Ardsic WD ol AR cunony s, ?OQIW*‘(?LWWW flrge)r O~ 1+ Way ¢ Y g e | ) ‘-) K \E l 5 w/LQO . x 10em v Sem B. At eaga of g\e marked points draw vectors that indicate the magnitude and e direction of the electric field due only to the negatively charged sheet. Pet & Uekqve pudd i honve Kame woem udh 2 b effosid ditethen | ousosdy Pas NRuus fheel - : C. Ateach of the marked points draw vectors that indicate the magnitude . . » and direction of the nef electric field due tq both sheets Ax Qoint A ond ¢, Y RS (oun ) 2acha othy, owen®y (+ Rome P Gt Pount § x 10cm v ISem D. Determine the x-component of the net electric field at each point. Part C & X . -2 TR s 0 e fal N2k | >t A B ¢ B A L i - & - I - (“L i 2 & §-§5%io A ’\“3*'QQA)(C‘ x*em x-1Scom M A ond ¢ A -_— E. On the graph below, sketch a plot of the value of the x-component of the electric field (recall that the sheets are located at x = 10 cm and x = 15 cm). Label appropriate values on the vertical axis. E (NIC) r : ..3‘ 0 16 20 as¥lem : ?
F. S s the ; ::;p;lngsg th} c‘harge on the positive sheet is doubled. At cach of the PR e :;:l:;\h dra\\ vectors that ir}dicatc the magnitude and direction of t : at indicate the magnitude ang direction of the net electric field due to both sheets. o BCRy s 22y o= o L (3xion) St 20 266 " 26 2 ; . : : . ¢.bxof N S o < PO BT AL b ve it 26 24 26 2. % c - T/ E(( - ¥ g S e | (\~\3'>k\a°‘) { § [ p— - 1 26k 2 3 _ -5 buaef pide e G. Draw and label a plot of the x-component of the electric field for this new case. E.(NC) T ] ’; lfO 2'0 ;‘r (em) | -5.6 % lo’ r—"1 \ i : \
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