Static Equilibrium1

docx

School

Saint Leo University *

*We aren’t endorsed by this school

Course

221L

Subject

Mechanical Engineering

Date

Jan 9, 2024

Type

docx

Pages

Uploaded by zitoaliyah

General Physics I Laboratory (PHY221L) Static Equilibrium Name: Aliyah Zito Date: 10 / 30 / 23 ______________________________________________________________________________ Introduction State what you show or demonstrate in this laboratory experiment. Include the background/theory and any useful equations used in the lab. (5 points) In this experiment we are using a torque apparatus along with masses and mass hangers to determine where the equilibrium point is within the ruler. We will use different masses on both sides of the ruler and have to move them to certain locations on the ruler to find the balancing location. Materials: Masses, torque apparatus (with 50 cm ruler) and mass hangers. Method Part I 1. Adjust the position of the fulcrum without the hangers until balance is achieved (0-25 is left and 25-50 is right). Record the fulcrum's position ( x 0 ) in table 1. 2. Place 100 g mass at the 22 cm mark (on the left side). Record the distance of the 100 g with respect to the fulcrum position ( x 0 ) in table 1. 3. Place 50 g mass on the other side (on the right side) and move it until balance is achieved. Record the distance of the 50 g with respect to the fulcrum position ( x 0 ) in table 1. Figure 1. Show the experimental setup. 5. Move the 100 g mass 1 cm until the 13 cm mark and adjust the position of the 50 g mass until balance is achieved. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 1. Part II 1. Remove the 100 g mass. Place the 50 g mass at the 20 cm mark (on the left side) and place the 40 g mass to the other side (on the right side). Adjust the position of the 40g mass until w w x L x R x 0

balance is achieved. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 2. 2. Move the 50 g mass 1 cm until the 11 cm mark and adjust the position of the 40 g mass until balance is achieved. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 2. Part III 1. Place the 50 g mass at the 28 cm mark (on the right side). Add the 20 g mass on the other side (on the left side) and adjust its position until balance is achieved. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 3. 2. Change the position of the 50 g mass 1 cm until the 35 cm mark and adjust the position of the 20 g mass until balance is achieved. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 3. Part IV 1. Place the 50 g mass at the 38 cm mark (on the right side) and place the 30 g mass on the other side (on the left side). Adjust its position until balance is achieved. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 4. 2. Move the 50 g mass 1 cm until you reach the 29 cm mark and adjust the position of the 30 g mass until balance is achieved for every change in the 50 g mass position. Record the distances of both masses with respect to the fulcrum position ( x 0 ) in table 4. Results (45 points) Place your data in this section Table 1 x 0 = m m L = kg m R = kg w L = N w R = N x L ( m ) x R ( m ) τ L (N.m) τ R (N.m) τ Percent difference % 2

0.03 0.052 0.029 0.0253 13.7 0.04 0.074 0.039 0.3626 161.2 0.05 0.096 0.049 0.4704 162.3 0.06 0.115 0.059 0.0564 4.51 0.07 0.135 0.069 0.0662 4.14 0.08 0.155 0.078 0.07595 2.66 0.09 0.174 0.088 0.0853 3.12 0.10 0.193 0.098 0.0946 3.53 0.11 0.215 0.108 0.1054 2.44 0.12 0.232 0.118 0.1137 3.71 Table 2 x 0 = m m L = kg m R = kg w L = N w R = N x L ( m ) x R ( m ) τ L (N.m) τ R (N.m) τ Percent difference % 0.05 0.056 0.025 0.022 12.8 0.06 0.071 0.029 0.028 3.51 0.07 0.083 0.034 0.033 2.99 0.08 0.095 0.039 0.037 5.26 0.09 0.110 0.044 0.043 2.30 0.10 0.124 0.049 0.049 0 0.11 0.131 0.054 0.051 5.71 0.12 0.146 0.059 0.057 3.45 0.13 0.160 0.064 0.063 1.57 0.14 0.172 0.069 0.067 2.94 Table 3 x 0 = m m L = kg m R = kg w L = N w R = N x L ( m ) x R ( m ) τ L (N.m) τ R (N.m) τ Percent difference % 0.079 0.03 0.1548 0.0147 165.3 3

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

0.109 0.04 0.0214 0.0196 8.78 0.125 0.05 0.0245 0.0245 0 0.153 0.06 0.0299 0.0294 1.69 0.179 0.07 0.3508 0.0343 164.4 0.203 0.08 0.0398 0.0392 1.52 0.224 0.09 0.0439 0.0441 45.5 0.247 0.10 0.4841 0.0490 163.2 Table 4 x 0 = m m L = kg m R = kg w L = N w R = N x L ( m ) x R ( m ) τ L (N.m) τ R (N.m) τ Percent difference % 0.215 0.13 0.063 0.064 1.57 0.200 0.12 0.059 0.059 0 0.188 0.11 0.055 0.054 1.83 0.169 0.10 0.050 0.049 2.02 0.153 0.09 0.045 0.044 2.25 0.136 0.08 0.040 0.039 2.53 0.123 0.07 0.036 0.034 5.71 0.105 0.06 0.031 0.029 6.67 0.090 0.05 0.026 0.025 3.92 0.070 0.04 0.021 0.010 71.0 Data Analysis (30 points) 1. Calculate the weight of each mass ( w L = m L g and w R = m R g ) in table 1-4. Include a sample of your calculations below. (10 points) Table 1 0.1x9.8=0.98 4

Table 2. 0.5x9.8=0.49 Table 3. 0.02x9.9=0.196 Table 4 0.02x9.8=0.294 2. Using the weight and distance with respect to fulcrum data, calculate the torque of the weight on the left ( τ L = x L w L ) and on the right ( τ R = x R w R ). Write your answers for each value in table 1-4. Include a sample of your calculations below. (10 points) Table 1 TL= (0.03 x 0.098)=0.00294 TR=(0.052 x 0.49) = 0.02548 Table 2 TL=(0.03 X 0.098)= 0.0245 TR=(0.052 X 0.392)=0.021952 Table 3 TL= (0.079 x 0.196)= 0.01548 TR=(0.03 x 0.49 )=0.147 Table 4 TL=(0.215 x 0.294)=0.06321 TR=(0.13 x 0.49)=0.0637 3. Compare between the torque on the left and the right by calculating the percent difference ( ¿ τ L − τ R ∨ ¿ τ L + τ R 2 × 100% ¿ ). Write your answer for each value in table 1-4. Include a sample of your calculations below. (10 points) Table 1 (0.029-0.0253)/(0.029 + 0.0253)/2)=13.7 % Table 2 (0.0250-0.022)/((0.25+0.22)/2)=12.8% Table 3 (0.0214-0.0196)/((0.0214+0.0196)/2)=8.78% Table 4 (0.063-0.064)/((0.063+0.064)/2)=1.57% 5

Conclusion (10 points) State the main conclusions along with a discussion of your results. To conclude in this experiment we had a fulcrum mass and we had to move the other mass on the right side of the ruler in order to find where they would balance. After we calculated and found the torque in respect of the fulcrum data. Our results showed that the highest torque on the left was in table 4 and on the right side was table 3. Our lowest percent difference was in table 4, being 1.57% 6

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version