PHY122_Vectors%26Statics_worksheet

Need help, round answers to 3 sig figs please

sample calculations 目 File Edit View Insert Format Data To 100% $ % .0 .00 12: fx | A 1 Variable Value Units diameter height m 4 volume m^3 3 The image above shows a section of a Google sheet. What formula should be written in cell B4 to calculate the volume of a cylinder with a diameter value in B2 and height in B3? a) =0.25*PI()*B2^2 * B3 b) =PI()*B2^2 * B3 c) =pi*diameter^2 * height d) =PI*B2^2 * B3 3 5

Part III Capstone Problem Interactive Physics - [Lab7Part3.IP] Eile Edit World View Object Define Measure Script Window Help Run StoplI Reset 圖|& 品凸? Time Length of Spring 22 6.00 dx Center of Mass of Rectangle 2 5.000 Tension of Rope 3 Jain@ IFI ... N ot rot ***lad Split 4.000 Velocity of Center of Mass of Rectangle 2 Vx Vx V Vy MM Ve - m/s m/s 3.00 *** m/s Vo ..* lad/s 2 00 Center of Mass of Rectangle 1 1.000 tol rot *.* rad EVelocity of Center of Mass of Rectangle 1 Vx Vx VVy M 0.000 -m/s w 30 m/s w.. MI Ve 母100 *** m/s Vo ... rad/s + EAcceleration of Center of Mass of Rectangle 1 Ax Ax A Ay AUJAI Ae --- m/s^2 ... m/s^2 -- m/s^2 .-- rad/s^2 3.00 Aø Mass M1 = 2.25 kg is at the end of a rope that is 2.00 m in length. The initial angle with respect to the vertical is 60.0° and M1 is initially at rest. Mass M1 is released and strikes M2 = 4.50 kg exactly horizontally. The collision is elastic. After collision, mass M2 is moving on a frictionless surface, but runs into a rough patch 2.00…

You are watching a live concert. You can also find the concert streaming live on Spotify. About how far must you stand from the stage in order for the live concert and the live stream to be perfectly in sync? HINT: Assume the radio signal (Spotify) has to travel all the way around the Earth. circumference of the Earth (average): 40,041,000 m Speed of sound: 345 m/s Speed of light: 300,000,000 m/s

A mechanic changing a tire rolls a wheel along the ground towards the car. The radius of the wheel is 42cm, and the speed of the wheel as it rolls is 2 revolutions per second. Height Above Ground (m) radiu HIDE wheel spet Time The diagram above illustrates the vertical motion of a point on the tire over time. It is possible to model the height of this point using a sinusoidal function of the form h(t)=-a sin[b(t-c)]+d. a) Determine the length of time required for one revolution of the tire. b) State the numerical value for each of the parameters a, b, c & d. And write a function representing the motion of the point in the form h(t)= -a sin[b(t−c)]+d.

Given: The plane accelerates in its current trajectory with a= 100 m/s^2 Farag Angle theta= 5° W=105 kips F_drag= 80 kips m= 1000 lbs Find: F_thrust, F_lift Please include the KD. Fthrust Futel t Fueight 000 BY NC SA 2013 Michael Swanbom

Please Solve correctly [ Mechanical- Dynamics]

From the image below, identify the values of the position coordinates SA and SB. SA is for block A and B is for pulley B. Datum 2 4m 2m $A Number $B = Number m m B с ▬▬ Datum 1 5m 3m A @ 09 Engineering

From the image below, and using the given datum, match the variable expressions to their position coordinates, SA, SB and SC, where s A is for block A, $3 is for pulley B, and so is for pulley C. If an expression does not match any position coordinate, then match it to the "None" option. 1.k-q 2.0 3.p 4. k SA Datum bc SC k ✓ None SB ФВ A Р ⒸOF

1- 3D model with dimensions (SE or SW view) and 2- The 3D model's Top view Note : use creo parametric to show the above view R30 R12 70 20 R20 40 20 26 024 24 R16 50 20 80 100

The vector expressions for the position vectors for cables “AC” and “AD” are given by: rAC = -3i - j - 6k ft and rAD = ­ 2i + 3j - 6k ft respectively.  What is the length of cable “AD”?

Steam enters an adiabatic turbine steadily at 6 MPa and 450 °C and leaves at 500 kPa and 250 °C. If the power output of the turbine is 3.9 MW determine the isentrFopic efficiency of the turbine and the mass flow rate of the steam flowing through the turbine. TI Pi T2 P2 %23

For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution] Position vs time Velocity vs time Acceleration vs time Force vs time [For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner) Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at  t = 4 second ? a =(50 e^t)/(550 ) [N/kg] v = ∫_0^t▒(50 e^t )dt/(550 )= v_0  +(50 e^t-50)/550=((e^t- 1))/11 x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0  +(e^t- t - 1)/(11 ) a(4s)=(50*54.6)/550= 4.96[m/s^2 ] v(4s)=((e^4-1))/11= 4.87[m/s] x(4s)=((e^4- 4 - 1))/11= 4.51 [m]

HW4 Q9