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Kinematics pls put clear solution ty

O 17161489 C Get Homework Help With b My Questions | bartleby O Mail - Castro Alvarez, Flavic X Content A learn-us-east-1-prod-fleet01-xythos.s3.amazonaws.com/5c1270dbb5a74/17161489?response-cache-control=private%2C%20max-age%3D21600&respon. ☆ ME 3022 - HW 19 1. (More practice from Monday) A 90° elbow in a horizontal pipe is used to direct a flow of oil (SG = 0.87) upward at a rate of 40 kg/s. The cross- sectional diameter of the elbow is a constant 20 cm. The elbow discharges at A into a large holding tank where the level of oil is 1.8 m above A. The 50 cm "weight" of the elbow and the oil in it is 50 kg. Determine (a) the gage pressure at the inlet of the elbow and (b) the anchoring force needed to hold the elbow stationary. Take the momentum-flux correction factor to be 1.03 40 kg/s at both the inlet and the outlet. Activar Windows Ve a Configuración para activar Windows. Esperando blackboard.ohio.edu. 17:07 P Escribe aquí para buscar a ) ENG 14/10/2020 近

Create in multisim this circuit

IKT f 327 DXD 187 S 487

please check my solution thank you

kindly explain the house of quality of this thank you

y On = 0, cos²0 + o, sin²0 + 2 Txy sin 0 cos 0 15.00 Tnt = -(0x - Oy) sin 0 cos 0 + txy( cos²0- sin?0) These equations may also be written as: Ox+Oy On Ox- Oy cos 20 + Txy sin 20 2 8.00 2 Ox- Oy Tnt sin 20 + Txy Cos 20 2 = - 10.00 10.00 55° 8.00 On Both the xyz and ntz coordinate systems are right-handed systems. The z axis is directed 15.00 Tnt toward the viewer. 1st 2nd 3rd Enter solved problems counter attempt