HW11

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California Polytechnic State University, San Luis Obispo *

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422

Subject

Mechanical Engineering

Date

Feb 20, 2024

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pdf

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2

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CE 422 Highway Geometrics and Design Homework Assignment No.1 Name: _________ KEY __________________ Score: _______ (see back) 1. Determine the range of design speeds that would apply to these streets and highways in our area, based on Highway Design Manual Table 101.2. (2) Location Range of Design Speeds Reason (roadway classification, terrain, local facility) Route 101 over Cuesta Grade 40-50 Rural Conventional in Mountainous Terrain Route 1 from SLO to Cuesta College 50-60 Rural Conventional in Rolling Terrain Route 101 through SLO 55-80 Urban Freeway Route 41 from Morro Bay to Atascadero 40-50 Rural Conventional in Mountainous Terrain Santa Rosa Street (Route 1) in northern SLO 40-60 or 30-40 Urban Conventional Arterial Street (maybe a Main Street.) Chorro Street crossing under Route 101 freeway 30 Min or local standard Local facility crossing a freeway California Blvd connecting to Route 101 freeway 35 or 45 Local facility connecting to a freeway 2. Calculate the delta between these bearings. Give your answers in degrees/ minutes/ seconds and show your work: (3) N 70°52’11” E to N 35°17’32” W Both North, so add. 11+32=43” 52+17=69’=1°09’ Carry 1 70+35+1=106° 106°09’43” N 55°18’20” W to N 22°05’38” W Same quadrant, so subtract. 20-38= -18=42” Borrow 1 from minutes 18-05-1=12’ 55-22=33° 33°12’42” N 72°12’16” E to S 60°33’11” E Both East, so subtract sum from 180. 16+11= 27” 12+33= 45’ 72+60= 132° 179°59’60”-132°45’27”= 47°14’33” Or use decimal: 180-(72.2044+60.5531)= 47.2425 = 47°14’33”
CE 422 Highway Geometrics and Design Homework Assignment No.1 3. A traverse consists of one line, bearing N 41°20’ E, and a second line, with a deflection angle ( Δ ) between them of 34°42’ to the right. Draw a diagram of this traverse and calculate the bearing of the second line. (1) 20+42=62’=1°02’ Carry 1. 41+34+1=76° N 76°02’ E 4. Consider the following circular horizontal curve that connects two tangent highway sections. Please show your work and state answer in US units, with distance accurate to .01 ft and angles in DMS: (4) a) What is the deflection angle of the curve ( Δ )? Δ =78°45’55” – 66°25’53” = 12°20’02” Or, Δ =78.7653 – 66.4314 = 12.3339 = 12°20’02” b) What is the length of the curve (L)? L=2419.53 – 2161.21 = 258.32 ft c) What is the radius of the curve (R)? R=180 x L / ( Δ x π ) =180 x 258.32 / (12.3339 x 3.14159) = 1200 ft d) What is the tangent length of the curve (T)? T=R x tan ( Δ / 2) = 1200 x tan (12.3339 / 2) = 129.66 ft e) How long would the curve length (L) be if the radius is increased to 1600 ft? L= π R Δ /180 = (3.14159 x 1600 x 12.3339) /180 = 344.43 ft Bonus Point: List three songs (with artists) based on roads, highways, or driving:
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