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Feb 20, 2024
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Q4: Is the slope of the position graph (your answer to Q1) between the min and max? Tap or click on the File Menu icon in the top left of your screen and Export a CSV of your data. Open up the data you exported in MS Excel. We are going to test to see whether the accelerometer data is consistent with the position data. We could do this by numerically differentiating the position data, but numerical differentiation is unstable. (The Graphical Analysis software uses sophisticated methods to overcome this challenge.) However, numerical integration is stable, so we will instead numerically integrate the accelerometer data and compare that to the position data. You will need a column with the time, a column with the X-axis accelerometer data, a new column for calculated velocity, and a new column for calculated position. For the first row of data, where the time is zero, input a calculated velocity and a calculated position of 0. In the later columns for velocity, calculate the next cell down as the previous calculated velocity plus the previous acceleration times the “time step”. The time step is the sampling interval, or the difference in time from one row to the next. In the position column, calculate the position as the previous position plus the previous velocity times the “time step”. Copy these formulas all the way down. Create a plot of your calculated position vs time and on the same plot show the sensor position data vs time. Copy and paste your plot into your lab report. Q5: How well does your calculated position agree with the measured position? What do you think is the greatest source of any discrepancy between the two? Constant Acceleration Now we are going to try to create some motion with constant acceleration. We are going to use the spring- loaded plunger on the second cart to launch the first cart. 1. Attach the rubber stopper to the end of the cart by screwing it into the force sensor. 2. Place the track on the table and put a brick under one end so that the track is sloped. 3. Place the second cart (the one not connected to the Graphical Analysis program) on the lower end of the track, with the spring-loaded plunger pointing to the upper end of the track. 4. Depress the plunger until it locks into place. Place the original cart on the track so that the rubber stopper is resting against the plunger. 6. Tap or click on the “Position” button in the bottom right corner of the screen to bring up the Sensor Menu. Zero the sensor and turn on the “Reverse” option 7. Start a data collection by tapping or clicking on the “Collect” button. 8. When data starts to appear, press the dark gray button above the plunger. This will release the spring and launch the original cart forward up the track. 9. Continue to hold the second cart (the launcher). Wait until the first cart comes back down the track and the rubber stopper contacts the extended plunger. Then stop the data collection by tapping or clicking on the “Stop” button. o First, take a quick peek at a plot of the Position vs. time. To change what plot is displayed, tap or click on the y-axis label and toggle the columns to show the ones you want. Q6: What shape is the Position vs. Time curve, and what does this mean? PHYS2215 Velocity and Acceleration Lab Page 3
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I’m making the graph that you see in the picture but the code that I’m using makes the line with to many curves. Could you make the lines look like the one that you see on the graph. Don’t change the color just make it with a little bit less curves like you see in the picture.
Use this code on MATLAB and fix it.
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Fix the random seed for reproducibility
rng(50);
% Assumed CO2 emissions for Diesel and Petrol
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves
pDiesel = polyfit(carPosition, CO2Diesel, 3);
pPetrol = polyfit(carPosition, CO2Petrol, 3);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);
fitPetrol = polyval(pPetrol, carPosition);
% Combined best fit
combinedFit = (fitDiesel + fitPetrol) / 2;…
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Hello I’m trying to make the graph that you see in the picture, I’m trying the exact copy of that graph using this code but I’m having a hard time doing that. Could you change the code so that it looks like the graph that you see on the picture using MATLAB, please send the code when you are finished.
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Fix the random seed for reproducibility
rng(45);
% Assumed positions of cars
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves
pDiesel = polyfit(carPosition, CO2Diesel, 3);
pPetrol = polyfit(carPosition, CO2Petrol, 3);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);
fitPetrol = polyval(pPetrol, carPosition);
% Plotting the data
figure; hold on;
scatter(carPosition, CO2Diesel, 'o', 'MarkerEdgeColor', [1 0.5…
arrow_forward
Could you please fix my code it’s supposed to look like the graph that’s on the picture. But the lines do not cross eachother at the beginning. Could you make the lines look like the lines on the graph?
Use this code in MATLAB and fix it.
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Define your seed here
seed = 50;
rand('seed',seed); % Set the seed for reproducibility
% Assumed CO2 emissions for Diesel and Petrol
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves with a reduced degree of 2
pDiesel = polyfit(carPosition, CO2Diesel, 2);
pPetrol = polyfit(carPosition, CO2Petrol, 2);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);
fitPetrol = polyval(pPetrol, carPosition);
% Plotting the data
figure;
hold on;
% Plot Diesel best fit line…
arrow_forward
This code keeps on generating graphs with different curves. The picture that you see two different graphs comes from the same code but both of them have different curves. I need the curve to look like the picture that only has one graph. I basically need the line to have a slight curve and every time I run the code it will come up as the same graph every time. Use this code on MATLAB and fix it
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Use the 'seed' function instead of 'rng'
seed = 50; % Define your seed here
rand('seed',seed);
% Assumed CO2 emissions for Diesel and Petrol
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves with a reduced degree of 2
pDiesel = polyfit(carPosition, CO2Diesel, 2);
pPetrol = polyfit(carPosition, CO2Petrol, 2);
% Generate points for best fit…
arrow_forward
Use MATLAB
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There is a small space between the orange and purple line could you please connect the two lines together also can you please make the purple line shorter and then connect the purple line to the orange line, please take out the box that says “Diesel, petrol, Diesel best fit, petrol best fit”. Also when ever I run this code the graph shows up but there are still errors that comes up could you please fix them when you are running this on MATLAB.
Please use this code on MATLAB and fix it.
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Fix the random seed for reproducibility
rng(50);
% Assumed CO2 emissions for Diesel and Petrol
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves
pDiesel = polyfit(carPosition, CO2Diesel, 3);
pPetrol = polyfit(carPosition, CO2Petrol, 3);
% Generate…
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Please type out and or diagram Your solution in a way that is easy to read I have bad eyesight
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Hi I need help to make the line change into a different color, I half of the line to be orange and I need the other half of the line towards the end to be purple as shown in the picture. Also I need there be a box saying Diesel, petrol, diesel best fit, petrol best fit. This part is also shown in the graph.
Please use this code and fix it in MATLAB:
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Fix the random seed for reproducibility
rng(50);
% Assumed positions of cars
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves
pDiesel = polyfit(carPosition, CO2Diesel, 3);
pPetrol = polyfit(carPosition, CO2Petrol, 3);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);
fitPetrol = polyval(pPetrol, carPosition);
% Combine the best fit lines
combinedFit =…
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How do I input this code for this MATLAB problem? Thanks!
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I need help with the purple line the line that you see one the graph on the picture needs to be on the graph.
Use this code to add the purple line and make sure it’s crossing the orange line. Please make sure the lines are positioned the same way it is shown on the picture with the graph.
Use this code on MATLAB and add the purple line.
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Use the 'seed' function instead of 'rng'
seed = 50; % Define your seed here
rand('seed',seed);
% Assumed CO2 emissions for Diesel and Petrol
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves with a reduced degree of 2
pDiesel = polyfit(carPosition, CO2Diesel, 2);
pPetrol = polyfit(carPosition, CO2Petrol, 2);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);…
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Please examine how you got answer step by step please
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I was going over the equations for the notes in class and I had a thought. Based on the equations in the image, you could get negative propellant mass. So, I coded it in matlab and I got negative mass. How is that possible? I think I used practical values for the velocity and mass ratio and so on. Did I do something wrong?
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Motiyo
Add explanation
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Please make this on MATLAB, make the graph shown on the picture, copy the orange and blue circles and the line please make sure that they are on the exact same spots. Make the exact copy of the graph please. Nothing different, just make the same graph and put the orange and blue circles on the exact spots and make sure the lines are the same and make sure the title of the graph is their as well. They rest of the pictures that has numbers are the data that is believed to be the orange and blue dots . Take your time please. I need help with this.
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I’m using this code in MATLAB but for some odd reason every time I run it on MATLAB I keep on getting a different graphs. In the picture that shows two different graphs are from the same code, but I need to it to look like the picture that has one graph. Could you please fix it. To make it look like the picture that has one graph?
Here is the code:
% Sample data for Diesel and Petrol
carPosition = linspace(1, 60, 50); % Assumed positions of cars
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves
pDiesel = polyfit(carPosition, CO2Diesel, 3);
pPetrol = polyfit(carPosition, CO2Petrol, 3);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);
fitPetrol = polyval(pPetrol, carPosition);
% Plotting the data
figure;
hold on;
scatter(carPosition, CO2Diesel, 'o', 'MarkerEdgeColor', [1 0.5 0]); % Diesel data…
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Don't Use Chat GPT Will Upvote And Give Handwritten Solution Please
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Don't Use Chat GPT Will Upvote And Give Handwritten Solution Please
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Could you change the lines in to two lines just like it shows in the graph . Make it exactly those two lines. Keep the colors and the same.
Use this code on MATLAB and fix it.
% Sample data for Diesel and Petrol cars
carPosition = linspace(1, 60, 50); % Assumed positions of cars
% Define your seed here
seed = 50;
rand('seed',seed); % Set the seed for reproducibility
% Assumed CO2 emissions for Diesel and Petrol
CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel
CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol
% Fit polynomial curves with a reduced degree of 2
pDiesel = polyfit(carPosition, CO2Diesel, 2);
pPetrol = polyfit(carPosition, CO2Petrol, 2);
% Generate points for best fit lines
fitDiesel = polyval(pDiesel, carPosition);
fitPetrol = polyval(pPetrol, carPosition);
% Combined best fit
combinedFit = (fitDiesel + fitPetrol) / 2;
% Plotting the data
figure; hold on;
% Define the split index and shorten…
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Don't Use Chat GPT Will Upvote And Give Solution In 30 Minutes Please
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Please follow the instructions and the requirements according to the pictures above and I kinda need the solution quickly. The language of the code is in Matlab, thank you in advance.
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I need help with this question. :)
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Help solve this USING MATLAB
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For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution]
Position vs time
Velocity vs time
Acceleration vs time
Force vs time
[For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner)
Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at t = 4 second ?
a =(50 e^t)/(550 ) [N/kg]
v = ∫_0^t▒(50 e^t )dt/(550 )= v_0 +(50 e^t-50)/550=((e^t- 1))/11
x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0 +(e^t- t - 1)/(11 )
a(4s)=(50*54.6)/550= 4.96[m/s^2 ]
v(4s)=((e^4-1))/11= 4.87[m/s]
x(4s)=((e^4- 4 - 1))/11= 4.51 [m]
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4. Documents business requirements use-case narratives.for only one process
note: please i want Documents like this in pic
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Related Questions
- I’m making the graph that you see in the picture but the code that I’m using makes the line with to many curves. Could you make the lines look like the one that you see on the graph. Don’t change the color just make it with a little bit less curves like you see in the picture. Use this code on MATLAB and fix it. % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Fix the random seed for reproducibility rng(50); % Assumed CO2 emissions for Diesel and Petrol CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves pDiesel = polyfit(carPosition, CO2Diesel, 3); pPetrol = polyfit(carPosition, CO2Petrol, 3); % Generate points for best fit lines fitDiesel = polyval(pDiesel, carPosition); fitPetrol = polyval(pPetrol, carPosition); % Combined best fit combinedFit = (fitDiesel + fitPetrol) / 2;…arrow_forwardHello I’m trying to make the graph that you see in the picture, I’m trying the exact copy of that graph using this code but I’m having a hard time doing that. Could you change the code so that it looks like the graph that you see on the picture using MATLAB, please send the code when you are finished. % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Fix the random seed for reproducibility rng(45); % Assumed positions of cars CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves pDiesel = polyfit(carPosition, CO2Diesel, 3); pPetrol = polyfit(carPosition, CO2Petrol, 3); % Generate points for best fit lines fitDiesel = polyval(pDiesel, carPosition); fitPetrol = polyval(pPetrol, carPosition); % Plotting the data figure; hold on; scatter(carPosition, CO2Diesel, 'o', 'MarkerEdgeColor', [1 0.5…arrow_forwardCould you please fix my code it’s supposed to look like the graph that’s on the picture. But the lines do not cross eachother at the beginning. Could you make the lines look like the lines on the graph? Use this code in MATLAB and fix it. % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Define your seed here seed = 50; rand('seed',seed); % Set the seed for reproducibility % Assumed CO2 emissions for Diesel and Petrol CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves with a reduced degree of 2 pDiesel = polyfit(carPosition, CO2Diesel, 2); pPetrol = polyfit(carPosition, CO2Petrol, 2); % Generate points for best fit lines fitDiesel = polyval(pDiesel, carPosition); fitPetrol = polyval(pPetrol, carPosition); % Plotting the data figure; hold on; % Plot Diesel best fit line…arrow_forward
- This code keeps on generating graphs with different curves. The picture that you see two different graphs comes from the same code but both of them have different curves. I need the curve to look like the picture that only has one graph. I basically need the line to have a slight curve and every time I run the code it will come up as the same graph every time. Use this code on MATLAB and fix it % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Use the 'seed' function instead of 'rng' seed = 50; % Define your seed here rand('seed',seed); % Assumed CO2 emissions for Diesel and Petrol CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves with a reduced degree of 2 pDiesel = polyfit(carPosition, CO2Diesel, 2); pPetrol = polyfit(carPosition, CO2Petrol, 2); % Generate points for best fit…arrow_forwardUse MATLABarrow_forwardThere is a small space between the orange and purple line could you please connect the two lines together also can you please make the purple line shorter and then connect the purple line to the orange line, please take out the box that says “Diesel, petrol, Diesel best fit, petrol best fit”. Also when ever I run this code the graph shows up but there are still errors that comes up could you please fix them when you are running this on MATLAB. Please use this code on MATLAB and fix it. % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Fix the random seed for reproducibility rng(50); % Assumed CO2 emissions for Diesel and Petrol CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves pDiesel = polyfit(carPosition, CO2Diesel, 3); pPetrol = polyfit(carPosition, CO2Petrol, 3); % Generate…arrow_forward
- Please type out and or diagram Your solution in a way that is easy to read I have bad eyesightarrow_forwardHi I need help to make the line change into a different color, I half of the line to be orange and I need the other half of the line towards the end to be purple as shown in the picture. Also I need there be a box saying Diesel, petrol, diesel best fit, petrol best fit. This part is also shown in the graph. Please use this code and fix it in MATLAB: % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Fix the random seed for reproducibility rng(50); % Assumed positions of cars CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves pDiesel = polyfit(carPosition, CO2Diesel, 3); pPetrol = polyfit(carPosition, CO2Petrol, 3); % Generate points for best fit lines fitDiesel = polyval(pDiesel, carPosition); fitPetrol = polyval(pPetrol, carPosition); % Combine the best fit lines combinedFit =…arrow_forwardHow do I input this code for this MATLAB problem? Thanks!arrow_forward
- I need help with the purple line the line that you see one the graph on the picture needs to be on the graph. Use this code to add the purple line and make sure it’s crossing the orange line. Please make sure the lines are positioned the same way it is shown on the picture with the graph. Use this code on MATLAB and add the purple line. % Sample data for Diesel and Petrol cars carPosition = linspace(1, 60, 50); % Assumed positions of cars % Use the 'seed' function instead of 'rng' seed = 50; % Define your seed here rand('seed',seed); % Assumed CO2 emissions for Diesel and Petrol CO2Diesel = 25 + 5*cos(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Diesel CO2Petrol = 20 + 5*sin(carPosition/60*2*pi) + randn(1, 50)*5; % Random data for Petrol % Fit polynomial curves with a reduced degree of 2 pDiesel = polyfit(carPosition, CO2Diesel, 2); pPetrol = polyfit(carPosition, CO2Petrol, 2); % Generate points for best fit lines fitDiesel = polyval(pDiesel, carPosition);…arrow_forwardPlease examine how you got answer step by step pleasearrow_forwardI was going over the equations for the notes in class and I had a thought. Based on the equations in the image, you could get negative propellant mass. So, I coded it in matlab and I got negative mass. How is that possible? I think I used practical values for the velocity and mass ratio and so on. Did I do something wrong?arrow_forward
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