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University of Nairobi *

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1020

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Mechanical Engineering

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Nov 24, 2024

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1 Physics Problems Student’s Name Institutional Affiliation Course Code and Name Professor’s Name Due Date
2 Question 1 First, find the total weight: 646 N (person) + 96 N (bike) = 742 N. Since the weight is distributed evenly between 2 tires, each tire supports 742 N / 2 = 371 N. Now, use the formula for pressure: Pressure = Force / Area. We want to find the area of contact (A). Rearrange the formula: A = Force / Pressure. Plug in the values: A = 371 N / 8.40 x 10^5 Pa ≈ 4.41 x 10^(-4) square meters (or square m). So, each tire's contact area is about 4.41 x 10^(-4) square meters. Question 2 a) When =0.19 m PB = PA + PG =1.013×105Pa+(1420kg/m3×9.81m/s2× 0.19 m) Calculating this gives: PB = 1.013×105Pa+2615.884Pa = 1.015×105Pa (b) When =0.08 m: PB =1.013×105Pa+(1420kg/m3×9.81m/s2×0.08m) Calculating this gives: PB = 1.013×105Pa+902.784Pa = 1.014×105Pa Question 3 Given a pressure difference of 120201 of an atmosphere:
3 Pressure difference=1/20×101325 Pa=5066.25 PaPressure difference=201 ×101325Pa=5066.25Pa Using the formula =Pressure difference/ ( ρ × g) =5066.25 Pa/ (1032 kg/m3×9.81 m/s2) ≈0.495 m So, the diver can go approximately 0.495 m below the water's surface using a snorkel, given the pressure difference constraint.
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