MATH302 D011 Fall 2023 - APEI
pdf
keyboard_arrow_up
School
American Public University *
*We aren’t endorsed by this school
Course
302
Subject
Mathematics
Date
Feb 20, 2024
Type
Pages
24
Uploaded by BarristerDugongPerson958
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
1/24
Week 7 Knowledge Check Homework Practice Questio…
Attempt 1 of 4
Written Jan 17, 2024 3:07 PM - Jan 17, 2024 3:56 PM
Attempt Score
17 / 20 - 85 %
Overall Grade (Highest Attempt)
17 / 20 - 85 %
Question 1
1 / 1 point
A vacation resort rents SCUBA equipment to certified divers. The resort
charges an up-front fee of $25 and another fee of $12.50 an hour. What is
the independent variable?
Hide ques±on 1 feedback
fee amount
driver certification
time
resort location
The equation is
Dollars = $12.5(hour) + $25
Dollars depends on how many hours you use the equipment for.
Dollars is the dependent variable and time (in hours) is the independent
variable.
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
2/24
Question 2
1 / 1 point
Which of the following equations are linear?
Hide ques±on 2 feedback
Question 3
1 / 1 point
You move out into the country and you notice every Spring there are more
and more Deer Fawns that appear. You decide to try and predict how many
Fawns there will be for the up coming Spring.
You collect data to, to help estimate Fawn Count for the upcoming Spring
season. You collect data on over the past 10 years.
x1 = Adult Deer Count
x2 = Annual Rain in Inches
x3 = Winter Severity
Where Winter Severity Index:
1 = Warm
2 = Mild
3 = Cold
8x
3
+4y
2
y=6x+8
3y=6x+5y
2
y-x=8x
2
A linear equation is a linear line. If a problem has a squared or a cubed term, it
isn't linear. It is a quadratic equation.
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
3/24
4 = Freeze
5 = Severe
Approximately what percentage of the variation for Fawn Count is accounted
for by these 3 variables in this model?
See Attached Excel for Data.
Deer data.xlsx
Hide ques±on 3 feedback
11.05% of variation in Fawn Count is accounted for by Adult Count,
Annual Rain in inches and Winter Severity in this model.
98.86% of variation in Fawn Count is accounted for by Adult Count,
Annual Rain in inches and Winter Severity in this model.
98.25% of variation in Fawn Count is accounted for by Adult Count,
Annual Rain in inches and Winter Severity in this model.
97.74% of variation in Fawn Count is accounted for by Adult Count,
Annual Rain in inches and Winter Severity in this model.
You can run a Multiple Linear Regression Analysis using the Data Analysis
ToolPak in Excel.
Data -> Data Analysis -> Scroll to Regression
Highlight Fawn Count for the Y Input:
Highlight columns Adult Count to Winter Severity for the X Input:
Make sure you click on Labels and Click OK
If done correctly then
R Square
0.977400423
Adjusted R
Square
0.966100634
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
4/24
Question 4
1 / 1 point
You are thinking about opening up a Starbucks in your area but what to know
if it is a good investment. How much money do Starbucks actually make in a
year? You collect data to, to help estimate Annual Net Sales, in thousands, of
dollars to know how much money you will be making.
You collect data on 27 stores to help make your decision.
x1 = Rent in Thousand per month
x2 = Amount spent on Inventory in Thousand per month
x3 = Amount spent on Advertising in Thousand per month
R-squared:
97.74% of variation in Fawn Count is accounted for by Adult Count, Annual
Rain in inches and Winter Severity in this model.
If you want to give a more conservative estimate, you can use the Adjusted R-
squared. This can make sure you don't over promise on what the model can
do. But the interpretations are the same.
Adjusted R-squared:
96.61% of variation in Fawn Count is accounted for by Adult Count, Annual
Rain in inches and Winter Severity in this model.
Note:
Correlation is a value between -1 and 1. This STAYS a decimal.
R-square gets converted from a decimal to a percentage. The Correlation IS
NOT a percent, leave it as a decimal.
Note:
Correlation is a value between -1 and 1. This STAYS a decimal.
R-square gets converted from a decimal to a percentage. The Correlation IS
NOT a percent, leave it as a decimal.
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
5/24
x4 = Sales in Thousand per month
x5= How many Competitors stores are in the Area
Find the estimated regression equation which can be used to estimate Annual
Net Sales when using these 5 variables are predictor variables.
See Attached Excel for Data.
Starbuck Sales data.xlsx
Hide ques±on 4 feedback
Annual Net Sales = -49.0449 + 0.9911(Rent) + 0.9823(Inventory) +
0.9782(Advertising) + 27.6181(Sales) - 2.9766(Competitor)
Annual Net Sales = -49.0449 + 15.1571(Rent) + 0.1744(Inventory) +
12.1779(Advertising) + 14.2972(Sales) - 2.9766(Competitor)
Annual Net Sales = 44.4256 + 5.5406(Rent) + 0.0979(Inventory) +
3.7165(Advertising) + 2.9543(Sales) - 2.5614(Competitor)
Annual Net Sales = -1.1039+ 2.736(Rent) + 1.9204(Inventory) +
3.2767(Advertising) + 4.8384(Sales) - 1.1620(Competitor)
You can run a Multiple Linear Regression in Excel using the Data Analysis
ToolPak.
Data -> Data Analysis -> Scroll to Regression
Highlight Annual Net Sales for the Y Input:
Highlight all 5 columns from Rent to Competitor for the X Input:
Make sure you click on Labels and Click OK
If done correctly then you look under the Coefficients for the values to write
out the Regression Equation
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
6/24
Question 5
1 / 1 point
You are thinking about opening up a Starbucks in your area but what to know
if it is a good investment. How much money do Starbucks actually make in a
year? You collect data to, to help estimate Annual Net Sales, in thousands, of
dollars to know how much money you will be making.
You collect data on 27 stores to help make your decision.
x1 = Rent in Thousand per month
x2 = Amount spent on Inventory in Thousand per month
x3 = Amount spent on Advertising in Thousand per month
x4 = Sales in Thousand per month
x5= How many Competitors stores are in the Area
Approximately what percentage of the variation in Annual Net Sales is
accounted for by these 5 variables in this model?
See Attached Excel for Data.
Coefficients
Intercept
-49.04488287
Rent/$1000
15.15714777
Inventory/$1000
0.1743754
Advertising/$1000
12.17790597
Sales per month
/$1000
14.29717285
# Competior
Stores in Area
-2.976567478
Annual Net Sales = -49.0449 + 15.1571(Rent) + 0.1744(Inventory) +
12.1779(Advertising) + 14.2972(Sales) - 2.9766(Competitor)
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
7/24
Starbuck Sales data.xlsx
Hide ques±on 5 feedback
98.24% of variation in the Annual Net Sales is accounted for by Rent,
Inventory, Advertising, Sales per Month and # of Competitor store in
this model.
99.11% of variation in the Annual Net Sales is accounted for by Rent,
Inventory, Advertising, Sales per Month and # of Competitor store in
this model.
27.62% of variation in the Annual Net Sales is accounted for by Rent,
Inventory, Advertising, Sales per Month and # of Competitor store in
this model.
99.25% of variation in the Annual Net Sales is accounted for by Rent,
Inventory, Advertising, Sales per Month and # of Competitor store in
this model.
The R-squared value is the amount of explained variance in the data points in
the model. You convert this decimal to a percent.
You can run a Multiple Linear Regression in Excel using the Data Analysis
ToolPak.
Data -> Data Analysis -> Scroll to Regression
Highlight Annual Net Sales for the Y Input:
Highlight all 5 columns from Rent to Competitor for the X Input:
Make sure you click on Labels and Click OK
If done correctly then
R Square
0.982353754
Adjusted R Square
0.978152267
R-squared:
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
8/24
Question 6
1 / 1 point
You move out into the country and you notice every Spring there are more
and more Deer Fawns that appear. You decide to try and predict how many
Fawns there will be for the up coming Spring.
You collect data to, to help estimate Fawn Count for the upcoming Spring
season. You collect data on over the past 10 years.
x1 = Adult Deer Count
x2 = Annual Rain in Inches
x3 = Winter Severity
Where Winter Severity Index:
1 = Warm
2 = Mild
3 = Cold
98.24% of variation in the Annual Net Sales is accounted for by Rent,
Inventory, Advertising, Sales per Month and # of Competitor store in this
model.
If you want to give a more conservative estimate, you can use the Adjusted R-
squared. This can make sure you don't over promise on what the model can
do. But the interpretations are the same.
Adjusted R-squared:
97.82% of variation in the Annual Net Sales is accounted for by Rent,
Inventory, Advertising, Sales per Month and # of Competitor store in this
model.
Note:
Correlation is a value between -1 and 1. This STAYS a decimal.
R-square gets converted from a decimal to a percentage. The Correlation IS
NOT a percent, leave it as a decimal.
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB=…
9/24
4 = Freeze
5 = Severe
Estimate Fawn Count when Adult Deer Count = 10, Annual Rain = 13.5 and
Winter Severity = 4
See Attached Excel for Data.
Deer data.xlsx
Hide ques±on 6 feedback
3.06
2.95
5
3.85
You can run a Multiple Linear Regression Analysis using the Data Analysis
ToolPak in Excel.
Data -> Data Analysis -> Scroll to Regression
Highlight Fawn Count for the Y Input:
Highlight columns Adult Count to Winter Severity for the X Input:
Make sure you click on Labels and Click OK
If done correctly then you look under the Coefficients for the values to write
out the Regression Equation
Coefficients
Intercept
-5.559106707
Adult Count
0.303715877
Annual Rain in
Inches
0.397827379
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
10/24
Question 7
0 / 1 point
Which residual plot has the best linear regression model?
Winter
Severity
0.249286765
Fawn Count = -5.5591 + 0.3071(Adult Count) + 0.3978(Annual Rain) +
0.2493(Winter Severity)
Plug in, Adult Deer Count = 10, Annual Rain = 13.5 and Winter Severity = 4
Fawn Count = -5.5591 + 0.3071(10) + 0.3978(13.5) + 0.2493(4)
a
b
c
d
e
f
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
11/24
Hide ques±on 7 feedback
Question 8
1 / 1 point
In the context of regression analysis, what is the definition of an influential
point?
Question 9
1 / 1 point
You determine there is a strong linear relationship between two variables
using a test for linear regression. Can you immediately claim that one variable
is causing the second variable to act in a certain way?
Hide ques±on 9 feedback
A good residual plot has an even distribution of data points above and below
the line x = 0.
Observed data points that are far from the least squares line
Observed data points that are far from the other observed data points
in the horizontal direction
Observed data points that are close to the least squares line
Observed data points that are close to the other observed data points
in the horizontal direction
No, you should examine the situation to identify lurking variables that
may be influencing both variables.
No, the correlation would need to be a perfect linear relationship to be
sure.
No, you must first decide if the relationship is positive or negative.
Yes, a strong linear relationship implies causation between the two
variables.
No, correlation does not equal causation.
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
12/24
Question 10
1 / 1 point
A negative linear relationship implies that larger values of one variable will
result in smaller values in the second variable.
Hide ques±on 10 feedback
Question 11
1 / 1 point
When r is close to ____, there is either a weak linear relationship between x
and y or no linear relationship between x and y.
Hide ques±on 11 feedback
Question 12
1 / 1 point
True
False
For a negative relationship, as one value increases, the other value decreases.
0
-1
±∞
1
Correlation is a value from -1 to 1. The closer r is to 0, the worst the
correlation is. When r = 0, this means there is no correlation (zero) between
the two values.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
13/24
If there are 15 data points in a set of data, what is the number of degree of
freedom for the Residual?
Hide ques±on 12 feedback
Question 13
1 / 1 point
It has long been thought that the length of one's femur is positively correlated to the length of one's
tibia. The following are data for a classroom of students who measured each (approximately) in
inches.
Femur Length
Tibia Length
18.7
14.2
20.5
15.9
16.2
13.1
15.0
12.4
19.0
16.2
21.3
15.8
21.0
16.2
15
13
14
12
The Residuals have n -2 degrees of freedom. 15 - 2 = 13
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
14/24
14.3
12.1
15.8
13.0
18.8
14.3
18.7
13.8
Regression Statistics
Multiple R
0.9305
R Square
0.8659
Adjusted R Square
0.8510
Standard Error
0.5963
Observations
11
ANOVA
df
SS
MS
F
Significance
F
Regression
1
20.6611
20.6611
58.0968 3.25116E-05
Residual
9
3.2007
0.3556
Total
10
23.8618
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
15/24
CoefficientsStandard Error t Stat
P-value
Lower 95%
Upper 95%
Intercept
3.5850
1.4137
2.5359
0.0319
0.3871
6.7830
Femur Length
0.5899
0.0774
7.6221
0.0000
0.4148
0.7650
A strong linear correlation was found between the two variables. Find the standard error of estimate.
Round answer to 4 decimal places. Make sure you put the 0 in front of the decimal.
Answer:___
Answer: 0.5963
Hide ques±on 13 feedback
Question 14
0 / 1 point
Body frame size is determined by a person's wrist circumference in relation to height. A researcher
measures the wrist circumference and height of a random sample of individuals.
This is given to you in the output
Standard Error0.5963
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
16/24
Model Summary
b
Model
R
R
Square
Adjusted
R
Square
Std.
Error of
the
Estimate
1
.734
a
.539
.525
4.01409
a. Predictors: (Constant), Wrist
Circumference
b. Dependent Variable: Height
ANOVA
a
Model
Sum of
Squares
df
Mean
Square
F
Sig.
1
Regression
621.793
1
621.793
38.590
.000
b
Residual
531.726
33
16.113
Total
1153.519
34
a. Dependent Variable: Height
b. Predictors: (Constant), Wrist Circumference
Model
Unstandardized
Coefficients
Standardized
Coefficients
t
Sig.
B
Std.
Error
Beta
1
(Constant)
38.177
5.089
7.502
.000
Wrist
Circumference
4.436
.714
.734
6.212
.000
What is the value of the test statistic to see if the correlation is statistically significant?
0.539
7.502
4.436
5.089
6.212
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
17/24
Hide ques±on 14 feedback
Question 15
1 / 1 point
Body frame size is determined by a person's wrist circumference in relation to height. A researcher
measures the wrist circumference and height of a random sample of individuals.
Model Summary
b
Model
R
R
Square
Adjusted
R
Square
Std.
Error of
the
Estimate
1
.734
a
.539
.525
4.01409
a. Predictors: (Constant), Wrist
Circumference
b. Dependent Variable: Height
ANOVA
a
Model
Sum of
Squares
df
Mean
Square
F
Sig.
0.734
You need to test the slope. The T-stat that corresponds with the slope (or
Wrist Circumference) is 6.212
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
18/24
1
Regression
621.793
1
621.793
38.590
.000
b
Residual
531.726
33
16.113
Total
1153.519
34
a. Dependent Variable: Height
b. Predictors: (Constant), Wrist Circumference
Model
Unstandardized
Coefficients
Standardized
Coefficients
t
Sig.
B
Std.
Error
Beta
1
(Constant)
38.177
5.089
7.502
.000
Wrist
Circumference
4.436
.714
.734
6.212
.000
What is the correct conclusion for testing that there is a significant correlation?
Hide ques±on 15 feedback
Question 16
1 / 1 point
The correlation coefficient, r, is a number between:
There is a significant correlation.
There is not a significant correlation.
The p-value for the slope is 0.000, this is less than .05. Yes, it is significant.
This is also the same p-value for the overall ANOVA Sig. value.
0 and ∞
-
10 and 10
-∞ and ∞
0 and 10
0 and 1
- 1 and 1
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
19/24
Question 17
1 / 1 point
Bone mineral density and cola consumption has been recorded for a sample of patients. Let x
represent the number of colas consumed per week and y the bone mineral density in grams per cubic
centimeter. Assume the data is normally distributed. Calculate the correlation coefficient using
technology (you can copy and paste the data into Excel). Round answer to 4 decimal places.
Make sure you put the 0 in front of the decimal.
x
y
1
0.883
2
0.8734
3
0.8898
4
0.8852
5
0.8816
6
0.863
7
0.8634
8
0.8648
9
0.8552
10
0.8546
11
0.862
Answer:___
Answer: -0.8241
Hide ques±on 17 feedback
Question 18
1 / 1 point
Use =CORREL function in Excel.
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
20/24
A teacher believes that the third homework assignment is a key predictor in how well students will
do on the midterm. Let x represent the third homework score and y the midterm exam score. A
random sample of last terms students were selected and their grades are shown below. Assume
scores are normally distributed. Calculate the correlation coefficient using technology (you can copy
and paste the data into Excel). Round answer to 4 decimal places.
Make sure you put the 0 in front of the decimal.
HW3
Midterm
13.1
59.811
21.9
87.539
8.8
53.728
24.3
95.283
5.4
39.174
13.2
66.092
20.9
89.729
18.5
78.985
20
86.2
15.4
73.274
25
93.25
9.7
52.257
6.4
43.984
20.2
79.762
21.8
84.258
23.1
92.911
22
87.82
11.4
54.034
14.9
71.869
18.4
76.704
15.1
70.431
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
21/24
15
65.15
16.8
77.208
Answer:___
___
Answer: 0.9846
Hide ques±on 18 feedback
Question 19
1 / 1 point
Body frame size is determined by a person's wrist circumference in relation to height. A researcher
measures the wrist circumference and height of a random sample of individuals. The data is
displayed below.
Regression Statistics
Multiple R
0.7938
R Square
0.6301
Use =CORREL function n in Excel.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
22/24
Adjusted R Square 0.6182
Standard Error
3.8648
Observations
33
Coefficients Standard Error t Stat
P-value
Intercept 31.6304
5.2538
6.0205 1.16E-06
x
5.4496
0.7499
7.2673 3.55E-08
Which is the correct regression equation?
Hide ques±on 19 feedback
ŷ=
31.6304 + 5.2538x
ŷ=
31.6304 + 5.4496x
ŷ=
5.4496+31.6304x
ŷ=
5.4496+0.7499x
You will use the Coefficients values to write the regression equation. This is
given to you in the output. No calculations are needed.
Coefficients
Intercept 31.6304
x
5.4496
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
23/24
Question 20
0 / 1 point
Bone mineral density and cola consumption has been recorded for a sample of patients. Let x
represent the number of colas consumed per week and y the bone mineral density in grams per cubic
centimeter. Assume the data is normally distributed. A regression equation for the following data is
ŷ=
0.8893-0.0031x
.
Which is the best interpretation of the slope coefficient?
x
y
1
0.883
2
0.8734
3
0.8898
4
0.8852
5
0.8816
6
0.863
7
0.8634
8
0.8648
9
0.8552
10
0.8546
11
0.862
For every additional average weekly soda consumption, a person's bone density decreases
by 0.8893 grams per cubic centimeter.
For every additional average weekly soda consumption, a person's bone density increases
by 0.0031 grams per cubic centimeter.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
1/17/24, 3:29 PM
William Bridgeforth - MATH302 D011 Fall 2023 - APEI
https://myclassroom.apus.edu/d2l/lms/quizzing/user/quiz_submissions_attempt.d2l?isprv=&qi=270932&ai=3068927&isInPopup=0&cfql=0&fromQB…
24/24
Hide ques±on 20 feedback
Done
For an increase of 0.8893 in the average weekly soda consumption, a person's bone density
decreases by 0.0031 grams per cubic centimeter.
For every additional average weekly soda consumption, a person's bone density decreases
by 0.0031 grams per cubic centimeter.
You want to interpret the slope. ŷ=
0.8893-0.0031x
The slope value is -0.0031
X is the number of sodas you drink and Y is your bone density.
As the number of sodas you drink per week increases by 1, then your bone
density will decrease by 0.0031.
Your bone density will decrease because it is negative. The "decrease"
accounts for the negative. Saying "increase by a -0.0031" isn't correct. If a
slope is negative then it decreases.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help