Quiz 1_Explanation

docx

School

Utah Valley University *

*We aren’t endorsed by this school

Course

1010

Subject

Industrial Engineering

Date

Jan 9, 2024

Type

docx

Pages

2

Uploaded by PrivateBee3551

Report
Quiz 1 Explanation 1) 130 km hr × 1 mi 1.60934 km = 80.78 mi hr Note that if you round up or down your result or your conversion factor, your number may be slightly different. If that happens in the future, chose the most similar answer 2) 130 km hr × 1000 m 1 km × 1 hr 3600 sec = 36.11 m sec 3) 80 mi hr × 1.60934 km 1 mi = 128.75 km hr 4) 7.58 g cm 3 × 1 kg 1000 g × 1000000 cm 3 1 m 3 = 7,580 kg m 3 Note that, while 1 m is equal to 100 cm, 1 m 3 is equal to 1,000,000 cm 3 . Remember to always square or cube the conversion factor! 5) 7,580 kg m 3 × 2.20462 lb 1 kg × 1 m 3 35.3147 lb 3 = 473.20 lb ft 3 6) Multiply both sides by V: ρ ×V = m V ×V On the right side, V cancels out: m = ρ×V 7) Multiply again both sides by V: ρ ×V = m V ×V m = ρ×V Now, divide both sides by ρ: m ρ = V 8) Given the equation v=d/t, solve for time:
t = d v t = 880 mi 60 mi hr = 14.67 hr Note that, in terms of units, mi cancels out. You are left with 1/1/hr, which is equivalent to hr. 9) above = ¿ H total × ( 1 ρ object ρ fluid ) H ¿ Rearrange the stuff in parentheses: above = ¿ H total × ( ρ fluid ρ object ρ fluid ) H ¿ above = ¿ H total ρ fluid H total ρ object ρ fluid H ¿ Multiply both sides by ρ fluid and simplify: H above ρ fluid = H total ρ fluid H total ρ object Solve for ρ object : ρ object = ρ fluid ( H total H above ) H total 10) The atomic number is the number of ptotons, the mass number is protons plus neutrons. So, the number of neutrons must be 14-7=7.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help