M5 Exam

M5: Exam - Requires Respondus LockDown Browser + Webcam Due No due date Points 50 Questions 4 Time Limit 90 Minutes Requires Respondus LockDown Browser Instructions You may only have the following items when taking an exam: computer, 1-2 pieces of blank scratch paper, a pen/pencil, and a calculator. You may ONLY use the equation sheets that are provided WITHIN the exam. The use of printed versions will be considered a violation of the Academic Integrity Policy. Attempt History Attempt Time Score LATEST Attempt 1 27 minutes 46 out of 50 Score for this quiz: 46 out of 50 Submitted Aug 23 at 5:38pm This attempt took 27 minutes. Question 1 513 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet &

Suppose that you take a sample of size 18 from a population that is not normally distributed. Can the sampling distribution of X be approximated by a normal probability distribution? Your Answer: No. the population is not normally distributed, therefore we need a sample size of at least 30 to approximate by normal distribution. No. The population is not normally distributed, therefore, we need a sample size of at least 30 to approximate by a normal probability distribution. Question 2 15/ 15 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet & (https://previous.nursingabc.com/upload/images/Help_file picture/Statistics Standard Normal Table = Suppose that you are attempting to estimate the annual income of 2000 families. In order to use the infinite standard deviation formula, what sample size, n, should you use? < 4 Your Answer: % < .05, 2 ‘ 2000 °O5‘ In < .05 (2000)

P (X < 150)] ox 7.6 \P(Z < —1.316) = .09510 We calculate the standard deviation of the sample distribution: Calculate the z-score: O P | o Oy 2 7.6 = A So, we want to find P(Z < -1.32) on the standard normal probability distribution table. Recall that P(Z < -1.32) = .09342. Therefore, there is a 0.09342 probability that a simple random sample of 25 nurses will have a mean time of 150 seconds or less. Question 4 11/ 15 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet = (https://previous.nursingabc.com/upload/images/Help_file picture/Statistics Standard Normal Table = (https:/Iprevious.nursingabc.com/upload/images/Help_file picture/standardn

Suppose that in a very large city 9.8 % of the people have more than two jobs. Suppose that you take a random sample of 70 people in that city, what is the probability that 9 % or more of the 70 have more than two jobs? Your Answer: |01_o = \/ =y (1n_p ) — \/ '098(;'098) = .0012628| Z-score q __ [p—p _ 10-.094 Z = \/ op .0012628 4'75| \P(Z < 4.75) =1 = 0.0355 _ [p(1—p) _ (0.098(1—0.098) B N 70 Now we find the z-score: 5—p 0.09—0.098 R N —26 5 0.0355 We want P(Z>-0.23). From the standard normal table, we find: P(Z>-.23)=1- P(Z<-.23)=1-.40905=.59095. So there is a .60257 probability that the percentage of the sample that have more than two jobs is more than 9 %.