M9 Exam

M9: Exam - Requires Respondus LockDown Browser + Webcam Due No due date Points 35 Questions 4 Time Limit 90 Minutes Requires Respondus LockDown Browser Instructions You may only have the following items when taking an exam: computer, 1-2 pieces of blank scratch paper, a pen/pencil, and a calculator. You may ONLY use the equation sheets that are provided WITHIN the exam. The use of printed versions will be considered a violation of the Academic Integrity Policy. Attempt History Attempt Time Score LATEST Attempt 1 62 minutes 31 out of 35 Score for this quiz: 31 out of 35 Submitted Nov 27 at 5:53pm This attempt took 62 minutes. Question 1 45 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet & table.pdf)

Critical values chart = (https://iprevious.nursingabc.com/upload/images/Help_file picture/Critical v: Suppose you have 14 data points and you calculate the sample correlation coefficient and find that r = - .58. Can you be 95% confident that a linear relation exists between the variables? If so, is the relation positive or negative? Justify you answer. Your Answer: n= 14 r=-.58 critical value = .53241 Absolute value of r =.58 .58 > .53241 so ther is a linear relationship 4 G ¢ Note that for n=14 and 95% we get a value from the chart of .53241. The absolute of r is |r|=.58, which is above .53241. So a negative linear relation exists. Question 2 4/5 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet & (https://Iprevious.nursingabc.com/upload/images/Help_file_ picture/Statistics standard normal table = (https://previous.nursingabc.com/upload/images/Help_file picture/standardn t-table = (https://Iprevious.nursingabc.com/upload/images/Help_file_picture/t- table.pdf)

Critical values chart = (https://previous.nursingabc.com/upload/images/Help_file picture/Critical vz Compute the sample correlation coefficient for the following data: X y 1 15 2 12 5 11 7 9 9 7 Can you be 95% confident that a linear relation exists between the variables? If so, is the relation positive or negative? Justify you answer. Your Answer: (14-2+5+7+9) _‘ 18 ‘(15+12+11+9+7) 3 : :‘ 10.8 5—1 ( (1-4.8)%+(2—4.8)2+(5—4.8)2+(7—4.8)>+(9—4.8)? ) :F 48 \m =‘6.69 (15—10.8)%+(12—10.8)%+(11—10.8)*+(9—10.8)*+(7—10.8)* 5—1 4/36.8 =|6.07 5—1 ( (1—4.8)(15—10.8)+(2—4.8)(12—10.8)+(5—4.8) (11—10.8)+(7—4.8) (9—10.8)+(9—4.8)( n=5, Sx=6.69, Sy=6.07, r=-39.2 Ir|=39.2 > .87834 =positive linear relation

r=-.9654 Sx = 3.3 Sy = 3.03. Note that for n=5 and 95% we get a value from the chart of .87834. The absolute of r is |[r|=.9654, which is above .87834. So a negative linear relation exists. Question 4 14 / 15 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet & standard normal table > (https://previous.nursingabc.com/upload/images/Help_file picture/standardn t-table & (https://previous.nursingabc.com/upload/images/Help_file_picture/t- table.pdf) Critical values chart = (https://previous.nursingabc.com/upload/images/Help_file_ picture/Critical vz Find the best fit line for the following data: X y 3 17 5 14 6 11 8 10 10 8 4 4 Your Answer: