2017 CSSA HSC MATHEMATICS 2 UNIT MARKING CRITERIA
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University of New South Wales *
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Course
MATH
Subject
Health Science
Date
Oct 30, 2023
Type
Pages
28
Uploaded by CorporalGoldfinch1422
x(J,
CSSA
CATHOLIC
SECONDARY
SCHOOLS
ASSOCIATION
2017
TRIAL
HIGHER
SCHOOL
CERTIFICATE
EXAMINATION
MATHEMATICS
~
MARKING
GUIDELINES
These
marking
guidelines
show
the
criteria
to
be
applied
to
responses
along
with
the
marks
to
be
awarded
in
line
with
the
quality
of
responses.
These
guidelines
are
suggested
and
not
prescriptive.
This
is
not
intended
to
be
an
exhaustive
list
but
rather
an
indication
of
the
considerations
that
students
could
include
in
their
responses.
Section
I
10
Marks
Questions
1-10
(1
mark
each)
.
Targeted
Question
Answer
Outcomes
Assessed
Performance
Bands
1
C
P4,
HS
3
2
D
P4
3
3
C
H8
3
4
A
PS5
3-4
5
D
P3,
P4,
H5
4
6
B
P4,
H5
4
7
B
P4,
H5
4
8
C
P3,H5
4-5
9
A
H6
5
10
D
H38
6
-1-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
6200-2
Section
II
90
Marks
Question
11
(15
marks)
(a)
(1
mark)
Qutcomes
Assessed:
P3,
H1
Targeted
Performance
Bands:
2
Criteria
Mark
o
Correctly
determines
the
value
to
2
significant
figures
1
Sample
answer:
37
(b)
(1
mark)
Qutcomes
Assessed:
P4
Targeted
Performance
Bands:
3
Criteria
Mark
Correctly
factorises
the
expression
1
Sample
answer:
(5x+3)(x-1)
(c)
(3
marks)
Outcomes
Assessed:
P4
Targeted
Performance
Bands:
4
Criteria
Marks
Correctly
solves
the
inequality
and
correct
sketching
of
inequality
on
number
line
3
Correctly
solves
the
inequality
2
Some
progress
towards
solution
1
Sample
answer:
—8=<3x-4=<8
-4=3x<12
L
-
4
-——=sx=4
3
3
2-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff,
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(d)
(2
marks)
Outcomes
Assessed:
H5
Targeted
Performance
Bands:
4
Criteria
Marks
e
Correct
substitution
into
first
derivative
and
simplification
2
o
Correct
differentiation
of
trigonometric
function
1
Sample
answer:
f(x)=3sindx
f(x)=12cosdx
b1
4
|
=
|=12cos—
18
=12
%~
1
=
-6
(e)
(2
marks)
Qutcomes
Assessed:
H3,
H8
Targeted
Performance
Bands:
4
Criteria
Marks
e
Correctly
finds
the
primitive
2
o
Progress
towards
finding
the
primitive
1
Sample
answer:
1
J'
4x°
4]
x*+7
%loge
x*+D+C
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers,
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
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)
(2
marks)
Outcomes
Assessed:
P3
Targeted
Performance
Bands:
3-4
Criteria
Marks
o
Correct
answer
2
s
Progress
towards
answer
1
Sample
answer:
lim
3(x+1)
x—>=1
(x+1)}{x=1)
_
lim
3
x=>-1
(x-1)
=3
2
(g)
(2
marks)
Outcomes
Assessed:
P3
Targeted
Performance
Bands:
3-4
Criteria
Marks
o
Findsbd
2
o
Progress
towards
a
solution
1
Sample
answer:
—2+4=l
DISCLAIMER
HSC
papers.
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer. The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Triat
(h)
(2
marks)
Outcomes
Assessed:
P3
Targeted
Performance
Bands:
3-4
Criteria
Marks
e
Correct
answer
2
e
Progress
towards
answer
using
index
laws
1
Sample
answer:
5x+Z
=
_1_
=
5—1
5
x+2=-1
Sx==3
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranfy
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Question
12
(15
marks)
(a)(i)
(1
marks)
Outcomes
Assessed:
P3
Targeted
Performance
Bands:
3
Criteria
Mark
o
Obtains
correct
expression
for
a
1
Sample
answer:
(a)
(ii)
(2
marks)
Qutcomes
Assessed:
P6
Targeted
Performance
Bands:
3-4
Criteria
Marks
o
Correctly
obtains
the
x-coordinate
of
P
2
o
Substantial
progress
towards
a
solution
1
Sample
answer:
-6-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
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(b)
(3
marks)
Outcomes
Assessed:
H2
Targeted
Performance
Bands:
3-4
Criteria
Marks
o
Correct
reasoning
is
used
to
establish
AMPO
=
AOSN
3
o
Significant
progress
is
made
towards
proving
AMPO
=
AOSN
2
o
Correctly
establishes
that
APSM
=
AOSN
1
Sample
answer:
In
A's
PSM
and
OSN
£PMS
=
ZONS(given)
PS
=
08§
(given)
LPSM
=
LOSN
(vertically
opposite
angles)
-
APSM
=
AOSN
(AAS)
In
A's
MPO
and
NOP
PM
=
ON
(corresponding
sides
of
congruent
triangles)
PQ
is
common
OM
=
PN
(since
SM
=
SN
and
P§S
=
0S5)
.
AMPO
=
AOSN
(SSS)
(c)
(3
marks)
Outcomes
Assessed:
P3
Targeted
Performance
Bands:
4
Criteria
Marks
e
Obtains
the
correct
values
of
3
o
Significant
progress
is
made
towards
correct
solution
2
e
Correctly
establishes
that
cos8
=
—%
1
Sample
answer:
25in6.cose
+1=0
sin
-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
@
(@)
(1
mark)
Outcomes
Assessed:
P4
Targeted
Performance
Bands:
3
Criteria
Mark
e
Correctly
shows
that
48
is
parallel
to
DC
Sample
answer:
My
=——
AB
2___2
(d)
(i)
(1
mark)
Outcomes
Assessed:
P4
Targeted
Performance
Bands:
3
Criteria
Mark
e
Correctly
shows
the
equation
of
ABis
x
-2y
+10=0
Sample
answer:
1
=
—(x
=2
y
5
(x--2)
2y
-8=x+2
SLx-2y+10=0
(d)
(iii)
(2
marks)
Outcomes
Assessed:
P4
Targeted
Performance
Bands:
3
Criteria
Marks
e
Correctly
determines
the
perpendicular
distance
from
45
to
point
C
e
Significant
progress
is
made
towards
correct
answer
Sample
answer:
w20
+10
DISCLAIMER
The information contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
refation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(d)
(iv)
(2
marks)
Qutcomes
Assessed:
P3,
P4
Targeted
Performance
Bands:
3-4
Criteria
Marks
e
Correct
area
of
trapezium
is
found
2
e
The
correct
lengths
of
4B
and
DC
are
determined
1
Sample
answer:
dyy
=2
-
-2)"
+(6-
4)?
=20
=245
dpe
=445
(DC
=2AB,
given)
-9
Area
=
2£(2£+4V§)
=27
units*
9.
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
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- 24/7 expert homework help
Question
13
(15
marks)
(@
@)
(1
mark)
Qutcomes
Assessed:
P7,
H3
Targeted
Performance
Bands:
3-4
Criteria
Mark
»
Find
the
correct
derivative
1
Sample
answer:
dx
(2)(i1)
(2
marks)
Outcomes
Assessed:
P7,
H5
Targeted
Performance
Bands:
4
Criteria
Marks
®
Obtains
the
correct
expression
for
the
derivative
2
e
Progress
towards
the
correct
derjvative
1
Sample
answer:
2
(nx)(2x)
-
(2
+5)%
=
X
ax
(Inx)
-10-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA.
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(b)
(2
marks)
Qutcomes
Assessed:
HS
Targeted
Performance
Bands:
4
Criteria
Marks
s
Correct
solution
is
obtained
2
o
Progress
is
made
towards
correct
solution
1
Sample
answer:
[
1
=|
4x-7)?
dx
L
-2
DS
e
—x4
2
=_f£l
+C
2
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
refation
to
any
specific
trial
exam.
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(c)(i)
(3
marks)
Qutcomes
Assessed:
H5,
H6
Targeted
Performance
Bands:
3
Criteria
Marks
Correctly
determines
both
stationary
points
and
their
nature
3
Some
progress
—
e.g.
determines
the
x
values
where
the
curve
is
stationary
and
their
5
nature
1
Correctly
differentiates
Sample
answer:
y=2x>+3x*
-
12x+7
fl=6x2+6x—12
dx
For
stationary
points,
%
=0
6x*+6x~12=0
(x+2)(x=1)=0
sox=-2and
x=1
f(-2)=27
and
f(1)=0,
so
stationary
points
occur
at
(-2
,27)
and
(1,
0)
2
at
x=-2,
g—x%i
=-18
so
N
i.e.
a
MAXIMUM
turning
point
at
(-2
,
27)
2
atx=1,
‘;cy
=18
so
U
i.e.
a
MINIMUM
turning
point
at
(1
,
0)
T
=
-12-
DISCLAIMER
The
information contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff,
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
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(c)(ii)
(2
marks)
Outcomes
Assessed:
H5,
H6
Targeted
Performance
Bands:
3-4
Criteria
Marks
e
Correctly
determines
point
of
inflexion
with
concavity
change
2
e
Correctly
determines
the
point
of
inflexion
1
Sample
answer:
Possible
Point
of
inflexion
at
Z;}Z)
=0
12x+6=0
x=—
0.5,
at
this
value
of
x
the
y
value
is
13.5
x
-1
-0.5
0
2
%
-6
0
6
A
change
of
concavity
has
occurred.
.'.
a
point
of
inflexion
occurs
at
(0.5
,
13.5)
(c)(iil)
(3
marks)
Outcomes
Assessed:
H5,
H6
Targeted
Performance
Bands:
4
Criteria
Marks
o
Correctly
draws
graph,
including
all
stationary
points,
points
of
inflexion
&
end
points
3
e
Significant
progress
is
made
towards
correct
graph
2
¢
Some
attempt,
but
does
not
include
all
points
1
Sample
answer:
227y
7
(-3,16)
(-0.5,13.5)
(3,52)
-3
1,0)
13-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(c)
(iv)
(1
mark)
Outcomes
Assessed:
H7
Targeted
Performance
Bands:
3
Criteria
Mark
o
Correct
answer
obtained
1
Sample
answer:
Maximum
value
of
the
function
in
the
domain
-3
=
x
=
3
is
52
(¢)
(v)
(1
mark)
Outcomes
Assessed:
H7
Targeted
Performance
Bands:
5
Criteria
Mark
s
Correct
domain
and
inequality
symbols
given
1
Sample
answer:
—l
<x<l
2
-14-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possibie
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer. The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for the
Trial
HSC
papers.
Question
14
(15
marks)
(@)(d)
(1
mark)
Outcomes
Assessed:
H5
Targeted
Performance
Bands:
3
Criteria
Mark
o
Correctly
finds
the
value
of
8
in
radians
1
Sample
answer:
I=rf
100
=408
=
-
radians
2
(2)(ii)
(3
marks)
Qutcomes
Assessed:
H2,
H5
Targeted
Performance
Bands:
3-5
Criteria
Marks
e
Evaluates
the
height
correctly
3
o
Significant
progress
towards
correct
solution
2
e
Establishes
a
right-angled
triangle
with
the
correct
angle
1
Sample
answer:
Let
/
be
the
height
of
M
above
the
track
after
the
wheel
has
rolled
1
metre.
The
angle
required
for
triangle
is
3
.,
5-m
x
sin
=
—
2
40
x=40sin§i-
=32
So
the
height
of
M
above
the
track
is
32
+
40
=
72cm.
-15-
DISCLAIMER
“The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
con;
Mo
stitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teacher:
or
warranty
is
made
or
implied
with
respect
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
u
HSC
papers.
s
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
sefulness
of
any
Marking
Guidelines
provided
for
the
Trial
Your preview ends here
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(b)(@)
(1
mark)
Outcomes
Assessed:
P3,
P4
Targeted
Performance
Bands:
3
Criteria
Mark
o
Gives
the
correct
coordinate
for
T
1
Sample
answer:
y=2-
xz,
cuts
the
x-axis
when
y=0.
0=2-x"
x=442
,x>0
So
T
is
the
coordinate
(\/-2_,0).
(b)(ii)
(3
marks)
Outcomes
Assessed:
H5,
HS,
H9
Targeted
Performance
Bands:
4-5
Criteria
Marks
o
Evaluates
the
volume
correctly
3
e
Correctly
integrates
the
expression
2
¢
Some
progress
towards
the
solution
1
Sample
answer:
Let
y
=x*
andy,=2-x
L
V2
y
=2
dren
s
1
Jz
=
7z"|.x6
dx+flj(2—x2)zdx
0
1
i
=
flj.x6
abc+7z'_[(4—4x2
+x4)dx
1]
1
i
T
4%
x°
0
1
—
%Jr
445_§*3/_5+i@
_[4_i+1j
3242
286
15
105
=0.921
(3decimal
places
)
-16-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer,
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(©)()
(1
mark)
Qutcomes
Assessed:
H4,
HS
Targeted
Performance
Bands:
3-4
Criteria
Mark
o
Gives
the
correct
expression
for
the
annuity
after
one
year
1
Sample
answer:
Let
the
amount
in
her
account
at
the
start
of
Helen’s
annuity
be
$500
000;
let
the
rate
»
=
0.06
and
let
Ay
be
the
amount
remaining
in
the
annuity
after
n
years.
A
=500
000(1
‘06)
-M
(c)
(iD)(3
marks)
Outcomes
Assessed:
H4,
H5,
H9
Targeted
Performance
Bands:
4-5
Criteria
Marks
e
Correctly
determines
the
value
of
$M
3
e
Progress
towards
finding
$M
2
o
Forms
an
equation
involving
$M
1
Sample
answer:
4,
=
4,(1.06)-
M
=(500
000(1.06)~
M
)(1.06)~
M
=500
000(1.06)°
-
M
(1+1.06)
so
continuing
the
pattern
Agy
=500
000(1.06)"
-
M
(1+1.06
+...+1.06”
)
But
4,
=0and
(1+1.06+...+1.06”)
is
a
GP
where
=30,
a=1
and
7
=
1.06
(1
06%°
-
1)
So,
0=
500
000(1.06)"
-
M
x
1.06-1
_0.06x500
000
(1.06)"
(1.06%
-1)
=$36
32446
(2
decimal
places)
-17-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
wartanty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completencss
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(c)
(iii)(3
marks)
Outcomes
Assessed:
H4,
H5,
H9
Targeted
Performance
Bands:
4-6
Criteria
Marks
e
Correctly
determines
how
many
more
years
Helen
will
be
able
to
withdraw
money
3
*
_
Significant
progress
towards
solving
the
problem
2
»
Finding
the
amount
remaining
after
15
withdrawals
1
Sample
answer:
A5
=500
000(1.06)""
-
36
324.46(1+1.06+...+1.06*)
1.06"
-1
=500
000(1.06)"°
~36
324.46
x—(-————)
=$352
792.06
So,
after
15
years
there
is
approximately
$352
792.06
remaining
in
Helen’s
annuity.
Let
B, be
the
amount
remaining
in
the
annuity
»
years
after
rate
changes
to
4%
p.a.
B
=352
792.06(1
.04)
-M
B,=B
(104)-M
=352792.06(1.04)"
-
M
(1+1.04)
"
B,
=35279206(1.04)"
—
M(1+1.04+..+1.04")
‘When
B,=0.
.
(1.04"-1)
352
792.06x(1.04)"
=36
324
46x
!
0.04
(1.04)"
=1.635293
e
log(1.635293)
log(1.04)
n=12.539years
Therefore,
Helen
will
be
able
to
withdraw
money
from
this
annuity
for
12
more
years.
-18-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff,
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
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Question
15
(15
marks)
(a2)(1)
(2
marks)
Outcomes
Assessed:
H5,
H9
Targeted
Performance
Bands:
4
Criteria
Marks
o
Correctly
finds
the
coordinate
P
2
e
Progress
towards
an
answer
1
Sample
answer:
sin2x
=
cos
2x
tan2x
=1
S
4
Sz
8
2x=£,
4
z
X=—,
8
b4
When
x
=
E’
y=
—1-
So
P
is
the
coordinate
z
1
8°J2)
V2
DISCLAIMER
.
4
,
xis
in
first
quadrant,
so
x
=—.
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specitic
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(a)(ii)
(3
marks)
Outcomes
Assessed:
H5,
H8
Targeted
Performance
Bands:
3-5
Criteria
Marks
e
Evaluates
shaded
area
correctly
3
e
Significant
progress
towards
correct
solution
2
»
Correctly
determines
part
integral
of
sin2x
or
cos2x
correctly
1
Sample
answer
T
3
A=
ZJ
(1—cos2x)dx
0
K]
-20-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not the
inteation
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
(b)()
(1
mark)
Outcomes
Assessed:
H4,
H5
Targeted
Performance
Bands:
3-4
Criteria
Mark
o
Correctly
determines
the
probability
1
Sample
answer:
Class
A
Class
B
8
14
F
2
4_—F
¢
M
14
8
14
_-F
12
M
14
M
5
14
P
(
FF)
=
2
X
8
=
4
14
14
49
(b)(ii)
(2
marks)
Qutcomes
Assessed:
H4,
H5
Targeted
Performance
Bands:
3-4
Criteria
Marks
e
Correctly
determines
the
probability
2
o
Some
progress
towards
the
correct
answer
1
Sample
answer:
P(1
female,
1
male)
=
P(FM)
+
P(MF)
2
6
12
8
=X
X
—
14
14
14
14
3
24
27
==
49
49
49
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outeomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
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(c)()
(1
mark)
Outcomes
Assessed:
H3,
H9
Targeted
Performance
Bands:
3-4
Criteria
Mark
o
Correctly
writes
down
the
value
of
P
1
Sample
answer:
From
the
graph,
P
=
6.
(c)(ii)
(2
marks)
Qutcomes
Assessed:
H3,
H9
Targeted
Performance
Bands:
3-5
Criteria
Marks
o
Correctly
determines
the
value
of
k
2
»
Progress
towards
finding
the
value
of
k
1
Sample
answer:
When
=6,
M=3
and
P
=
6:
3=6e%
1
=%
2
ln(l
=6k
2
k
=—0.1155(4
decimal
places)
(c)(iii)
(2
marks)
Outcomes
Assessed:
H3,
H9
Targeted
Performance
Bands:
3-5
Criteria
Marks
s
Correct
answer
2
o
Progress
towards
the
correct
answer
1
Sample
answer:
~0.1155;
1.2="6e
x'
12
=
g
M1Sse
6
In[QJ
=-0.1155x¢
6
t=13.934...
So
one
fifth
of
the
initial
dose
will
remain
after
approximately
14
hours.
22-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with respect
to
the
application
or
use of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
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(c)(iv)
(2
marks)
Qutcomes
Assessed:
H3,
H5
Targeted
Performance
Bands:
3-5
Criteria
Marks
o
Correct
answer
2
e
Progress
towards
the
correct
answer
1
Sample
answer:
f’,@_
=
kPe®
dt
=-0.1155x
6x
11>
=
~0.245
mg/hr
»
Drug
removed
at
rate
of
0.245
mg/hr.
DISCLAIMER
‘The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for the
Trial
HSC
papers.
Your preview ends here
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Question
16
(15
marks)
(a)
(i)
(1
mark)
Outcomes
Assessed:
H3,
H4
Targeted
Performance
Bands:
2-3
Criteria
Mark
o
Solvefort=0
1
Sample
answer:
Whent=0
x=0+3Inl=0
(a)
(ii)
(3
marks)
Outcomes
Assessed:
H4,
H5
Targeted
Performance
Bands:
3-5
Criteria
Marks
s
Gives
the
correct
answer
3
e
Substantial
progress
towards
an
answer
2
o
Differentiates
and
equates
to
zero
1
Sample
answer:
.
6t
18¢
.
=6t
+3In(3t*
+1
S
X=6+3x
=6+
and
atrest
x=0
*
(e
+1)
341
341
¥
18t
2
2
"O=6+3tz
S
18
+18t+6=0
s34+
3t+1=0
+
and
since
A=
9-12=-3<0
..
no
solution
i.e.
the
particle
never
come
to
rest.
(a)
(iii)
(1
mark)
Outcomes
Assessed:
P2,
H5
Targeted
Performance
Bands:
3-4
Criteria
Mark
o
(ives
the
correct
answer
1
Sample
answer:
The
limiting
velocity
is
6
m/s.
24-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer. The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
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(b)
(3
marks)
Outcomes
Assessed:
P4
Targeted
Performance
Bands:
4-6
Criteria
Marks
e
Gives
the
correct
values
for
x;
3
s
Makes
substantial
progress
towards
the
solution
including
justification
2
e
Gives
the
correct
substitution
into the
correct
formula
1
Sample
answer:
(e-x
)
+(y+4f
=25
Centre:
C
(x1
,—4)
and
the
radius
=
5.
The
point
M
(4,
-
1)
will
lie
outside
the
circle
if
the
distance
CM
>3
A,
—4)
+(-4+1)
>5
(x,—4)
+9>25
(x,-4)P>16
-~
x2-8x+16>16
..x(x—8)>0
x
<0or
x
>8
25
DISCLAIMER
The information contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
Your preview ends here
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(c)
(i)
(2
marks)
Outcomes
Assessed:
H5,
H6
Targeted
Performance
Bands:
4-6
Criteria
Marks
e
Gives
the
correct
answer
2
e
Gives
the
correct
gradient
of
the
tangent
1
Sample
answer:
-
-6
-3
y=—6—=6x'l
fl:—f
andatQ,
x=2g
.m=-—p=—
X
dx
x
4g°
2q
.
.
3
-3
-
the
equation
of
the
tangentat
Qis:
|
y——
|=
F(x
-29)
q
q
2g°y~6q
=-3x+6q
2¢°y=12g-3x
()
(ii)
(2
marks)
Qutcomes
Assessed:
P4
Targeted
Performance
Bands:
3-4
Criteria
Mark
®
Gives
the
correct
answer
2
e
Correctly
evaluates
either
4
or
B
1
Sample
answer:
At
4:
lety=0
so
x=4q
..
A=(4q,0)
At
B:
letx=0
soy=1—2—621=g
S
B=
0,§-
29"
¢
q
26~
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
ot
warranty
is
made
or
implied
with
respect
to
the
application
or
use of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer,
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
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(¢)
(iii)
(3marks)
Outcomes
Assessed:
H5,
H6
Targeted
Performance
Bands:
4-6
Criteria
Marks
®
Gives
the
correct
answer
which
includes
a
correct
test
3
o
Correctly
determines
the
derivative
and
recognises
that
g
is
in
the
third
quadrant
2
o
Differentiates
a
correct
expression
for
L
and
equates
to
zero
1
Sample
answer:
6
dL
72
AB”
=16q2+—2
o
L=16¢*
+36q7"
d—=32q—-—;
q
2
For
minimum
length,
Z—L
=0
~0=32g—
7—3
N2
=72
q
3
.
.
.
3
Lg=t
3
and
since Q
in
the
third
quadrant
..
g
=-—
3
2
o)
2
'.‘111.,:=32+1—14—6
amdwhenq:—\/E
d];=32+&=128
dg’
g
2
dg*
%
d;f
>0
ie.
minimum
length
when
¢
=—
\/E
dg
2
27-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
auswer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for
the
Trial
HSC
papers.
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BLANK
PAGE
28-
DISCLAIMER
The
information
contained
in
this
document
is
intended
for
the
professional
assistance
of
teaching
staff.
It
does
not
constitute
advice
to
students.
Further
it
is
not
the
intention
of
CSSA
to
provide
specific
marking
outcomes
for
all
possible
Trial
HSC
answers.
Rather
the
purpose
is
to
provide
teachers
with
information
so
that
they
can
better
explore,
understand
and
apply
HSC
marking
requirements,
as
established
by
the
NESA.
No
guarantee
or
warranty
is
made
or
implied
with
respect
to
the
application
or
use
of
CSSA
Marking
Guidelines
in
relation
to
any
specific
trial
exam
question
or
answer.
The
CSSA
assumes
no
liability
or
responsibility
for
the
accuracy,
completeness
or
usefulness
of
any
Marking
Guidelines
provided
for the
Trial
HSC
papers.
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