Lab 1 (Planet Earth)
pdf
keyboard_arrow_up
School
Pace University *
*We aren’t endorsed by this school
Course
101
Subject
Geology
Date
Dec 6, 2023
Type
Pages
6
Uploaded by SuperHumanMeerkat606
Building a Planet
PRE-LAB QUESTIONS 1.
Which of the following are chemical layers? (Select all that apply.) a.
Lithosphere (No) b.
Core (Yes)
c.
Inner Core (No)
d.
Mantle (Yes) e.
Crust (Yes) 2.
Given what you know about how the Earth differentiated, what would you expect the interiors of other planets in the solar system to look like? Given what I know about how the Earth differentiated, I would expect the interiors of other planets in the solar system to have an iron-rich core, silicate mantles, and a basaltic crust. Therefore, even though we haven't been to the other planets in our solar system, those are the predictions we can make when talking about the interiors of the other planets. ©2016, eScience Labs
Building a Planet
EXERCISE 1 DATA SHEET Table 1. Unknown Rock 1 Density Measurements Table 2. Unknown Rock 2 Density Measurements Table 3. Density of Substances Trial 1
Trial 2
Trial 3
Mass (g)
22.4
22.5
22.4
Volume (V
0
, mL)
100
100
100
Volume (V
1
, mL)
108
108
108
Rock Volume (mL)
8
8
8
Trial 1
Trial 2
Trial 3
Mass (g)
26.6
26.6
26.6
Volume (V
0
, mL)
100
100
100
Volume (V
1
, mL)
110
110
110
Rock Volume (mL)
10
10
10
Material
Density
(
ρ
)
Continental Crust
2.7 g/cm
3
Oceanic Crust
2.9 g/cm
3
Mantle
3.3 g/cm
3
Water
1.0 g/cm
3
©2016, eScience Labs
Building a Planet
POST-LAB QUESTIONS Use Tables 1, 2, and 3 to answer the following questions: 1.
Find the density for each trial of Unknown Rock 1 using the equation: ρ
= M/V. Show your work, and write the answer for each trial here. Density: (equation: p = M/V) 22.4 / 8 = 2.8 22.5 / 8 = 2.8 2.
Find the average for the three trials of Unknown Rock 1. Show your work, and write the answer here. Average for Mass(g): 22.43g Average mass= 22.4 + 22.5 + 22.4 / 3 = 22.43g 3.
Find the density for each trial of Unknown Rock 2 using the equation: ρ
= M/V. Show your work, and write the answer for each trial here. Density: (equation: p = M/V) 26.6 / 10 = 2.66 4.
Find the average for the three trials of Unknown Rock 2. Show your work, and write the answer here. Average for Mass(g)= 22.6g Average Mass= 26.6 + 22.6 + 22.6 / 3 = 22.6g 5.
Compare the average density you found for Unknown Rock 1 and Unknown Rock 2 to Table 3 on the Data Sheet. What materials do they resemble? Unknown Rock 1 resembles oceanic crust and Unknown Rock 2 resembles continental crust ©2016, eScience Labs
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Building a Planet
6.
Why is it necessary to take the average of multiple trials to find density? Use your work to justify your response. The reason why it is necessary to take the average of multiple trials to find density is that exact density cannot be determined. Even when finding the density for the two unknown rocks they weren’t the exact density that was shown for the substances. For example for unknown rock 1, the density was 2.8 and the density for the oceanic crust was 2.9. Furthermore, for unknown rock 2, the density was 2.66 and the density for continental crust was 2.7. That’s why it is necessary to take the average of multiple trails to find the density. 7.
Apply what you have just learned from the exercise to answer and understand the following questions: Imagine you have a rectangular wooden block with dimensions of 10 cm x 3 cm x 8 cm (L x W x H). a.
What is the volume of your wooden block? Show your work. V = L x W x H 10cm x 3 cm x 8cm = 240 cm^3 b.
What is the density of this wooden block if it has a mass of 168 g? Show your work. Density: p = M/V 168g / 240 cm^3 = .70 g/cm^3 ©2016, eScience Labs
Building a Planet
8.
Your wooden block is shown here in a pool of water. Calculate how much of the block lies below the water line using the equation: ` 9.
where r
is the height below the water and h
is the total height of the block. The density of water is given in Table 3. 0.7 / 1 = r / 8 (1)(r) = (8)(0.7) r = (8)(0.7) r = 5.6 10. A section of continental crust with a height of 25 km (h) floats in the mantle. Some of it lies within the mantle (r), and the rest floats above the mantle. How much of the continental crust lies within the mantle? Use the concepts you learned from the previous question and the densities in Table 3 to solve the problem. Continental Crust Density = 2.7 g/cm^3 2.7 / 1 = r / 25 1(r) = (25)(2.7) r = 25(2.7) r = 67.5 ©2016, eScience Labs
Building a Planet
©2016, eScience Labs
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help