Lab2
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School
Concordia University *
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Course
ELEC 273
Subject
Electrical Engineering
Date
Jan 9, 2024
Type
Pages
5
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LABORATORY REPORT
Basic Circuits & Systems Laboratory
This cover page must always be the top sheet
Course:
ELEC 273
275
Lab Section:
( Circle )
Experiment No.:
Date Performed:
20
–
–
YYYY
–
MM
–
DD
Experiment Title:
Name:
ID No.:
Lab Partner
Name:
Lab Partner
ID:
I certify that this submission is my original work and
meets the Faculty’s Expectations of Originality
Signature:
Date:
20
–
–
YYYY
–
MM
–
DD
FL-X
Prince Raphael Johnson
40153375
Faisal Quraishi
40161298
Abstract
The objective of this experiment was for the students to familiarize themselves with the
basics of the Operational Amplifier (or OpAmp) by constructing circuit OpAmp, as well to test
the principle of Transient Response by building circuits with capacitors and inductors and
measuring different responses.
Introduction
We begin this experiment by getting familiar with the principals of an OpAmp and how it
works in a circuit. An OpAmp circuit has the objective to either obtain the output voltage Vout of
the circuit for a given set of input voltages, or to find the voltage gain Av which is equal to
Vout/Vin. This can be obtained via the Open Circuit (i.e., I+ = I-= 0) & Short-circuits (i.e. V+ =V-
) principles.
Procedure (Methods)
OpAmp circuits:
Start with checking whether the OpAmp IC is operational or not by temporarily short-
circuiting one of the inverting input terminals to ground to get an output voltage of zero (if
not, replace IC unit).
Then go onto building the OpAmp circuits, Non-inverting amplifier circuit and testing out
various principles such as saturation and increased Gain.
Transient Response
We start building 1
st
an RC circuit using the RLC chassis provided, and 2
nd
an RL circuit
with the schematic provided, all the while making the right connection between the
Function Generator and the chassis.
We then go onto try and make an RLC circuit in order to get respectively an Overdamped
RLC response, a Critically Damped Response, and finally an Underdamped Response
Results and Discussion
Operational Amplifiers
Inverter Circuit
-
For the inverter circuit made from Figure 4.1 of the lab manual, we have a display of a
sinusoidal wave for channel 1 and 2.
-
We had an expected output amplitude of V
o
=(-R
2
/R
1
)V
i
= -6.16V but observed an
expected output amplitude of 6.04V.
-
Simply put, the inverter means that the direction of the signal is changed compared to
the input of the circuit.
Saturation
-
We were getting a sinusoidal wave when we increased the input amplitude and looked
for saturation of the op-amp output voltage and noticed the channel 1 input starting to
break slightly.
-
Saturation for an Op-Amp would mean that the output voltage approaches the power
supply voltage
𝑉
s
and even exceed.
-
The maximum value of the output voltage
that we observed without saturation was
28.40 V and the largest input voltage that does not give rise to saturation in the output
14.80 V
Increasing gain and Saturation
Value of
Gain
𝐺
=
𝑅
2
⁄
𝑅
1
Expected Amplitude
Measured Amplitude of V
0
R
2
= 1
Ω
G=1
5*1=5V
V
0
= 10.40
R
2
= 2
Ω
2
10
V
0
= 20.40
R
2
= 3
Ω
3
15
V
0
= 28.40
R
2
= 4
Ω
4
20
V
0
= 28.80
R
2
= 5
Ω
5
25
V
0
= 28.80
R
2
= 6
Ω
6
30
V
0
= 28.80
-
The circuit built does deliver the expected Gain for all R
2
values mentioned in the table
-
From the table, the maximum output voltage without saturation seems to 28.80V, and
we found the value to be 28.40V, which is a bit smaller than the value measured.
-
In this part of the experiment, we neglected the output resistance of the function
generator, which is
𝑅
S
= 50 Ω. The
𝑅
S
resistor completely changes the expected gain
when put in the circuit.
Figure 1: Circuit drawn with Rs and Vs
Transient Response
Charging RC Circuit
-
For the RC circuit, we’re getting a square wave output with the calculated frequency
Time Constant
-
From the scope display, we use the paired cursor to measure the time constant by setting
it correctly between the channel 1 and 2
-
To measure the time Constant, we follow this formula
𝜏
=RC. In this case, R=3300Ω +
50 Ω from Rs and the provided C=22nF.
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-
The calculated time constant obtained after choosing the position of our x and y cursor
is
220*10
-6
s.
This is completely different from what we measured during the
experiment
.
Value of
𝑅
1
from the TA
𝑅
1
=3300 Ω
Measured time Constant of the RC circuit
𝜏
=
73.7*10
-6
s
Calculated time Constant of the RC circuit
𝜏
= 220*10
-6
s
% error in the time constant
199%
Charging RL circuit
-
For the RL circuit, we’re getting a square wave output with the calculated frequency.
Time Constant
-
On our scope display, we get the time constant by using the paired cursor and putting
it between channel 1 and 2.
-
This time around, the calculated time constant is not that far off the one measured
during the experiment.
Value of
𝑅
1
from the TA
𝑅
1
= 330Ω
Measured time Constant of the RL circuit
𝜏
= 123.68*10
-6
s
Calculated time Constant of the RL circuit
𝜏
= 110 *10
-6
s
% error in the time constant
11.06%
RLC circuit
Overdamped RLC Response
-
On the display we have a square wave for channel 2 and channel 1 is broken down and
flat.
-
In order to measure the time constant, we set the display to square wave, input the
calculated frequency, then use the cursor by placing it between channels 1 and 2.
-
The measured time constant is equivalent to
0.101ms
which is found by using the
damping ratio, and the calculated time constant seen on the display seemed to
be
560*10
-6
s
. By this, there is 99.44% error between the calculated and the measured
value for the time constant
Critically Damped Response
-
We adjusted the resistor value so that the response is critically damped (the decrease
of the Resistor value is what makes the display shows critical damping)
-
We found a resistor value of
1.7845 K
Ω
which was the value where the circuit was
starting to get critically damped.
Underdamped RLC Response
-
Here, the resistor value has been lowered again, and we can see that the V
out
is being
underdamped as the display shows the figure varying at precise point.
-
To find the damped natural frequency, we use the provided resistor value (500 Ω) and
then use the V-bars to measure the period of the oscillation between the different breaks
visible between channel 1 and 2.
-
In order to find the time constant, we use two maxima
Conclusion
Overall, this experiment was tedious and long to handle. We had to figure out the various
time constant for the 2
nd
part of the lab in order to be able to get the proper reading on the display,
and with we managed to visualize various type of response and an OpAmp in different conditions.
Related Questions
. Give the short answer offollowing questions each question carries equal marks
Don’t need tobriefly explain Its better to give point to point answer .
(a) How zenerdiode is a special diode
(b) Explain the difference between zener and avalanche effect
(c) Explain break down voltage
(d) Draw the symbol of PN junction diode, tunnel diode , Zener
Diode.
(e) How collector size is more than emitter
(f) How NPN transistor is more good as compare to pnp
(g) Why collector have more size than emitter
arrow_forward
I want the answer in clear handwriting or typeface
arrow_forward
Please answer all subpart not only first three subpart I will like for all subpart either dislike is ready please..
arrow_forward
In a full-wave rectifier _______________.
a) the output is apure DC voltage.
b) only the negative half of the input cycle is used.
c) only the positive half of the input used.
d) the complee input cycle is used.
arrow_forward
What type of waveform is produced from a bridge rectifier circuit with an open diode?
a. Half-wave output equal to Vsec- 1.4
O b. Half-wave output equal to Vsec- 0.7
Oc. Full-wave output equal to Vsec- 1.4
Od. Full-wave output equal to Vsec- 0.7
QUESTION 14
To maintain a constant voltage supplied to the load, we can use
Oa. A high-resistance voltage divider
Ob. Either a Zener diode or an IC regulator
OC. A Zener diode
O d. An IC regulator
arrow_forward
The purpose of the current limiting resistor in a Zener diode circuit is to _________.
a. Maintain a constant current through the load resistor
b. Maintain a constant voltage across the Zener diode
c. Maintain a constant current through the Zener diode
d. Drop the additional voltage from the power supply in order to maintain a constant voltage across the Zener diode
Please answer it clearly.
arrow_forward
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