Determining Beta for BJTs

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Thomas Edison State College *

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306

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Electrical Engineering

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Jan 9, 2024

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Kevin Austin ELT-306 Module 3 Lab: Determine Beta for BJTs R B (Ω) I B (µA) I C (mA) V BC (mV) V CE (V) Beta 1MΩ 4.351 0.561 4.04 4.74 129 470 kΩ 9.21 1.32 3.68 4.38 143 200 kΩ 21.5 3.37 2.72 3.42 157 100 kΩ 42.8 6.88 1.07 1.77 161 47 kΩ 90.8 10.3 -0.541 0.159 113 V BC = V CE − V BE

V CE = V CC −( I ¿¿ C×R C ) ¿ β DC = I C / I B Create a circuit similar to the simulation circuit above. Use a 470k resistor as R1. 8.48 V battery Base current: 12.35 µA Collector current: 2.11 mA Beta: 159

Simulation when R1= 470k Ω Go on to study the effect of temperature: a. Squeeze the transistor between your fingers to raise the case temperature; record any change in collector current: 2.18 mA recorded -2.11 mA = 0.7 mA increase b. Put a piece of ice in a plastic bag and hold it on the transistor to reduce the case temperature; record any change in collector current: 1.98 mA recorded - 2.11 mA = 0.13 mA decrease Describe your perception of the relationship between Beta and case temperature. As the temperature increases, the collector current increases, which increases Beta. As the temperature decreases, the collector current decreases, causing Beta to decrease. Describe the behavior of Beta vs I C . The collector current (IC) is directly proportional to the base current (IB) by the factor of beta (β), as expressed by the equation IC = β * IB. An increase in the base current results in a proportionate increase in the collector current, assuming other factors

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remain constant. Beta is essentially a measure of how effectively the transistor amplifies the input signal. Higher beta values indicate a more efficient amplifier.

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