ELT-306 WA2

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Thomas Edison State College *

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306

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Electrical Engineering

Date

Jan 9, 2024

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docx

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4

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Kevin Austin ELT-306 WA2 Questions: 1. Describe the first, second, and third approximations for a diode. In the first approximation, the diode is often modeled as an ideal diode. An ideal diode is a theoretical concept that has zero resistance when forward-biased and infinite resistance when reverse-biased. The ideal diode model simplifies calculations and is often used for basic analysis to understand the fundamental characteristics of diodes. The second approximation involves a more realistic model, known as the constant voltage drop model or piecewise linear model. In this model, the diode is considered to have a constant voltage drop when it is conducting in the forward direction. This voltage drop is typically around 0.7 volts for silicon diodes. When the diode is reverse-biased, it is modeled as an open circuit with no current flow. The third approximation is a more accurate representation of a diode's behavior and involves the Shockley diode equation. The Shockley equation describes the current- voltage relationship of a diode and takes into account the exponential relationship between the diode current and voltage. The equation is given by: I = I s ( e V nV T 1 ) I is the diode current, I s is the reverse saturation current V is the voltage across the diode n is the ideality factor V T is the thermal voltage
Kevin Austin ELT-306 WA2 2. What are the diode’s terminals labeled as? Anode (A): The anode is the positive terminal of the diode. Current enters the diode through the anode when the diode is forward-biased. Cathode (K): The cathode is the negative terminal of the diode. Current exits the diode through the cathode when the diode is forward-biased. 3. Show a diagram for a full wave bridge rectifier. Problems:
Kevin Austin ELT-306 WA2 1. For the circuit shown, R = 30 Ω, the power supply is set to 5 V. Use the second approximation for the diode. Calculate the circuit current, the diode, and resistor voltage and power. 5 V - 0.7V = 4.3 V/ 30Ω= 0.14 A for circuit 5V(0.14A)= 0.7 W for circuit | 30Ω(0.14 A) = 4.2 V for resistor | 4.2 V (R1)+0.7V= 4.9 V 2. The input winding has 1000 turns, winding #1 has 200 turns, winding #2 has 100 turns, winding #3 has 2000 turns. If the input voltage, E IN is set at 250 V, calculate the three secondary voltages. Winding 1: 1000/200= 5 | 250V/5= 50 V Winding 2: 1000/100= 10 | 250/10= 25 V Winding 3: 1000/2000 = 0.5| 250/0.5= 500 V
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Kevin Austin ELT-306 WA2 3. For a line frequency of 60 Hz, what is the ripple voltage if the load current is 250 mA and the capacitor is 500 F? 𝝁 Vripple=I/2(freq)(capacitor) 250 mA/(120 hz) (500µF)= 4.17