Waves Lab Worksheet .docx

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Wave - Lab Worksheet Name Carrington Dennis Section 15 Group 6 Date 11-8-2023 Directions: Answer the questions in the manual and enter them inside each box below. Expand the boxes as much as you need. Question 1:
Above is the graph of the sound pressure for the labeled tuning fork, with the frequency being 483 hertz by dividing the B quantity by 2 pi.
The image above shows the fourier transform graph of the first tuning fork, which shows a frequency of 484 hertz at its peak, which proves that our calculations when analyzing the first 0.05 seconds of the graph had similar results to that of the fourier transform. The image above shows the entire graph from a 0.6 second window, with the maximum frequency bein 738 hertz when dividing the value found by the highest sound pressure of 3.479 bein 4638 by 2 Pi.
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Question 2:
Above is the first 0.05 seconds of the frequency of mystery tuning fork A, which by dividing the B value by 2 pi, we get a value of 169 hertz.
The image above is the fourier transform for the frequency of mystery tuning fork A, which gives us a maximum frequency of 340 hertz. Which when compar This represents the entire 0.6 seconds of mystery tuning fork A, which when analyzin its peak compared to the fourier transform, we find the same value of around 340 hertz.
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Question 3: Above shows the first 0.05 seconds of the simultaneous frequency for mystery tuning fork A and B, when finding the value of the frequency by dividing the B value by 2 Pi, we get a frequency of 340 hertz. But it is unclear whether or not which mystery fork it is measuring as it is a standing wave that combines the frequency of each, makin it impossible to locate the frequency of each specific one with this method.
Above shows the fourier transform of the simultaneous frequencies for mystery tuning fork A and B, this makes it easier to identify the two individual frequencies being displayed by each tuning fork with this ,method with one bein 340 hertz as found in the calculations in the first 0.05 seconds, and a second frequency of 256 hertz which could not have been found by analyzing either of the other two graphs.
This shows the entire 0.6 seconds of the simultaneous frequency of tuning forks A and B, Like the first 0.05 seconds, it is not possible to locate each specific frequency for the tuning forks and is therefore inconclusive in the analysis Question 4:
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Above is the complete analyzation of the graph when comparing my voice to the tuning fork. The data found can conclude that I personally only need a little bit of fine tuning when it comes to autotune, but not much. Even then I probably could just take singing lessons or get a voice coach to help me refine my voice.
Question 5:
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The photo above is a picture of Jupiter 4 using a diffraction lens.Comparing it to the elements found in the spectacular spectra, we have concluded that the element that is found in Jupiter 4 is Oxygen. This conclusion is based on the RGB straight line pattern that was very easy to distinguish when compared to the spectra.
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The photo above is an image of Jupiter 3 using a diffraction lens. Comparing it to the elements found in the spectacular spectra, we have concluded that the element that is found in Jupiter 3 is Neon due to the consistency of straight patterns found when diffracting the light.