discussion10

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University of Illinois, Urbana Champaign *

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101

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Electrical Engineering

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Apr 3, 2024

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pdf

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PHYS 102 Discussion 10: Group activity Kalyssa Smith, Isis Johnson, Juno Jang TOTAL POINTS 5 / 5 QUESTION 1 1 Magnetic fields from currents 1 / 1 + 0.5 pts Vector orientations + 0.25 pts How to compute total field at A + 0.25 pts How to find expression for the field at A The big ideas here are magnetic fields from currents; they are perpendicular to both radius and current. We also need vector addition and superposition, because we want to add magnetic field vectors. We know that ᵰ =cos 1(2 ᵄ / ᵄ ), and the distance from either wire to point A is given by ᵅ =√( ᵄ /2)^2+ ᵄ ^2. For each current separately, the magnitude of the magnetic field is given by ᵃᵅ = ᵰ 0 ᵃ ᵅ /2 ᵰ ᵅ . From this information, we can find the x and y components of the two magnetic fields. The total field can then be found by adding the x and y components separately, and then finding the total magnetic field. QUESTION 2 2 Forces between currents 1 / 1 + 0.25 pts Vector sketches + 0.25 pts how do currents result in forces + 0.5 pts how to compute forces QUESTION 3 3 Torque on a loop 3 / 3 + 0.6 pts Approach, big ideas, formulas + 0.6 pts Solution with verfication + 0.6 pts how do forces on the wires relate to the torque + 0.6 pts how to change the torque direction + 0.6 pts behavior over time Page 1
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1 Magnetic fields from currents 1 / 1 + 0.5 pts Vector orientations + 0.25 pts How to compute total field at A + 0.25 pts How to find expression for the field at A The big ideas here are magnetic fields from currents; they are perpendicular to both radius and current. We also need vector addition and superposition, because we want to add magnetic field vectors. We know that ᵰ =cos 1(2 ᵄ / ᵄ ), and the distance from either wire to point A is given by ᵅ =√( ᵄ /2)^2+ ᵄ ^2. For each current separately, the magnitude of the magnetic field is given by ᵃᵅ = ᵰ 0 ᵃ ᵅ /2 ᵰ ᵅ . From this information, we can find the x and y components of the two magnetic fields. The total field can then be found by adding the x and y components separately, and then finding the total magnetic field. Page 4
2 Forces between currents 1 / 1 + 0.25 pts Vector sketches + 0.25 pts how do currents result in forces + 0.5 pts how to compute forces Page 6
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3 Torque on a loop 3 / 3 + 0.6 pts Approach, big ideas, formulas + 0.6 pts Solution with verfication + 0.6 pts how do forces on the wires relate to the torque + 0.6 pts how to change the torque direction + 0.6 pts behavior over time Page 11