Lab Experiment #4- Thevenin’s Theorem & Max Power Transfer.docx
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Carleton University *
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Electrical Engineering
Date
Feb 20, 2024
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Lab Experiment #4: Thevenin’s
Theorem & Max Power Transfer
ECOR1043: Circuits
Lab Group No: 1043C4-G-18
Group Member 1:
101297039 Numan Kadir Celik Group Member 2:
101326327 Mason Hassan
Performed on:
06/01/2024.
Submitted on:
09/02/2024.
7.1 Verification of Thevenin Theorem
3.
Answer: I
L
= 3.20 mA
Answer: V
L
= 472mV
4.c)
Answer: V
T H
= 689mV
Answer: R
T H
= 432Ω
Answer: I
SC
= 1.595mA
6.
Answer: I
L
= 1.45mA
Answer: V
L
=325mV
7.2 Verification of Maximum Power Transfer
Resistance R
L
Voltage V
L
Power P
L
0Ω
0V
0
100Ω
222mV
542µW
150Ω
285mV
542µW
220Ω
352mV
563µW
470Ω
474mV
478µW
∞
0V
0 W
8.1 Verification of Thevenin Theorem
1.C)
Answer: I
L
= 1.021mA
e) Take a clear screenshot/photo of the circuit showing all the
three currents.
g)
Answer: V
L=
480.04mV
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(i) Take a clear screenshot of the circuit showing all the four node
voltages
2.d) Answer: V
T H
=687.5mV
(f) Take a clear screenshots of the circuit showing all the four node
voltages .
3. e)
Answer: I
SC
= 3.3846mA
Answer: R
T H
= 203.126 Ω
(f) Answer: P
max
= 582 µW
(i) Take a clear screenshot of the circuit showing all the three
currents.
8.2 Verification of Maximum Power Transfer
Resistance
Voltage
Current
Power
0Ω
0
I
0W
50Ω
135.8mV
2.716mA
369µW
100Ω
226.8mV
2.268mA
514µW
150Ω
292.04mV
1.9469mA
569µW
220Ω
357.46mV
1.6248mA
581µW
470Ω
480.04mV
1.0214mA
490µW
1000Ω
571.43mV
571.43uA
327µW
∞
V
0
0W
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8.3 Complete Analysis of a Circuit
1.
V
T H
= 4.5056V
I
SC
= 2.5746mA
R
T H
=1750
2.
Answer: P
max
=9.137mW
3.Draw Thevenin and Norton equivalents of the circuit depicting values
of vT H , RRH and unknown load RL.
5. Take a clear screenshot of the circuit for the last (maximum) value
of the load, R
L
clearly shows load current I
L
and load voltage V
L
.
6.
Resistance
Voltage
Current
Power
0
Ω
0
I
0
300
Ω
1.7212V
5.7373mA
9.88mW
500
Ω
2.453V
4.9061mA
12.03mW
700
Ω
2.9996V
4.2852mA
12.85mW
900
Ω
3.4234V
3.8038mA
13.02mW
1500
Ω
4.2676V
2.8450mA
12.14mW
3000
Ω
5.2358V
1.7453mA
9.14mW
∞
V
0
0
9 Discussion Questions
1.
The advantage is that thevenin theorem can be used to simplify circuits, therefore
making circuits easier to beehive under other conditions. Using thevenin's
theorem with iL and vL we can find v_th and R_th a lot easier and then can be
used to simplify further analysis of the circuit
2.
a)
b) At the peak of each graph the maximum is 581µW for the first graph and then
13.02mW for the second graph
3.
a ) Rth = Vth / Isc = 4.5056V / 2.5746mA = 1750Ω
Pmax = (Vth)^2 / 4Rth = (4.5056V)^2 / 4 x 1750 = 5.755mW
b) Many factors can be taken from the difference between numbers obviously
Measurement errors or human errors can have a huge error in the work done
compared to measurements which is exact numbers in a formula
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