HW2_Solution

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Rowan University *

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231

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Electrical Engineering

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Feb 20, 2024

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EGR231 HW2 Solutions P 3.2-5 Determine the power absorbed by each of the resistors in the circuit shown in Figure P 3.2-5. Answer: The 4-Ω resistor absorbs 16 W, the 6-Ω resistor absorbs 24 W, and the 8-Ω resistor absorbs 8 W. Figure P 3.2-5 Solution: P 3.2-14 Determine the value of the voltage that is measured by the meter in Figure P 3.2-14. Figure P 3.2-14
Solution: We can label the circuit as shown. The subscripts suggest a numbering of the circuit elements. Ohm’s law to the 48 resistor to get Apply KCL at the top node of the CCCS to get Ohm’s law to the 4 resistor to get Apply KVL to the outside loop to get Finally, P3.2-27 Consider the circuit shown in Figure 3.2-27. a.) Determine the values of the resistances. b.) Determine the values of the power supplied by each current source. c.) Determine the values of the power received by each resistor. Figure 3.2-27
Solution: Using KCL and Ohm’s law: , and Using KVL, the power supplied the current sources are: , and The power received the resistors are: , and a.) , and b.) , and c.) , and P 3.3-4 Determine the voltage v in the circuit shown in Figure P 3.3-4. Figure P 3.3-4
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Solution: P 3.3-10 Determine the value of the voltage measured by the meter in Figure P 3.3-10. Figure P 3.3-10 Solution: Replace the (ideal) voltmeter with the equivalent open circuit. Label the voltage measured by the meter. Label some other element voltages and currents. Apply KVL the left mesh to get Use voltage division to get
P 3.4-7 Determine the value of the current i in the circuit shown in Figure P 3.4-7. Figure P 3.4-7 Solution: All of the elements of this circuit are connected in parallel. Replace the parallel current sources by a single equivalent 2 – 0.5 + 1.5 = 3 A current source. Replace the parallel 12 and 6 resistors by a single resistor. By current division P 3.4-12 Determine the value of the current measured by the meter in Figure P 3.4-12. Figure P 3.4-12
Solution: Replace the (ideal) ammeter with the equivalent short circuit. Label the current measured by the meter. Apply KCL at the left node of the VCCS to get Use current division to get P 3.6-3 Find i using appropriate circuit reductions and the current divider principle for the circuit of Figure P 3.6-3. Figure P 3.6-3 Solution: Reduce the circuit from the right side by repeatedly replacing series 1 resistors in parallel with a 2 resistor by the equivalent 1 resistor This circuit has become small enough to be easily analyzed. The vertical 1 resistor is equivalent to a 2 resistor connected in parallel with series 1 resistors:
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P 3.6-32 Determine the resistance measured by the ohmmeter in Figure P 3.6-32. Figure P 3.6-32 Solution: P3.6-42 Determine the values of , , , and in the circuit shown in Figure P3.6-42. Figure P3.6-42
Solution: Use equivalent resistances to reduce the circuit to From KCL . From KVL So , and . Returning our attention to the original circuit, notice that and were not changed when the circuit was reduced. Now and .