circuits_worksheet M.C (1)
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Florida Virtual School *
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Electrical Engineering
Date
Nov 24, 2024
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Circuits Worksheet
Name:
Part 1 Questions (20 points)
1.
You have a battery and a light bulb. What else must you have to complete the circuit to light the bulb. Why is this
component necessary?
Wires connecting the battery and the light bulb are required to complete the circuit and light the bulb. Conducting
cables are required because they offer a channel for electric current to go from the battery to the light bulb. Without
the wires, electrons cannot move from the positive terminal of the battery to the filament of the light bulb, and
therefore the circuit stays incomplete.
2.
How is a parallel circuit different from a series circuit? Provide an example to support your statement.
A series circuit connects components end-to-end in a single loop, allowing electricity to flow along only one path. A
parallel circuit, on the other hand, has components linked in many branches, allowing various channels for electricity
to flow.
Example:
Christmas lights are linked in series in this circuit. If a single bulb fails, the entire string becomes dark because
electricity cannot flow. Home electrical outlets form a parallel circuit. Because each device has its own distinct
channel to the power source, if one device is disconnected or malfunctions, it has no effect on the operation of
other devices attached to the same power source.
3.
What is the role of resistance in an electrical circuit? Provide an example to support your statement.
The passage of electric current is restricted in an electrical circuit by resistance. It is a material and component
property that is measured in ohms. The greater the resistance, the more difficult it is for current to pass through.
When you switch on an incandescent light bulb, the filament within provides resistance to the passage of energy.
Because of this resistance, the filament heats up and emits light. When the resistance is increased (for example, by
adopting a higher resistance filament), the bulb glows less brightly because less current flows through the circuit,
resulting in reduced power dissipation and less light output.
4.
Ohm’s law is represented by the following equation
I
=
V
R
Explain how the current would change if the amount of voltage increased, but resistance stayed the same.
Ohm's law (I = V/R) states that if the voltage (V) increases while the resistance (R) remains constant, the current (I) in
the circuit increases as well. In other words, when resistance is constant, voltage and current are directly
proportional. If the voltage is doubled, the current will double as well, providing the resistance remains constant.
Unless Otherwise Noted All Content © 2022 Florida Virtual School
Part 2 Circuit Design (20 points)
Part 2 Questions (20 points)
1.
Is the circuit you created a parallel, a series, or a series/parallel circuit? Support your answer with a description of
this type of circuit.
The preceding circuit is a series circuit. A series circuit connects components end-to-end in a single loop, creating just
one route for electricity to flow. If the circuit is broken at any point (for example, by opening the switch), the entire
circuit becomes open, and current ceases to flow through all components.
2.
If you were to add two more resistors to your circuit, but your voltage source stayed the same, how will this affect
the current in circuit? To support your statement, provide an example of how this will affect your device.
Adding two additional resistors in series to the circuit increases the overall resistance. According to Ohm's rule (I =
V/R), if resistance rises while voltage remains constant, current falls.
For example, adding two more resistors to the circuit raises the overall resistance. As a result, the current flowing
through the circuit diminishes, and the light bulb (load) becomes dimmer since less current passes through it.
3.
Describe the role of the switch in an electrical circuit.
A switch in an electrical circuit acts as a control device, allowing the circuit to be opened or closed. When the switch
is closed (turned on), current flows across the circuit, allowing linked devices or components to function. When the
switch is open (turned off), it prevents the flow of current, essentially disconnecting the circuit and preventing
electricity from reaching the devices. Switches are necessary for managing the functioning of electrical equipment as
well as conserving energy when the devices are not in use.
4.
Describe the path of electric current through your circuit.
Electric current travels through the components in a single, continuous loop in a series circuit. The current flows as
follows through the described circuit:
Current begins at the battery's positive terminal.
If the switch is closed, it flows through it.
It then travels in series through the light bulb (or load).
Finally, the current returns to the battery's negative terminal, completing the circuit.
The switch determines whether or not current may flow through the remaining components. When the switch is
Unless Otherwise Noted All Content © 2022 Florida Virtual School
turned off, no current flows and the circuit is closed. When the switch is turned off, current travels through the
complete loop, supplying electricity to the light bulb or load.
Unless Otherwise Noted All Content © 2022 Florida Virtual School
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Related Questions
If the measured values for resistors #1, #2 and # 3 are 552, 549 and 549 Ohms
calculate the %error (measured difference from expected value as a percentage) for
each resistor. Are they within tolerance (or specification) of manufacturer?
#1 98.4% #2 97.9% #3 97.9% Yes within specification
a.
b. #1 1.6% #2 2.1% #3 2.1% Yes within specification
#1 1.6% #2 2.1% #3 2.1% No outside specification
Ос.
Use Ohm's Law to calculate the equivalent resistance of R12, R23 and R123 (as
specified in the lab manual) using measured resistances #1 552 Ohms, #2 549
Ohms, #3 549 Ohms
R,
R2
R,=
R12
R23
arrow_forward
3. The figure on the left below shows a schematic diagram of a battery. The voltage measured by
U1 is called the terminal voltage given R1 = 1 ohm. In the figure on the right below, the terminal
voltage of each of the battery-resistor combination is Vr = 1.5 volts. Find the following:
a. The current passing through R5.
b. The currents passing through R1 and R3
C. The voltage across R1.
d. The voltage of the battery EMF.
e. The percentage of voltage loss ot the battery due to the internal resistance R1.
The power dissipated by the internal resistance R1.
g. The power dissipated by R5 if R1 = R2 = R3 = R4 = 0.
h. The percentage of power dissipation loss due to the four resistors R1, R2, R3, and R4
f.
R1
R3
S10
R1
U1
1.500
EMF
EMF
R5
100
V1
R2
$10
EMF
R4
EMF
EMF
arrow_forward
The drawing shows a circuit that includes a bimetallic strip (made from brass and steel) with a resistance heater wire wrapped around it. When the
switch is initially closed, a current appears in the circuit because charges flow through the heater wire (which becomes hot), the strip itself, the
contact point, and the light bulb. The bulb glows in response. As long as the switch remains closed, does the bulb:
Resistance
Contact
heater wire
point
Brass
Steel
Switch
continue to glow
cannot be determined
flash on and off
eventually turn off permanently
arrow_forward
An insulator has few electrons and atoms with bound electrons.
True or false
arrow_forward
In the figure below you see the sketches for the front and back of an electrical circuit board. The board is
cut into a trapezoidal shape and is made of plastic. On the back of the board there is conductive paint
shown here in green. On the front there are some resistors and capacitors, in addition to terminals for
inserting the leads from a DC power supply. The legs of the resistors and capacitors go through the holes
on the board and are soldered to the conducting paint on the back side. You also have a multi-meter which
you can use as an ammeter or a voltmeter.
16 v
4700
16
10
8
O-
7
3.
6.
4
O+
arrow_forward
Using the diagram below and the component photos from page 4, draw the realistic experimental setup you will use in this lab. Draw the actual apparatus with wires and other electrical elements, connected as they will be on your lab table. Be sure to label components, junctions, and distances as appropriate.
arrow_forward
What are the basic parts of a battery? How do batteries generate electrical current?
arrow_forward
How does a dry cell battery produce voltage?
What's the method it uses?
I know it's through a chemical reaction, what's that reaction called?
arrow_forward
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Related Questions
- If the measured values for resistors #1, #2 and # 3 are 552, 549 and 549 Ohms calculate the %error (measured difference from expected value as a percentage) for each resistor. Are they within tolerance (or specification) of manufacturer? #1 98.4% #2 97.9% #3 97.9% Yes within specification a. b. #1 1.6% #2 2.1% #3 2.1% Yes within specification #1 1.6% #2 2.1% #3 2.1% No outside specification Ос. Use Ohm's Law to calculate the equivalent resistance of R12, R23 and R123 (as specified in the lab manual) using measured resistances #1 552 Ohms, #2 549 Ohms, #3 549 Ohms R, R2 R,= R12 R23arrow_forward3. The figure on the left below shows a schematic diagram of a battery. The voltage measured by U1 is called the terminal voltage given R1 = 1 ohm. In the figure on the right below, the terminal voltage of each of the battery-resistor combination is Vr = 1.5 volts. Find the following: a. The current passing through R5. b. The currents passing through R1 and R3 C. The voltage across R1. d. The voltage of the battery EMF. e. The percentage of voltage loss ot the battery due to the internal resistance R1. The power dissipated by the internal resistance R1. g. The power dissipated by R5 if R1 = R2 = R3 = R4 = 0. h. The percentage of power dissipation loss due to the four resistors R1, R2, R3, and R4 f. R1 R3 S10 R1 U1 1.500 EMF EMF R5 100 V1 R2 $10 EMF R4 EMF EMFarrow_forwardThe drawing shows a circuit that includes a bimetallic strip (made from brass and steel) with a resistance heater wire wrapped around it. When the switch is initially closed, a current appears in the circuit because charges flow through the heater wire (which becomes hot), the strip itself, the contact point, and the light bulb. The bulb glows in response. As long as the switch remains closed, does the bulb: Resistance Contact heater wire point Brass Steel Switch continue to glow cannot be determined flash on and off eventually turn off permanentlyarrow_forward
- An insulator has few electrons and atoms with bound electrons. True or falsearrow_forwardIn the figure below you see the sketches for the front and back of an electrical circuit board. The board is cut into a trapezoidal shape and is made of plastic. On the back of the board there is conductive paint shown here in green. On the front there are some resistors and capacitors, in addition to terminals for inserting the leads from a DC power supply. The legs of the resistors and capacitors go through the holes on the board and are soldered to the conducting paint on the back side. You also have a multi-meter which you can use as an ammeter or a voltmeter. 16 v 4700 16 10 8 O- 7 3. 6. 4 O+arrow_forwardUsing the diagram below and the component photos from page 4, draw the realistic experimental setup you will use in this lab. Draw the actual apparatus with wires and other electrical elements, connected as they will be on your lab table. Be sure to label components, junctions, and distances as appropriate.arrow_forward
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Recommended textbooks for you
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningElectricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage LearningEBK ELECTRICAL WIRING RESIDENTIALElectrical EngineeringISBN:9781337516549Author:SimmonsPublisher:CENGAGE LEARNING - CONSIGNMENT
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ISBN:9781337900348
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Publisher:Cengage Learning
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