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Electrical Engineering

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Jun 14, 2024

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Pandya Hiral UNIVERSITY OF NEW HAVEN DEPARTMENT OF ECECS Advanced Network Design & Analysis – CSCI6649-02 Version 3, January 31, 2023 IP Address Assignment - Due Sunday, 9/24/23 by 11:59 PM 1) Write the IP address 222.1.1.20 mask 255.255.255.240 in CIDR (/) notation. Ans. 222.1.1.20/28 2) Write the correct mask value if given 179.10.1.20/26 ( CIDR notation ) . Ans. 255.255.255.192 3) You have been allocated a class B network address of 140.10.1.0 and need to create 4 subnets with around 200 hosts. What is the easiest mask to use to satisfy the criteria? Ans. 255.255.255.0/24 4) You are designing a network and given a network address of 155.100.0.0 . You’ve been assigned the task of creating a network that can support a minimum of 1200 hosts per subnet. Taking into consideration each/all possible network addresses and broadcast addresses per subnet, answer the following design questions. a) What is the class network? Ans. Class B first octet of IP falls between 128-191 b) What is the default mask? Ans. 255.255.0.0=/16 c) After subnetting, how many networks will exist? Ans. 2^5=32 networks d) After subnetting, how many hosts will exist per subnet? Ans. ( 2^11)-2=2048-2=2046 usable hosts per subnet e) What is the subnet mask needed/used for this design? Ans. 2048 addresses, we would need a subnet mask of /21 (255.255.248.0) f) What is this number using the “/” notation? Ans. 155.100.0.0/21 5) You are designing a network and given a network address of 190.40.5.0 . You’ve been assigned the task of creating a network that can support a minimum of 12 networks. Taking into consideration each/all possible network addresses and broadcast addresses per subnet, answer the following design questions.

Pandya Hiral a) What is the class network? Ans. Class B first octet of IP falls between 128-191 b) What is the default mask? Ans. 255.255.0.0=16 c) After subnetting, how many networks will exist? Ans. We would need 2^4 = 16 networks d) After subnetting, how many hosts will exist per subnet? Ans. (2^12)-2=4094 usable hosts per subnet e) What is the new subnet mask needed/used for this design? Ans. 255.255.240.0 f) What is this number using the “/” notation? Ans. 190.40.5.0/20 g) Create a table (Excel) showing your subnet #’s (starting with 0), the network address, host address ranges (for each subnet), and the broadcast address for each range. Ans.

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