E6
docx
keyboard_arrow_up
School
University of California, San Diego *
*We aren’t endorsed by this school
Course
43A
Subject
Chemistry
Date
Jan 9, 2024
Type
docx
Pages
6
Uploaded by ChancellorMetalWombat6
NAME: Qiutong Huang
EXPERIMENT 6
FISCHER ESTERIFICATION
Summary of Points for Experiment 6:
Item
Possible Points
Actual Points
PRE-LAB
2
NOTEBOOK:
Purpose/Table of Reagents
2
Corrections
2
Blank Spaces
2
Signatures
2
TLC’s
N/A
Coherent
2
Conclusions (absent here)
1
Sub-Total =
13
multiply Sub-Total x 1=
13
REPORT:
Introduction
2
Data and Calculations
59
Unknown ID
7
Data Analysis / Conclusions
5
Sub-Total =
73
TOTAL
86
POINT DEDUCTIONS:
minus any page over
7
(0)
minus for late reports
(0)
minus for TA points
(0)
minus for missing attachments
(0)
TOTAL POINTS
86
ADJUSTED TOTAL POINTS
=
Total Points x 60/86
60
INTRODUCTION
(2 points)
This experiment produce fischer ester through reaction between unknown alcohol and
excess carboxylic acid using a reflux setup. The ester was characterized by Infrared
Spectroscopy, Gas Chromatography, and boiling point analysis. IR was used to identify
specific functional groups in compounds through vibrational bonding. Based on the graph of
percent transmission versus the wavenumber, the functional group presented in ester could
be verified.
DATA
AND
CALCULATIONS
GC DATA:
RETENTION TIME FOR SYNTHESIZED ESTER: 0.829
(2 points)
RETENTION TIME FOR REFERENCE STANDARD WITH CLOSEST RETENTION
TIME:
0.853
DOES CO-INJECTION SHOW SINGLE GC ESTER PEAK?
Yes
BASED ON THIS GC DATA, THE PRESUMED IDENTITY OF SYNTHESIZED
ESTER (FROM TABLE 1) IS:
NAME: Isoamyl acetate
SUPPORT FOR THIS ID IS FROM BP AND IR DATA:
MEASURED BP of PRODUCT ESTER: N/A
(2 points)
LITERATURE BP : 142 / 756 mmHg
(2 points)
LITERATURE SOURCE of
BP:
www.sigmaaldrich.com
(1 point)
PRODUCT ESTER: YOUR DATA
(6 points; 0.5 points per entry)
Peak is due to
the bond
shown:
Absorbance
(cm
-1
)
Strength
(s,m,w)
Shape
(s,br)
Peak is due to
this bond
motion:
O-H
absence
absence
absence
O-H stretching
C=O
1741.55
s
s
C=O stretching
C-O
1229.65
m
s
C-O bending
PRODUCT ESTER: LITERATURE DATA
(6 points; 0.5 points per entry)
Peak is due to
the bond
shown:
Absorbance
(cm
-1
)
Strength
(s,m,w)
Shape
(s,br)
Peak is due to
this bond
motion:
O-H
absence
absence
absence
O-H stretching
C=O
1800-1700
s
s
C=O stretching
C-O
1300-1200
m
s
C-O bending
Source of literature data : https://www.chemicalbook.com/SpectrumEN_123-92-2_IR2.htm
(1 point)
ACETIC ACID: LITERATURE DATA
(6 points; 0.5 points per entry)
Peak is due to
the bond
shown:
Absorbance
(cm
-1
)
Strength
(s,m,w)
Shape
(s,br)
Peak is due to
this bond
motion:
O-H
3300-2500
m
br
O-H stretching
C=O
1800-1700
s
s
C=O stretching
C-O
1300-1200
m
s
C-O bending
Source of literature data : https://www.chemicalbook.com/SpectrumEN_64-19-7_IR2.htm
(1 point)
ALCOHOL: LITERATURE DATA
(6 points; 0.5 points per entry)
Peak is due to
the bond
shown:
Absorbance
(cm
-1
)
Strength
(s,m,w)
Shape
(s,br)
Peak is due to
this bond
motion:
O-H
3500-3100
m
br
O-H stretching
C=O
absence
absence
absence
C=O stretching
C-O
1100-1000
m
s
C-O bending
Source of literature data :https://www.chemicalbook.com/SpectrumEN_123-51-3_IR1.htm
(1 point)
FINAL CONFIRMED IDENTITY OF SYNTHESIZED ESTER (FROM TABLE 1):
UNKNOWN ALCOHOL NUMBER: #411
UNKNOWN ESTER ID (name): Isopentyl acetate
UNKNOWN STRUCTURE:
(7 points)
YIELD CALCULATION
Balanced equation for Fischer esterification:
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
acetic acid
alcohol
H
2
SO
4
ester
water
Fill in the table below using the appropriate data for your alcohol:
(12 points; 0.5 points
per correct entry)
Acetic
Acid
Alcohol
H
2
SO
4
Ester*
Water
H
2
SO
4
volume
1.5 mL
0.5 mL
1 drop
0.682
mL
0.0827
mL
1 drop
density**
1.049
g/mL
0.809
g/mL
N/A
0.876
g/mL
1.00
g/mL
N/A
grams
1.5735 g
0.4045
g
N/A
0.5975 g
0.0827 g
N/A
mol wt
60.05
88.15
N/A
130.18
18.02
N/A
moles
0.0262
0.00459
N/A
0.00459
0.00459
N/A
equivalent
s
5.7
1.0
catalyst
1.0
1.0
catalyst
*
these are the theoretical
amounts (assuming 100% conversion)
** literature source for density values:
www.chemicalbook.com/ProductChemicalProperties
(1 point)
Theoretical yield of ester
(
in moles
; show calculations; be sure to determine and utilize
the limiting reagent for your calculation):
Mol Alcohol = m/MW = 0.4045g/88.15 = 0.00459 mol
Mol acetic acid = 1.5735g/60.05 = 0.0262 mol > 0.00459 mol; Alcohol is limiting reagent
Theoretical yield of ester in moles = mol alcohol = 0.00459 mol
THEORETICAL YIELD: 0.00459 mol
(7 points)
Actual yield of ester (
as a percentage
):
actual mol/ theoretical mol *100%= (0.6858g/130.18)mol/ 0.00459 mol *100% = 115%
% YIELD: 115%
(7 points)
DATA ANALYSIS AND
CONCLUSIONS
(5 points)
Based on the IR spectrum of the Fischer product, the strong characteristic peak at 1741.55
cm
-1
verified the C=O stretching of this ester and the peak at 1229.65 cm
-1
verified the C-O
stretching. On the other hand, the IR spectrum of the starting material (unknown alcohol
#411) had broad peak at 3323.68 cm
-1
indicating its O-H stretching and the sharp peak at
1056.58 cm
-1
verified the C-O stretching of the alcohol. Comparing these two spectra, the
conversion from alcohol to ester through Fischer esterification was pretty successful.
The IR technique can efficiently identify the characteristic functional groups of unknown
compound but it was not so effective in determining the purity of compounds. Mixed
melting point and TLC plates would be better at finding purity of unknowns.
ATTACHMENTS:
GC
TRACE
Attach your GC trace to this report You should have a total of 2 GC traces for your
product ester from the Fischer esterification (product ester alone and co-injection with
known reference). First, record the GC instrument parameters below:
loss of 2 points for each missing GC parameter
GC Parameters:
Column packing material: 10% SE30 LIQUID PHASE ON CHROMOSORB WHP SOLID
SUPPORT, 80/100 MESH
Mobile phase (name of gas): Helium, flow rate 30mL/min
Injector temperature: 150
℃
Column temperature: 130
℃
Detector temperature: 180
℃
ATTACHMENTS:
IR
SPECTRUM
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Documents
Related Questions
Experiment 1 Group 2 Cation Analysis
Fill up the table and answer the questions below.
Results:
Ion
Confirmatory Reagents
Observation
arrow_forward
Data Collection
Kinetic Data Collection
Time, t (s)
Volume of added base (mL)
First addition
40
0.50
Second addition
101
1.00
Third addition
160
1.52
Fourth addition
224
1.99
Fifth addition
278
2.49
Sixth addition
334
3.01
Seventh additlon
389
3.48
Calculations
Concentration of NaOH stock solution:
0.01 M
Concentration of t-BuCl stock solution:
0.2 M
Volume of t-BuCl solution:
10 mL stock stock solution added to 25 mL acetone
Table view
List view
Kinetic Data
Volume of
Moles of Amount of
t-Bucl
(mol)
[-Buc]
In[-BuC
Time, t (s) added base added base
(mL)
(mol)
First
addition
40
0.50
Second
additlon
101
1.00
Third
addition
160
1.52
Fourth
addition
224
1.99
Flfth
additlon
278
2.49
Sixth
additlon
334
3.01
Seventh
addition
389
3.48
Use the data in the table above to plot In[t-BuC]]; vs time (s). Include labelled axis, a title, and a
linear trendline. Upload your plot here.
arrow_forward
100
MASS SPECTRUM
80
60
40
20
0.0
10
20
30
40
50
60
m/z
NIST Chemistry WebBook (https://webbook.nist.gov/chemistry)
1. What is the M'?
2. What is the m/z of the base peak?
3. Does it contain chlorine? Explain your answer.
Rel. Intensity
arrow_forward
What are the errors in the following answer? (4-6 total errors in answer)
arrow_forward
Below is the question
arrow_forward
I.
Look at the MS/MS for paracetamol (a drug), explain the peaks seen at 134 and 110, and draw the
structure for the 110 peak.
Paracetamòl N-(4-hydroxyphenyliacetamide
ESI+, MS/MSs
Kky pan_03_c80720211368 1-38 RT: 0.00024 AV 35 N: 107ES
T TMSES F ms 12.00g24 00 0 00-10.0g
100g
110.0
CH
но
70
(M.H]*
162.0
16
1340
130
100
arrow_forward
2 Determine the weight % composition of the sample of Cut 3 from the gc trace you ran
Peak Area for Cyclohexane
Peak Area for Octane
Weight % Cyclohexane
Weight % Octane
arrow_forward
What is the parent mass of Unknown Compound #2 based on the given MS?
100
MS-NW-1062
A
80
00
Relative Intensity
10
40
20
0
0
B
D
E
FL
[M+2], H
[M], G
25
25
50
75
100
125
150
175
m/z
[M] peak is at 180
[M+2] peak is at 182
arrow_forward
sub= 18 help
arrow_forward
Lab Exam 1- Requires Respon X
021 Summary - CHM151-N803: Ger X A ALEKS - Delana Bailey - Learn X C Sign In or Sign Up | Chegg.com X
www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNslkr7j8P3jH-IJgg7xIASweFMYphv4tCLy6BMpSgONHO-bYrHeBZ4S54EqYg5AJLeyt82s1i-_fz32exQQdKy96vMC... ☆
→ C
tab
caps lock
shift
O CHEMICAL REACTIONS
Solving for a reactant using a chemical equation
Ammonium phosphate ((NH4),PO4)
What mass of ammonium phosphate is produced by the reaction of 7.4 g of ammonia?
Round your answer to 2 significant digits.
esc
Explanation
!
1
Q
e
A
1
control option
@
2
N
Check
W
S
#3
is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H₂PO4) with ammonia (NH₂).
X
H
command
E
D
X
$
4
C
R
FL
do 5
%
V
T
MacBook Pro
6
Y
&
7
G H
B
Ⓒ2022 McGraw Hill LLC. All Rights Reserved.
U
8
J
|
ΤΝΤ Μ
N
Nitrogen N2 gas and hydrogen X +
(
9
K
0
)
0
Terms of Use | Privacy Center | Accessibility
L
0/5
P
, |
1
command option
WE
{
[
+ 11
Delana
2
|
000
Ar
KI
}
?
D Update…
arrow_forward
What is the parent mass of Unknown Compound #1 based on the given MS?
100-
MS-NW-4927
80
60
60
Relative Intensity
40
40
20
20
A
B
[M+1]
C
0
10
15
20
25
30
35
40
45 50
50
55
60
65
70 75
80
m/z
arrow_forward
Correct numbers 1 and 3. Show all work/calculations:
arrow_forward
Which column gives greater resolution between compound X and compound Y? Explain your answer.
arrow_forward
Exam 1 2022 • Saving. -
O Search (Alt+Q)
hmdoyle107@gmail.com
n Layout References
Mailings Review
View Help Table Design Layout
- 12 v A A Aa v A
E- E E AL T
O Find -
Normal
Heading 1
& Replace
No Spacing
b x x A v 2. A v
Dictate
Sensitivity
A Select
Font
Paragraph
Styles
Editing
Voice
Sensitivity
27. Which of the following compounds is a tautomer of the following compound?
HO.
HO.
a.
b.
OH
C. Both a and b
d. Neither a nor b
28. NaBH4 reduces aldehydes to primary alcohols.
a. True
b. False
E On
Accessibility: Investigate
DFocus
DII
prt sc
home
end
insert
F2
F3
@
2#
$
%
&
3
4
5
7
8
9.
W
E
R
T
Y
U
P
S
D
H
K
arrow_forward
None
arrow_forward
I need the answer as soon as possible
arrow_forward
q41 IF YOU DO NOT KNOW THE ANSWER PLEASE DO NOT REJECT IT
please calculate the unknown concentration of the protein D wih an absorbance value of A412 given the standard curve indicated in the table. write your answers in numbers only with 2 decimals.
protein concentration (ug/ml)
absorbance
0
0.000
0.02
0.161
0.04
0.284
0.06
0.438
0.08
0.572
0.10
0.762
arrow_forward
y please answer all
arrow_forward
Given the following chromatogram of
opiates found in urine, determine the
separation resolution between morphine
and fentanyl, and decide if the two peaks are
resolved.
Intensity (AU)
2.5
2.0
1.5
1.0
0.5
(TTTTTTT
1. Hydrocodone
2. Codeine
3. Oxycodone
4. Hydromorphone
Morphine
6 Fentanyl
5.
1
ili
10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
Time (min)
ليد
O 2.0; not resolved
2.0; resolved
O 1.0; not resolved
O 1.0; resolved
arrow_forward
sp
sp?
sp3
sp3
109.5°
'H.
H.
H
109.5°
120°
180°
Submit
Previous Answers Request Answer
X Incorrect; Try Again; One attempt remaining
arrow_forward
The aspirin we made in lab gad 125-133 melting point and I attached the IR. Base on this information, does it mean we made aspirin? The percent yield was also less than 50. Was the synthetic method employed ab effective method for the preparation of aspirin?
please explain your answer.
arrow_forward
PERFORM THE FOLLOWING EXERCISES DOING MOL - GRAMS STECHIMETRIC ANALYSIS
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Related Questions
- Experiment 1 Group 2 Cation Analysis Fill up the table and answer the questions below. Results: Ion Confirmatory Reagents Observationarrow_forwardData Collection Kinetic Data Collection Time, t (s) Volume of added base (mL) First addition 40 0.50 Second addition 101 1.00 Third addition 160 1.52 Fourth addition 224 1.99 Fifth addition 278 2.49 Sixth addition 334 3.01 Seventh additlon 389 3.48 Calculations Concentration of NaOH stock solution: 0.01 M Concentration of t-BuCl stock solution: 0.2 M Volume of t-BuCl solution: 10 mL stock stock solution added to 25 mL acetone Table view List view Kinetic Data Volume of Moles of Amount of t-Bucl (mol) [-Buc] In[-BuC Time, t (s) added base added base (mL) (mol) First addition 40 0.50 Second additlon 101 1.00 Third addition 160 1.52 Fourth addition 224 1.99 Flfth additlon 278 2.49 Sixth additlon 334 3.01 Seventh addition 389 3.48 Use the data in the table above to plot In[t-BuC]]; vs time (s). Include labelled axis, a title, and a linear trendline. Upload your plot here.arrow_forward100 MASS SPECTRUM 80 60 40 20 0.0 10 20 30 40 50 60 m/z NIST Chemistry WebBook (https://webbook.nist.gov/chemistry) 1. What is the M'? 2. What is the m/z of the base peak? 3. Does it contain chlorine? Explain your answer. Rel. Intensityarrow_forward
- What are the errors in the following answer? (4-6 total errors in answer)arrow_forwardBelow is the questionarrow_forwardI. Look at the MS/MS for paracetamol (a drug), explain the peaks seen at 134 and 110, and draw the structure for the 110 peak. Paracetamòl N-(4-hydroxyphenyliacetamide ESI+, MS/MSs Kky pan_03_c80720211368 1-38 RT: 0.00024 AV 35 N: 107ES T TMSES F ms 12.00g24 00 0 00-10.0g 100g 110.0 CH но 70 (M.H]* 162.0 16 1340 130 100arrow_forward
- 2 Determine the weight % composition of the sample of Cut 3 from the gc trace you ran Peak Area for Cyclohexane Peak Area for Octane Weight % Cyclohexane Weight % Octanearrow_forwardWhat is the parent mass of Unknown Compound #2 based on the given MS? 100 MS-NW-1062 A 80 00 Relative Intensity 10 40 20 0 0 B D E FL [M+2], H [M], G 25 25 50 75 100 125 150 175 m/z [M] peak is at 180 [M+2] peak is at 182arrow_forwardsub= 18 helparrow_forward
- Lab Exam 1- Requires Respon X 021 Summary - CHM151-N803: Ger X A ALEKS - Delana Bailey - Learn X C Sign In or Sign Up | Chegg.com X www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNslkr7j8P3jH-IJgg7xIASweFMYphv4tCLy6BMpSgONHO-bYrHeBZ4S54EqYg5AJLeyt82s1i-_fz32exQQdKy96vMC... ☆ → C tab caps lock shift O CHEMICAL REACTIONS Solving for a reactant using a chemical equation Ammonium phosphate ((NH4),PO4) What mass of ammonium phosphate is produced by the reaction of 7.4 g of ammonia? Round your answer to 2 significant digits. esc Explanation ! 1 Q e A 1 control option @ 2 N Check W S #3 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H₂PO4) with ammonia (NH₂). X H command E D X $ 4 C R FL do 5 % V T MacBook Pro 6 Y & 7 G H B Ⓒ2022 McGraw Hill LLC. All Rights Reserved. U 8 J | ΤΝΤ Μ N Nitrogen N2 gas and hydrogen X + ( 9 K 0 ) 0 Terms of Use | Privacy Center | Accessibility L 0/5 P , | 1 command option WE { [ + 11 Delana 2 | 000 Ar KI } ? D Update…arrow_forwardWhat is the parent mass of Unknown Compound #1 based on the given MS? 100- MS-NW-4927 80 60 60 Relative Intensity 40 40 20 20 A B [M+1] C 0 10 15 20 25 30 35 40 45 50 50 55 60 65 70 75 80 m/zarrow_forwardCorrect numbers 1 and 3. Show all work/calculations:arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you