6AL Micelle Lab
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University of California, Santa Barbara *
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Course
6AL
Subject
Chemistry
Date
Jan 9, 2024
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Pages
4
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1.
What are three areas in which the reaction you performed adhered to the principles of green
chemistry? Explain your reasoning.
a.
One of the primary ways the reaction performed in lab adhered to the principles of green
chemistry is through the use of the surfactant TPGS-750-M. The surfactant is used to
generate vesicles that contain insoluble reagents or the reduce the amount of organic
solvent used. This way of carrying out a reaction greatly reduces the amount of solvent or
and reagent being used, thus reduces the environmental impact due to common chemical
practices. This step adheres to the principle of "safer solvents and auxiliaries."
Additionally, carrying out reactions in a reaction vesicle brings the reagents closer
together and increases the chance they will react with each other thus increasing the yield
of the reaction. The use of lower amounts of solvents while at the same time obtaining
greater amounts of desired product follows the principle of " reducing derivatives" as it
reduces the need for other reagents that may pose a threat to the health of the
experimenter and the environment.
The third principle of green chemistry that the reaction performed in lab follows is that of
"real-time analysis" which says that in-line analytical techniques should be performed
during a reaction to detect changes in reaction conditions to prevent reactions from
getting out of control. This proactive approach to chemical design allows experimenters
to catch potential runaway reactions and correct them before they have a chance to get
out of hand. Runaway reactions could lead to leakage into the environment of pose health
risks to those involved. This is a common technique used in large scale manufacturing. In
this experiment, TLC plates were used to track the progress of the reaction and
demonstrates the principle of real time analysis. By first determining the reactant that
proceeded the fastest first, we eliminated an intermediate step that would require even
more use of reagents and solvents. The use of TLC analysis allowed us to minimize the
use of excess materials.
2.
What are two areas in which the reaction you performed did not adhere to the principles of green
chemistry?
a.
One area of the reaction that did not adhere to the principles of green chemistry is the
prolonged use of a hot plate. This does not demonstrate the principle of "design for
energy efficiency." The reaction could potentially have been done in a room temperature
vesicle provided there was a way to conduct the reaction albeit at a lower rate. The use of
the hot plate is likely the result of the time constraint placed on students to complete the
lab in the allotted time period, so a more relaxed environment might facilitate better
adherence to the principles of green chemistry. Most of the U.S. power grid is supplied by
the burning of fossil fuels, and so contributes to the addition of pollutants into the
atmosphere as energy is produced at demand, rather than being stored for a later date.
The other area that the reaction performed in lab does not adhere to the principles of
green chemistry is the principle of "catalysis." Instead of using a stoichiometric catalyst
like sodium carbonate, a reusable catalyst might have been better suited to reduce the
amount of base used, especially considering that excess base was used.
3.
What evidence do you have that TPGS-750M increases the reaction rate? How does TPGS-750M
act to increase the reaction rate?
a.
The evidence that the addition of TPG-750M increased the rate of the reaction comes
from the second TLC plate that was done. By comparing the reaction mixture of vial 1
against vial 3, a comparison between the addition of the surfactant (vial 1) or water (vial
3) can be done and a conclusion on the effectiveness on the addition of a surfactant can
be drawn. The product this lab was seeking to produce is a non-polar compound, while
one of the reactants, benzylamine, is a polar compound. The TLC plate used a 20:80
mixture of ethyl acetate and hexanes, thus polar compound will show up lower down, on
the plate, and non-polar compound will travel further up the plate with the mostly
non-polar solvent. The three spots represent benzylamine, 2-bromo-5-nitropyridine, and
the product. Benzylamine had the lowest number of opportunities for hydrogen bonding
with the slica gel, so it will travel the furthest up the TLC place. This means that the spot
seen further up the plate likely represents benzylamine. Furthermore, the TLC analysis
conducted shows a larger spot from vial 3 (control vial), representing more of the starting
material being present, and thus a slower reaction rate.
TPGS-750M increases the rate of the reaction by forming reaction vesicles in the solvent
that brings the reagents closer together and increases the likelihood that they will react
with each other. The addition of a surfactant allows for decreased solvent use and
increases product yield while also allowing reaction that would normally be limited by
the reagent solubility or reaction inefficiency to go closer to completion.
4.
Did you correctly predict which 2-halo-5-nitropyridine would react the fastest? Discuss which
substrate had the faster reaction rate and provide a plausible explanation, including which step in
the mechanism is the rate limiting step. Which is more important in determining the rate of the
reaction, the halogen's size or electronegativity?
a.
The prediction that 2-flouro-5-nitropyridine would react that fastest was correct. This is
due to fluorine being a much more electronegative atom and will go through the SnAr
reaction faster than bromine as the fluorine will more readily draw electrons away from
the benzene ring making it a better electrophile and facilitate nucleophilic attack by
benzylamine at a faster rate. The nucleophilic attack is the rate limiting step in this
reaction. The halogen's electronegativity is the more important factor when predicting
reaction rate as it has a larger affect on the rate limiting step of the reaction by affecting
electrophilicity of the electrophile. In general, larger atoms are better leaving groups,
however, a halogen's ability to withdraw electrons has a larger effect on the SnAr reaction
due to the fact that the rate limiting step is dependent on the electrophilicity of the
electrophile, which is more affected by the halogen's ability to withdraw electrons.
5.
What was the yield for your isolated product? Draw the structure of your final product and state
(and analyze) the evidence you have that you correctly isolated this product. As part of this
discussion, you should print off and annotate your IR, as well as the spectra.
a.
The mass yield of the final product was 0.089 grams. This represents a percent yield of
39.2% compared to the theoretical yield of 0.227 grams calculated based on the amount
of fluorinated reagent used. The annotated IR spectra below provides evidence for the
identity of the product collected.
b.
6.
State and analyze the evidence you have that your product is pure.
a.
On the basis of purity of the isolated compound, one of the largest pieces of evidence
supporting it is that the product is pure is the thin melting point range. The melting point
range obtained was 131-135 degrees celcius. With only a 4 degree range, the product
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isolated is likely very pure with very little impurities present in the crystalline structure.
Additionally, the melting point range may be slightly inaccurate, as time is typically a
constraint for obtaining a truly accurate melting point range, so the ideal rise of 2 degree
celcius per minute is too slow for a reasonable trial during the allotted lab time slot. If
time was not a limiting factor, the obtained melting range would likely be thinner.
Furthermore, the IR spectra obtained lines up with the predicted product with multiple
peaks present that support the conclusion that the isolated product was true to the
prediction. If the reagents used were true to their identity, then the presence of the IR
peak at ~3200 provides further support for the idea that the product obtained was a
product of an SnAr reaction between benzylamine and the fluorinated reagant. A single
broad peak here indicates the presence of a secondary amine.
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a. 2-bromo-2-methylbutane (organic phase)
b. saturated sodium chloride (aqueous phase)
c. hard to predict since densities are both very close to 1.18 g/mL
d. there would only be one phase since the substances are miscible
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35-38. Ethanol is freely soluble in water, but ethane is insoluble. Using principles of
Нн
Н-С-С-н Н-С-С-О:
нн
intermolecular forces describe...
35. ...what is needed for a solute to dissolve in a solvent.
нн
ннн
ethane
ethanol
35. ...why ethanol dissolves in water.
36.
. why ethane does not dissolve in water.
...
38. Draw the IMF that is formed between water and ethanol.
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The Background section of this lab explains why weight percent (%w/w) can be
useful for comparing the relative amount of a desired or "active" compound in
different products.
During the lab, a major goal will be to decide which of your experiment flasks yield
data that would allow you to correctly calculate the %w/w of sodium bicarbonate in
these tablets.
Let's assume that you correctly choose one flask for this calculation. If the amount of
NaHCO3 in that flask was 2.80 g and the original weight of the tablet was 4.50 g,
what is the %w/w NaHCO3 in the tablet that went into this flask? GIVE YOUR
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Your Answer:
Answer
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2. Think about what you said in the question above. If your sample was espresso, would your answer change? Why?
3. I was careless and ended up using a wavelength other than the peak (Say 250 nm). Would I still be able to carry out the experiment successfully? What might be the reason that I do not get optimum results?
4. I carried out the experiment using a scratched (or several scratches) cuvet for one standard, and clear cuvets for others. How might my calibration curve change (improve or get worse and why)? Pllllz answer these questions as soon as possible
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what would the mechanism be(if any)?
More information provided below:
You are removing salt, talc and other impurities to get pure aspirin. Recrystallization is a useful technique that can be used to purify solid organic compounds. Thistechnique involves the solubility of organic solids in various solvents. For recrystallization towork properly, the target compound must dissolve in a solvent when it is hot and not dissolvewhen it is cold. In this experiment you will isolate pure aspirin from aspirin tablets. Aspirin tabletscontain various salts and impurities in addition to aspirin. By using recrystallization, you will beable to remove the impurities and be left with pure aspirin.Sometimes pairs of solvents can used to produce better results. In this experiment, 91%isopropanol will be used to recrystallize aspirin. The 91% isopropanol contains 91%…
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which of the following statements regarding purification by recrystallization is false?
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ii. water is the best recrystallization solvent for organic compounds.
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a. i, ii, and iii
b. i and ii
c. i only
d. ii and iii
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Explain this
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Part B: Miscibility of liquids
1.
Place 10 drops of propan-2-ol into each of two DRY semi-micro test tubes.
2.
Add 10 drops of water to one test tube and 10 drops of cyclohexane to the other test tube, shake and observe whether
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organic waste container.
3.
Place 10 drops of water in a clean semi–micro test tube and add 10 drops of cyclohexane to it. Record whether the two
liquids are miscible. If two layers form (i.e. the liquids are immiscible) add a drop of blue food dye to the mixture and
shake, then allow the two layers to reform. Based on your observation, decide whether the food dye is more soluble in
water or cyclohexane and then discard the mixture into the non–halogenated waste container.
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Water
Cyclohexane
Propan-2-ol
Cyclohexane
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Q3. What is the advantage of using Buchner filtration in filtering crystals?
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Q5. Briefly explain why crystals form as the solvent cools during recrystallization.
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Group of answer choices
a. The other group will observe less water absorbed because tap water has a higher
concentrations of ions present.
b. The other group will observe less water absorbed because tap water forms
hydrogen bonds more easily.
c. The other group will observe less water absorbed because tap water is more
attracted to sodium polyacrylate.
d. The other group will observe more water absorbed because tap water has a higher
concentrations of ions present.
e. The other group will observe more water absorbed because tap water is more
attracted to sodium polyacrylate.
The other group will observe more water absorbed because tap water forms
hydrogen bonds more easily.
f.
K
DEC
23
útv
♫
ST
اله
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True
False
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D. More chromophores in the same molecule cause a hypsochromic effect
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A. T-I*
B. 0 0*
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D. n-o*
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A. KBr pallet
B. Thin film
C. Nujol Mull
D. Organic compound sample in the solvent
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