Cal Lab Report

docx

School

Carleton University *

*We aren’t endorsed by this school

Course

1003

Subject

Chemistry

Date

Jan 9, 2024

Type

docx

Pages

7

Uploaded by LieutenantMetal13000

Report
Calorimetry: Determination of Heats of Solution ##-##-2022 By: #### Lab Section: L3 TA: Procedure: Calibrating the Calorimeter 1. 60mL of distilled water was heated in an 250mL beaker on a hot plate. The water was heated to 75 C. 2. 15.0 mL of distilled water at room temperature was measured into the calorimeter using a 50 mL graduated cylinder. 3. The calorimeter was then sealed and shaken for 60 seconds. The temperature was taken. 4. 20.0 mL of hot water was measured into the calorimeter using a 50 mL graduated cylinder after taking the temperature of the hot water. 5. The calorimeter was then sealed and shaken for 60 seconds. The temperature was taken. 6. The calorimeter was rinsed with distilled water before being dried using a tissue. The process was repeated 2 additional times. Heat of Solutions 7. 35.0 mL of room temperature distilled water was measured into the calorimeter using a 50mL graduated cylinder. 8. The calorimeter was then sealed and shaken for 60 seconds. The temperature was taken. 9. 1.5g of anhydrous sodium acetate was measured using an analytical balance. It was then poured into the calorimeter. 10. The calorimeter was then sealed and shaken for 60 seconds. The temperature was taken. 11. The calorimeter was rinsed with distilled water before being dried using a tissue. The process was repeated 3 addition times using 2.0g, 2.5g, and 3.0g of anhydrous sodium acetate. 12. The process was then repeated 4 addition times using 1.5g, 2.0g, 2.5g, and 3.0g of sodium acetate trihydrate. Data and Observations:
Table 1: Theoretical Molar Heat Compound Theoretical Molar Heat (kJ/mol) NaC 2 H 3 O 2 -17.32 NaC 2 H 3 O 2 •3H 2 O +19.66 Table 2: Temperatures of distilled water used to calibrate the calorimeter Trial Volume of Cold Water (mL) Volume of Hot Water (mL) T 1 (± 0.2 C) T 2 (± 0.2 C) T f (± 0.2 C) 1 15.0 20.0 19.1 55.4 34.5 2 15.0 20.0 20.0 57.0 37.8 3 15.0 20.0 20.1 57.0 34.8 Table 3: Change in temperature per mass of water Trial Mass of cold water (g) Mass of warm water (g) ΔT of Cold Water ( C) ΔT of Warm Water ( C) 1 15.0 20.0 15.4 -20.9 2 15.0 20.0 17.8 -19.2 3 15.0 20.0 14.7 -22.2 Table 4: Initial and final temperature for sodium acetate anhydrous dissolved in water Trial Mass (± 0.02g) Initial Temperature (± 0.2 C) Final Temperature (± 0.2 C) 1 1.50 20.0 21.6 2 2.01 19.1 22.0 3 2.50 19.5 22.8 4 3.03 19.5 23.5 Table 5: Change in temperature once turned into solution Trial Mass (± 0.02g) ΔT ( C) Mass of Solution (g) 1 1.50 1.6 36.50 2 2.01 2.9 37.01 3 2.50 3.3 37.50 4 3.03 4.0 38.03
Table 6: Molar heat of solution of sodium acetate anhydrous Trial Mass (± 0.02g) Moles ΔH of Solution (kJ/mol) 1 1.50 0.018 -13.578 2 2.01 0.025 -17.963 3 2.50 0.030 -17.259 4 3.03 0.037 -17.202 Table 7: Initial and final temperatures for sodium acetate trihydrate Trial Mass (± 0.02g) Initial Temperature (± 0.2 C) Final Temperature (± 0.2 C) 1 1.51 19.6 18.0 2 2.01 20.0 18.0 3 2.52 20.0 17.9 4 3.05 20.0 17.0 Table 8: Mass of solution per change in temperature Trial Mass (± 0.02g) ΔT ( C) Mass of Solution (g) 1 1.51 -1.6 36.51 2 2.01 -2.0 37.01 3 2.52 -2.1 37.52 4 3.05 -3.0 38.05 Table 9: Molar heat of solution of sodium acetate trihydrate Trial Mass (± 0.02g) Moles ΔH of Solution (kJ/mol) 1 1.51 0.01110 22.019 2 2.01 0.01478 20.954 3 2.52 0.01838 17.927 4 3.05 0.02228 21.425
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Calculations: 1. Calculating the heat capacity of the calorimeter: C cal = [ ( m cool water ) ( ρ water ) ( ∆T cool water ) + ( m warmwater ) ( ρ water ) ( ∆T warmwater ) ] ∆T calorimeter / cool water C calT 1 = [ ( 15.0 ) ( 4.184 ) ( 15.4 ) + ( 20.0 ) ( 4.184 ) ( 20.9 ) ] 15.4 C calT 1 = 50.806 J / °C C calT 2 = [ ( 15.0 ) ( 4.184 ) ( 17.8 ) + ( 20.0 ) ( 4.184 ) ( 19.2 ) ] 17.8 C calT 1 = 27.502 J / °C C calT 3 = [ ( 15.0 ) ( 4.184 ) ( 14.7 ) + ( 20.0 ) ( 4.184 ) ( 22.2 ) ] 14.7 C calT 3 = 63.614 J / ° C C calav = C cali n C calav = 50.806 + 27.502 + 63.614 3 C calav = 47.307 J / °C 2. Calculating the molar heat for each mass: ∆ H soln = m c ∆T n solute ∆ H solnT 1 = ( 36.51 × 10 3 ) 4.184 ( 1.6 ) ( 1.51 82.03 ) ∆ H solnT 1 =− 13.578 kJ / mol
Molar heat of solution of sodium acetate anhydrous Trial Mass (± 0.02g) Moles Mass of Solution (g) ΔH of Solution (kJ/mol) 1 1.50 0.018 36.50 -13.6 2 2.01 0.025 37.01 -18.0 3 2.50 0.030 37.50 -17.3 4 3.03 0.037 38.03 -17.2 Molar heat of solution of sodium acetate trihydrate Trial Mass (± 0.02g) Moles Mass of Solution (g) ΔH of Solution (kJ/mol) 1 1.51 0.01110 36.51 22.0 2 2.01 0.01478 37.01 21.0 3 2.52 0.01838 37.52 18.0 4 3.05 0.02228 38.05 21.4 3. Calculating average value for molar heats: ∆ H av = ∆ H i n ∆ H 1 av = ( 13.578 ) + ( 17.963 ) + ( 17.259 ) +(− 17.202 ) 4 ∆ H av =− 16.501 kJ / mol ∆ H 2 av = ( 22.019 ) + ( 20.954 ) + ( 17.927 ) +( 21.425 ) 4 ∆ H av = 20.581 kJ / mol Precision = ∆ H high ∆ H low ∆H av × 1000
Precision 1 = 13.578 −(− 17.963 ) 16.501 × 1000 Precision 1 = 265.74 ppt Precision 2 = 22.019 17.927 20.581 × 1000 Precision 2 = 198.82 ppt Relative Error = | ∆ H av ∆H t ∆ H t | × 100 Relative Error 1 = | 16.501 −(− 17.32 ) 17.32 | × 100 Relative Error 1 = 4.73% Relative Error 2 = | 20.581 19.66 19.66 | × 100 Relative Error 2 = 4.68% 4. Why a substance with an endothermic heat of solution dissolves: The sign of the molar heat of each solution is indicating whether the reaction is endo or exothermic. An endothermic reaction has a positive molar heat of solution, and an exothermic reaction has a negative molar heat of solution. Discussion: The calculated values for molar heat of the solutions could have varied from the theoretical values for different reasons. To start, the uncertainty on the mass of the solute and the temperature of the solution were factors in the final relative error being as large as it is. Another factor justifying the difference could be that an inaccurate specific heat capacity was used as the solution was not completely water and the sodium acetate, and sodium acetate trihydrate specific heat capacities were not considered in the calculation. Conclusion: The average molar heat of solution for sodium acetate anhydrous was calculated to be -16.5 kJ/mol, making it an exothermic reaction. The precision of this experiment was calculated to be 265 ppt. The calculated value has a relative error of 4.73% when compared to the theoretical
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
value of -17.32 kJ/mol. This level of error means that the calculated value is consistent with the theoretical value. The average molar heat for sodium acetate trihydrate is 20.6 kJ/mol, making it an endothermic reaction. The precision and relative error were calculated to be 199 ppt and 4.68%, respectively. Once again, this level of error means that the average value is consistent with the theoretical. The heat capacity of the calorimeter was calculated to be 47.3 J/ C