06-05_task1

POSSIBLE POINTS: 10 Sodium acetate dissolves readily in water according to the following equation. NaC2H3O2 (s) → NaC2H3O2 (aq) AH = –17.3 kJ Classify this process as either exothermic or endothermic and explain how you determined it. B I 0 / 10000 Word Limit 4 7 8 9. 10 11 12 13 Next > English Help Center | Schoology Blog | PRIVACY POLICY | Terms of Use Schoology © 2021 II !!!

I’m stuck on this problem, especially part d. Thanks

3. Suppose you are to measure the BOD removal rate for a primary wastewater treatment plant. You take 2 samples of raw sewage on its way into the plant and two samples of the effluent leaving the plant. Standard 5-day BOD tests are run on the four samples, with no seeding producing the following data: Sample Dilution Doi (mg/L) DOf (mg/L) Source 1 Raw 1:30 9.0 2.2 2 Raw 1:20 9.0 ? 3 Treated 1:15 8.5 1.5 4 Treated ? 9.0 1 a. Find the BOD5 for the raw and treated sewage, and the percent removal of BOD in the treatment plant. b. Find the DO that would be expected in sample 2 at the end of the test. c. What would be the maximum volume of treated sewage for sample 4 that could be put into the 300 mL BOD bottle and still have the DO after 5 days remain above zero?

I am struggling to figure out the steps to complete this problem! Please help me to understand the steps to solve this question!

Standardization of Sodium Hydroxide (NaOH) Solution Mass of KHP used (g) Initial buret reading (mL) Final Buret reading (mL) Link to video explaining how to do the following calculations Volume of base used (mL) Molarity of the NaOH solution (M) Titration of the Acetic Acid in Vinegar - WATCH THE VIDEO FOR A CALCULATION WALKTHRU Volume (mL) of Vinegar used Initial buret reading (mL) Final buret reading (mL) Volume of base used (mL) Molarity of the Acetic Acid in the Vinegar (M) HINT: Use as the M of base Trial 1 Link to video explaining how to do the following calculations 0.7138 1.15 18.97 Try 1: ✔ 17.82 2 2 Info ID41 NG 6 Info ID51 Trial 1 5.00 1.98 21.97 NG 2 Info ID121 NG 6 Info ID131

(9.29 × 105/8)-20.81 =  with correct sig figs

Help with the CHEM Lab report please! It is about Volumetric Analysis  There is also a Burn trail please make sure for that!

I will thumbs up if correct !

Be sure to answer all parts. Enter your answer in scientific notation. Carry out the following calculation, paying special attention to significant figures, rounding, and units (J-joule, the SI unit of energy; mol = mole, the SI unit for amount of substance): (6.022 x 1023 atoms/mol) (4.68 x 10-18 J/atom)(1-2-3-2)=[25.051 Note that the numbers 1 and 3 in the last term are exact. x 10 J/mol

How many grams of MgCl2 in 30.00 mL of a 25.5 ppt solution ? (30.00 mL)(- mL а. 25.5 b. 100.0 С. 2 d. 30.00 f. 24 е. 6 i. 18.0 g. 3 h. 36 j. 1 k. 6.00 x 10-3 I. 3.60 х 10-2 m. 6.00 x 10-2 n. 5 О. 3.0 х 102 р. 1.80 х 10-2 9. 7.65 х 10-10 г. 2.63 S. 7.89 t. 5.26 и. 1012 V. 109 w. 106 х. 103 у. 101 z. 10

| ax NME /Chemical%20Reactions%20Asgn%202-5.pdf 9 Employee Home r4c Covenant Health Ca... Outlook.com - Free... S Birthday party politi. G what does it mea 1 / 2 100% Chemical Reactions-Write Neat and Balanced Reactions from Word Equations You need to submit one sheet of paper (not this one), that is very neat, with a fully balanced reaction for these 6 reactions Remember to include proper states. 1. solid potassium metal reacts with oxygen gas to produce solid potassium oxide. 2. solid potassium chlorate decomposes into oxygen gas and solid potassium chloride. 3. solid aluminum oxide is decomposed into solid aluminum and oxygen gas. 4. aqueous cobalt(III) nitrate reacts with solid zinc to produce aqueous zinc nitrate and solid cobalt.

1. Aluminum sulfate can be made by the following reaction: 2AlCl3(aq)+3 H2SO4(aq)➡Al(SO4)3(aq)+6HCl(aq). It is quit soluble in water, so to isolate it the solution has to be evaporated to dryness. This drives off the volatile HCl, but the residual solid has to be heated to a little over 200 celsius to drive off the water. In one experiment, 25.0 g of AlCl3 were mixed with 30.0 g of H2SO4. Eventually, 28.46 g of pure Al2(SO4)3 were isolated. Calculate the percentage yield. 2. The potassium salt of benzoic acid, potassium benzoate (KC7H5O2), can be made by the action of potassium permanganate on toluene (C7H8) as follows: C7H8+ KMnO4➡ KC7H5O2+ 2MnO2+ KOH+ H2O. If the yield of potassium benzoate cannot realistically be expected to be more tha 71%, what is the minimum number of grams of toluene needed to achieve this yield while producing 11.5g of potassium benzoate? 3. A chemist set up a synthesis of phosphorus trichloride by mixing 12.0g P with 35.0g Cl2 and obatained 42.2 g of PCl3.…

3:52 Chegg 12.94 46 | ... KB/s expert.chegg.com/expertqna (2) Home Expert Q&A My answers My stats Today CF Score: Answered: Skipped: Time remaining: 00:09:20 Chemistry please neat writing! 13.28 Pick an appropriate solvent(s) from table to dissolve each of the following substances. Common Polar Common Nonpolar Solvents Solvents water hexane (H₂O) (C6H12) acetone diethyl ether (CH3CH₂OCH2CH3) (CH3COCH3) methyl alcohol (CH3OH) toluene (C7H8) Part A glucose (polar) Express your answer as a chemical formula. If there is more than one answer, separate them by a comma. ΑΣΦ ? Part B salt (ionic) Express your answer as a chemical formula. If there is more than one answer, separate them by a comma. ΑΣΦ ? Part C vegetable oil (nonpolar) Express your answer as a chemical formula. If there is more than one answer, separate them by a comma. ΑΣΦ ? Part D sodium nitrate (ionic) Express your answer as a chemical formula. If there is more than one answer, separate them by a comma. 2= | ΑΣΦ 1 ? Answer…

Consider the following data: HX → X- + H+ Ką = 6.61 · 10- 5 H2A + НА + Н + Ka = 2.68 · 10-7 Calculate the Keg for the following reaction: H2A + X¯ + HA¯ +HX Record your answer in scientific notation to 3 sig figs.

(5) question is in the photo below

Reactions of Na₂CO3 * Reactions with a carbonate salt and acid are gas evolving! I Na₂CO3(aq) Na* CO3²- Na2CO3(aq) Na₂CO3 (aq) Na₂CO3(aq) Na₂CO3 (aq) Na₂CO3 (aq) Na2CO3 (aq) Na₂CO3 (aq) Na₂CO3 (aq) Na₂CO3 (aq) + + + + 2 Pb(NO3)2 (aq) H* CI HCl (aq) Na3PO4 (aq) KI (aq) CuSO4 (aq) H₂SO4 (aq) NaOH (aq) AgNO3(aq) CaCl2 (aq) HNO3(aq) →>> →> →>>> ➜>> ↑ ↑ Na Cl + H* CO3²- NaCl (aq) + [H₂CO3 (aq)] → NaCl (aq) + H₂O (1) + CO2 (s) 2 NaCl (aq) + H2₂O (1) + PAGE 123 OF 232 (g)

A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer.   I'm confused on what the next step is from here. I dont know if I need to switch the 10-3 to the bottom to make the 103 and how would I solve the problem from here?

I don’t know how to do this

For Q6. I am uncertain on how 20.49 is the answer because I thought we’d use the figure with least sig figs which is 1 sig fig in this problem. I’m confused on why it’s 4 sig figs in the answer.

Question 7 of 10 Balance the following chemical equation (if necessary): C.H«(g) + O:(g) → CO:(g) + H:O(g) ロ+ 3 4 6. 7 8 9 ロ,ロロ。口。 (s) (1) (g) (aq) O2 CO. H:O C.H. Activ Go to Reset x H:O Delete 40F Rain sho nviDIa G-SYNC

Identify each of the following changes as either exothermic or endothermic • + + • • • • • 3C(s) + 2Fe₂O₂(g) catalyst 4Fe(s) + 3C0���(g) 4HNO3(aq) + 5N₂Hä(I) → 12H₂O(g) + 7N₂(9) 4C₂H5NO2(1) + 902(g) → 8CO2(g) + 10H₂O(l) + 2N2(g) + 3893.9 kJ 2NaAlO₂(aq) + 3H₂(g) + 850.0 kJ → 2NaOH(aq) + 2Al(s) + 2H₂O(1) The temperature of the surroundings increases. The products of a reaction have more potential energy than the reactants. The system absorbs energy. Potential Energy (kJ) ΔΗ> 0 Reactants ΔΗ < Ο The temperature of the surroundings decreases. Potential Energy (kJ) The reactants have more potential energy than the products. Reactants AH° +458.7 kJ Reaction Pathway The system releases energy. AH-2462.0 kJ Products Products Reaction Pathway

Calculate the mass of carbon needed to form 6.08 moles of iron according to this reaction: 2Fe2O3 + 3C --> 4Fe + 3 CO₂ Click 'add attachments to support your work' then click 'add a file' to upload your work. Your Answer: Answer units