Lab 5 report Enthalpy

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Tarrant County College, Fort Worth *

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1441

Subject

Chemistry

Date

Jan 9, 2024

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docx

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5

Uploaded by DrWater16907

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name partner name date Determining the Enthalpy of a Chemical Reaction Objectives: The objective of this project is to measure the transfer of heat by finding the change that occurs between the system and surroundings. Procedures: Procedures followed as instructed in the notebook. Results:
Table 1: Trial one and two of the reaction between HCl and NaOH The table above shows the comparison between trials one and two between mass and temperatures from the reaction between hydrochloric acid and sodium hydroxide. Table 2: Trial one and two of the reaction between NaOH and NH4Cl
The table above shows the comparison between trials one and two between mass and temperatures from the reaction between sodium hydroxide and ammonium chloride. Table 3: Trial one and two of the reaction between HCl and NH4OH The table above shows the comparison between trials one and two between mass and temperatures from the reaction between hydrochloric acid and ammonia solution Table 4: Trial one and two of the reaction between deionized water and ammonium nitrate
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The table above shows the comparison between trials one and two between mass and temperatures from the reactions between deionized water and ammonium nitrate. Table 5: Trial one and two of the reaction between HCl and magnesium The table above shows the comparison between trials one and two between mass and temperature from the reactions between hydrochloric acid and magnesium.
Analysis: During reaction 4, the probe wasn’t working properly. Thus, the temperature was showing much higher than what it most likely was. And during reaction 5, there was a large difference between the TF after mixing. Calculations: Cp H20 = 4.18J/C Ccup = 22 J/C Ccal = Qcal/ T Average Hrxn = (trial 1 + trial 2)/2. ex (-2.22134 + -10.23748)/2 = -6.22941 Qsoln KJ = (Cp x mass x T f-Ti ) ex (4.18 x 52.5 x 9.2) = 2.01894 Qcup = (Ccup x T sin ) ex 22 x 9.2 = 0.2024 Qcal = (Ccal x T) Ccal = 22 J/C ex 22 x 9.2 = 0.2024 Qrxn = -(Qcal + Qs/n). ex. -(0.2024 + 2.01894) = -2.22134 Qrxn = Hrxn. ex. -2.22134=-2.22134 T = High temp - low temp. ex 31.1 - 21.9 = 9.2 Discussion and Conclusion: One uses a polystyrene cup instead of a beaker since the polystyrene cup will keep thermal conduction better. Whereas a glass beaker would not be as good. Mg strips would most likely not work as well as Mg powder because powder can dissolve faster and strips would take a lot longer, thus losing heat during that. Mg+2HCl->MgCl2+H2