Experiment 7 Irresistible Buffers

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University of Nebraska, Lincoln *

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Chemistry

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Feb 20, 2024

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Experiment 7 Irresistible Buffers? Total Points: 22 Student’s Name: Adam Miller Lab Section: 804 The Effect of Acid on Solutions (6 pts) Beakers 1-6 Beaker 1 2 3 4 5 6 Contents DI H 2 O 50 mL NaCl 0.35 g NaAc + 50 mL HAc 0.60 g NaAc + 50 mL HAc 1.00 g NaAc + 50 mL HAc 2.00 g NaAc + 50 mL HAc mL of HCl added pH pH pH pH pH pH Black initial solvent, 0 7.54 4.80 4.28 4.50 4.87 5.06 1 1.87 1.62 3.94 4.24 4.60 4.96 2 3.23 4.00 4.36 4.72 3 1.97 3.67 4.22 4.68 4 3.00 3.98 4.55 5 1.89 3.87 4.42 6 3.43 4.31 7 2.60 4.23 8 1.77 4.19 9 4.00 10 3.89 1. (2 pts) Which beaker had the least amount of pH change? Explain why this occurred. Beaker 6, because it had the greatest amount of NaAc 2. (2 pts) Write the reaction occurring in beaker 1. HCl (aq) + H 2 0 (l) <-> Cl - (aq) + H 3 0 + (aq)
Experiment 7 Irresistible Buffers? Total Points: 22 The Effect of Base on Solutions (6 pts) Beakers 7-12 Beaker 7 8 9 10 11 12 Contents DI H 2 O NaCl 0.35 g NaAc + 50 mL HAc 0.60 g NaAc + 50 mL HAc 1.00 g NaAc + 50 mL HAc 2.00 g NaAc + 50 mL HAc mL of NaOH pH pH pH pH pH pH Blank, 0 6.00 9.41 4.40 4.55 4.68 5.04 1 10.22 11.53 4.45 4.62 4.88 5.17 2 4.66 4.85 5.10 5.31 3 4.92 5.05 5.42 5.58 4 5.31 5.42 5.55 5.71 5 5.95 6.27 6.23 6.59 6 10.87 10.75 11.45 11.50 7 8 9 10 Post-lab Questions NOTE: You must show your work for all calculations; no work, no credit. 1. (2 pts) Another buffer found in blood is based on the equilibrium between dihydrogen phosphate and monohydrogen phosphate. The reaction is shown below: H 2 PO 4 - (aq) + H 2 O (l) → H 3 O + (aq) + HPO 4 2- (aq) If the pH of a blood sample was 7.11, what would you calculate as the ratio of [H 2 PO 4 - ] to [HPO 4 2- ]? (K a1 = 7.5 × 10 -3 , K a2 = 6.2 × 10 -8 , K a3 = 3.6 × 10 -13 ) pH = pKa + log [A - ]/[HA] -log(6.2E-8) = 7.2076 7.11 = 7.2076 + log [HPO 4 2- ]/[H 2 PO 4 - ] [HPO 4 2- ]/[H 2 PO 4 - ] = 10 -.0976 = .799 [H 2 PO 4 - ]/[HPO 4 2- ] = 1/.799 = 1.25
Experiment 7 Irresistible Buffers? Total Points: 22 2. (4 pts) If you needed to perform a reaction in a controlled pH environment that was fairly basic, you might choose to use the ammonium and ammonia buffer system. How many grams of solid ammonium chloride would you have to add to 2.750 liters of 0.150M NH 3 to obtain a buffered solution of pH = 8.00? (K b of NH 3 = 1.8 × 10 -5 ) pOH = pKb + log [NH 4 ]/[NH 3 ] 6.00 = 4.74 + log [NH 4 ]/[NH 3 ] 1.26 = log [NH 4 ]/[NH 3 ] 10 1.26 = 18.197 18.197 = [NH 4 ]/[.150M] 2.729 = x / 2.750 x = 7.50mol 7.50 * 53.492 = 401 grams
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