LAB#4

LAB REPORT ¿¿¿ ¿¿¿  Add up the concentration of [Fe 3+ ] and [SCN - ]: ¿¿ ¿¿  Multiply the concentration of [Fe 3+ ] and [SCN - ]: ¿¿ ¿¿  Multiply the absorbance by the addition of [Fe 3+ ] and [SCN - ]: #1: ( 0.095 ) x ( 1.188 x 10 − 3 ) = 1.1286 x 10 − 4 #2: ( 0.164 ) x ( 2.157 x 10 − 3 ) = 3.5374 x 10 − 4  Now divide this value by the multiplication of the concentration of [Fe 3+ ] and [SCN - ] and this is your X-value on your graph: X 1 = 1.1286 x 10 − 4 1.9606 x 10 − 7 = 575.640 X 2 = 3.5374 x 10 − 4 3.8451 x 10 − 7 = 919.976  Now divide this value by the multiplication of the concentration of [Fe 3+ ] and [SCN - ] and this is your Y-value on your graph: Y 1 = 0.095 1.9606 x 10 − 7 = 484547.5473 Y 2 = 0.164 3.8451 x 10 − 7 = 426516.8656 THANH TIN LAM 3

LAB REPORT expressed as the ratio of reactant and product concentrations, where each term is raised by the reaction coefficient. its. When the equilibrium constant is expressed in moles, the equilibrium constant is called Kc. The value of this constant at equilibrium is always the same, regardless of the initial concentration of the reaction. At a given temperature, whether the reactants are mixed in their exact equilibrium ratios or the reactants have a large excess at first, the ratio described by the equilibrium constant expression will reach obtained when the reaction composition ceases to change. THANH TIN LAM 6