Enthalpy and Chemical Reactions 120 DQs 1
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Texas A&M University *
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Course
120
Subject
Chemistry
Date
Feb 20, 2024
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3
Uploaded by PrivateLapwingPerson1176
Name: Mackenzie Tijerina
Section: 617
Spring 2024 CHEM 120
Where did the Heat Go? Enthalpy Change for Chemical Reactions Discussion Questions.
Please include your name and section number and make sure that your responses to these discussion questions are legible. If your responses are illegible, they will not receive credit. We suggest that you type your responses. Using the data that you collected and wrote in your lab notebook during lab, organize your data into the required tables or graphs. Make sure that you format the table properly, i.e. include a title and labels for your columns, etc. Also make sure your plots are properly formatted and clearly labeled. (Hint: Follow the guidelines from Data and Graphics from CHEM 119!). 1.
Plot the data for each of your trials using three separate graphs. Include the equation and R
2
for the linear regression. (6 points)
Chart 1: This shows the enthalpy change of HCl and NaOH, showing time vs temperature or the calorimeter. y = -0.0004377x + 29.1974638
R² = 0.0051454
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31
0
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500
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700
Temperature (C) Time (s) Enthalpy Change of HCl and NaOH: Time vs Temperature
Chart 2: This shows the enthalpy change of HCl and Mg, showing time vs temperature or the calorimeter. Chart 3: This shows the enthalpy change of HCl and MgO, showing time vs temperature or the calorimeter. y = -0.0038826x + 33.7768116
R² = 0.3761432
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0
100
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Temperature (C) Time (s) Enthalpy Change of HCl and Mg: Time vs Temperature
y = 0.0001406x + 25.9264493
R² = 0.0074121
24.6
24.8
25
25.2
25.4
25.6
25.8
26
26.2
26.4
-80
20
120
220
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420
520
620
720
Temperature (C)
Time (s) Enthalpy Change of HCl and MgO: Time vs Temperature
2.
The lab manual discusses energy use in Texas, and states that the amount of heat energy released is dependent on the fuel combusted. Please visit the following link: https://www.engineeringtoolbox.com/fuels-higher-calorific-values-d_169.html#gsc.tab=0 and obtain the Specific Energy (use the Lower Heating Value in MJ/kg) of Gasoline and Diesel. Then, calculate and report the energy released by 1 mole of Gasoline and the energy released by 1 mole of Diesel in units of KJ. Assume a MW of 100.2 g/mol for Gasoline, and 198.1 g/mol for Diesel. Then, compare the energy output of both fuels, which one has the higher output per mole?
Mass of gasoline = moles of gasoline x molar mass of gasoline =1mol × 100.2gmol =100.2g =100.2g×10−3Kg=0.1002kg
Energy released by gasoline = Specific energy of gasoline x mass of gasoline Energy released by gasoline =43.4MJKg×0.1002Kg=4.34868MJ Energy released by 1 mole of gasoline = =4.34868MJ×103kJMJ =4,348.68KJ Mass of diesel = moles of diesel -Molar mass of diesel =1mol×198.1g9mol =198.1g Energy relesed by 1 mole or 0.1981kg of disel Energy relesed by diesel = Specific energy of diesel* mass of diesel Energy relesed by =42.6MJKg×0.1981kg =8.43906MJ Energy relesed by 1 mol of diesel =8.43906MJ×103kJMJ =8,439.06kJ 1 mole of gasoline releases 4338.66 kJ energy. 1 mole of diesel releases 8439.06 kJ energy. Therefore, diesel has a higher energy output per mole than gasoline.
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icat Sumnation
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