Enthalpy and Chemical Reactions 120 DQs 1

pdf

School

Texas A&M University *

*We aren’t endorsed by this school

Course

120

Subject

Chemistry

Date

Feb 20, 2024

Type

pdf

Pages

3

Uploaded by PrivateLapwingPerson1176

Report
Name: Mackenzie Tijerina Section: 617 Spring 2024 CHEM 120 Where did the Heat Go? Enthalpy Change for Chemical Reactions Discussion Questions. Please include your name and section number and make sure that your responses to these discussion questions are legible. If your responses are illegible, they will not receive credit. We suggest that you type your responses. Using the data that you collected and wrote in your lab notebook during lab, organize your data into the required tables or graphs. Make sure that you format the table properly, i.e. include a title and labels for your columns, etc. Also make sure your plots are properly formatted and clearly labeled. (Hint: Follow the guidelines from Data and Graphics from CHEM 119!). 1. Plot the data for each of your trials using three separate graphs. Include the equation and R 2 for the linear regression. (6 points) Chart 1: This shows the enthalpy change of HCl and NaOH, showing time vs temperature or the calorimeter. y = -0.0004377x + 29.1974638 R² = 0.0051454 23 24 25 26 27 28 29 30 31 0 100 200 300 400 500 600 700 Temperature (C) Time (s) Enthalpy Change of HCl and NaOH: Time vs Temperature
Chart 2: This shows the enthalpy change of HCl and Mg, showing time vs temperature or the calorimeter. Chart 3: This shows the enthalpy change of HCl and MgO, showing time vs temperature or the calorimeter. y = -0.0038826x + 33.7768116 R² = 0.3761432 29 30 31 32 33 34 35 0 100 200 300 400 500 600 700 800 Temperature (C) Time (s) Enthalpy Change of HCl and Mg: Time vs Temperature y = 0.0001406x + 25.9264493 R² = 0.0074121 24.6 24.8 25 25.2 25.4 25.6 25.8 26 26.2 26.4 -80 20 120 220 320 420 520 620 720 Temperature (C) Time (s) Enthalpy Change of HCl and MgO: Time vs Temperature
2. The lab manual discusses energy use in Texas, and states that the amount of heat energy released is dependent on the fuel combusted. Please visit the following link: https://www.engineeringtoolbox.com/fuels-higher-calorific-values-d_169.html#gsc.tab=0 and obtain the Specific Energy (use the Lower Heating Value in MJ/kg) of Gasoline and Diesel. Then, calculate and report the energy released by 1 mole of Gasoline and the energy released by 1 mole of Diesel in units of KJ. Assume a MW of 100.2 g/mol for Gasoline, and 198.1 g/mol for Diesel. Then, compare the energy output of both fuels, which one has the higher output per mole? Mass of gasoline = moles of gasoline x molar mass of gasoline =1mol × 100.2gmol =100.2g =100.2g×10−3Kg=0.1002kg Energy released by gasoline = Specific energy of gasoline x mass of gasoline Energy released by gasoline =43.4MJKg×0.1002Kg=4.34868MJ Energy released by 1 mole of gasoline = =4.34868MJ×103kJMJ =4,348.68KJ Mass of diesel = moles of diesel -Molar mass of diesel =1mol×198.1g9mol =198.1g Energy relesed by 1 mole or 0.1981kg of disel Energy relesed by diesel = Specific energy of diesel* mass of diesel Energy relesed by =42.6MJKg×0.1981kg =8.43906MJ Energy relesed by 1 mol of diesel =8.43906MJ×103kJMJ =8,439.06kJ 1 mole of gasoline releases 4338.66 kJ energy. 1 mole of diesel releases 8439.06 kJ energy. Therefore, diesel has a higher energy output per mole than gasoline.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help