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—— » R B © *+ @ Speed of Sound_2-07-24 — Saved to my Mac v Draw Design Layout References Mailings Review Q Tell me DComments fEditing v AsNew.‘, vi13 viA A | Aav | A _E V:E__r i‘v T:L: 2= IQ/V [2 @ é Styles Styles Dictate Sensitlvity Editor A ¥ l q Pane OBJECTIVE (3 points): A The objective for this experiment is to determine the speed of sound waves in the air by : comparing measured values of speed to the theoretical value. This will be done by adjusting the level of eater in a tube and finding resonances for specific keyboard notes. Experimental Data (3 point): How many resonance do you find in E3? 336.2 +/- 32.96 m/s How many resonance do you find in B4? 296.3 +/- 98.78 m/s Data Analysis (10 points): Theoretical Speed of Sound I Room Temperature T = 20 °C (provided in the Simulation) } Theoretical speed of sound in air at temperature T: ¢ v, = (331.5 + 0.607T) Experimental Speed of Sound 1) Frequency 1 - note E3 fea= 164.81 Hz 2) The length of air column for the first resonance L= 0.38 +/-0.005 m 3) The length of air column for the second resonance L= 1.40 +/-0.005 m nd_2-07-24.docx”; 3,615 characters (an approximate value) e = = E3J Focus G =
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6
v=1720 cm-1
v = 1150 cm 1
1. NaNH,
2. CH3l
v=3500-3300 cm¹
CI
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Heat
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v = 3500-3300 cm-¹
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H₂SO4, heat
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a
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v = 3500-3300 cm 1
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A sample of solid silver is heated with an electrical coil. If 30.4 Joules of energy are added to a 12.1
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Question 2
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"Heater Meals" are food packages that contain their own heat source. Just pour water into the heater unit, wait a few minutes, and voilà! You have a hot meal.
Mg(s) + 2 H2O(l) → Mg(OH) 2 (s) + H2(g)
Question 3
1 pt
Species
AH° (kJ/mol) S° (J/mol·K) AƒG° (kJ/mol)
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Mg(s)
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Question 7
1 pt
Question 8
2 pts
Question 9
1 pt
HEATER MEALS
Question 10
2 pts
Question 11
1 pt
Question 12
1 pt
Question 13
Charles D. Winters
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HEATER MEALS
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Question 14
1 pt
The heat for the heater unit is produced by the reaction of magne-
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Molarity (M) of NaOH (from the bottle of NaOH): 0.204 mol/L
Titration Number
3
4
34.44
mL
0.50ML
Final Volume buret reading (mL NAOH)
34.00
33.85
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33.80
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Initial Volume buret reading (mL NaOH)
Volume NaOH used in titration (mL) =
Final Volume buret reading (mL NAOH) - mL
Initial Volume buret reading (mL NaOH)
33.94
For calculations multiply mL by 10-3 to
convert mL toL
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from the bottle of NaOH
0.204
mol/L
10.0 mL 10.0mL
0.204
0.204
0.204
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Please answer the following questions fully and to the best of your ability
1) Please state how you would synthesize the following polymer below and show the mechanism behind
the reaction. Note that this also means you need to tell me which molecule you are starting with as well
as specifying all conditions required.
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2) Will either the polymer or the monomers you used to make it show peaks if IR spectroscopy analysis
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Ethanol (C₂H6O) burns in air
C₂H60) +O2(g) → CO2(g) + H₂O (1)
Balance the equation and determine the volume of air in liters at 35°C and 790 mm Hg required to burn 227 g of ethanol.
Assume that air is 21% O₂ by volume.
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9) In the reversible reaction Fe 3+ (ag) + SCN (ag) E → FESCN2+ (aq), the reactants are yellowish and the
product is red.
Why are iron (III) nitrate and potassium thiocyanate used to create this reaction mixture?
a) iron and thiocyanate are spectator ions
b) iron and thiocyanate are colorless
c) nitrate and potassium are spectator ions
d) nitrate and potassium are purple
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If you know the [OH ], how can you determine the pH of a solution?
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1.0 x 1014[H3O+]× [OH ]
When the [OH ] is known, the [H3O+] can be calculated using the equation
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which is called the
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[H3O+] x [OH
After rearranging to solve for [H30+], this equation can then be substituted into the expression to
water neutralization expression
solve for pH, which is
to determine the pH of a solution from the given [OH ].
water equilibrium equation
pH = - log [OH]
1.0 x 107 = [H3o*]× [OH]
pH = log [H3O*]
water dissociation expression
pH = 0.5 log [H30*]
|1.0 x 10-7= [H3O*] × [OH¯]
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- 6 v=1720 cm-1 v = 1150 cm 1 1. NaNH, 2. CH3l v=3500-3300 cm¹ CI CH₂OH Heat OH 1. Hg(OAc)2 e H₂O 2. NaBH4 v = 3500-3300 cm-¹ HBr No characteristic v tBuOK v=3050 cm¹¹, 1650 cm1 H₂SO4, heat HBr a v = 3050 cm¹¹, 1650 cm¹ 1. BH3 2. NaOH, H₂O₂ v = 3500-3300 cm 1 CrO₂, H₂SO4 v = 1705 cm¹arrow_forwardHi I need help with this questions pleasearrow_forwardb My Questions | bartleby N MyLab and Mastering O Chem 131 Ch 8 Flashcards | Quiz x Course Home A openvellum.ecollege.com/course.html?courseld=16962209&OpenVellumHMAC=7148a2eb283445d6406a0f326efaf3a4#10001 O My Courses C-C 348 C= C 614 C-H 413 H– Cl 431 C-C1 328 O 304 O -38 O -44 O 38 O 2134 ENG 3:36 PM P Type here to search 68°F 梦 的 US 11/5/2021 近arrow_forward
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