Marking Guidelines Chemistry 2015
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STHS 2015 Chemistry Preliminary Examination
.
Marking Guidelines and model Answers.
Part A Multiple Choice
1
2
3
4
5
6
7
8
9
1
0
11
1
2
1
3
1
4
1
5
1
6
1
7
1
8
1
9
2
0
C
B
C
C
C
A
C
B
A
A
B
B
D
D
C
A
A
C
C
A
Part B
FAULDER
21.a.
Marking Criteria
Marks
Both equations correct
2
One equation correct
1
Suggested Answer:
2Na
(s)
+
2H
2
O
(l)
2NaOH
(aq)
+
H
2(g)
2Na
(s)
+
2HCl
(aq)
2NaCl
(aq)
+
H
2(g)
21.b.
Marking Criteria
Marks
Equation correct
1
Suggested Answer:
Na
Na
+
+
e
-
22
Marking Criteria
Marks
Compares and contrasts the molecular shape, bonding and BP of
H
2
O and H
2
S, and includes a correct electron dot diagram.
Response contains both similarities and differences.
3
Describes the structure, bonding and BP of H
2
O and H
2
S
OR
Describes the structure and bonding of H
2
O and H
2
S, and
includes a correct electron dot diagram.
2
Describes the structure and/or bonding and/or properties of H
2
O
or H
2
S or correct diagram
1
Suggested Answer
Molecular Shape:
Both are bent due to the two pairs of nonbonding electrons in oxygen and
sulfur.
Bonding:
Similarity - The hydrogen atoms are bonded to the O or S atom through covalent
single bonds, where each bond contains one electron from each of the atoms in the bond.
1
Both molecules have dispersion forces between them, and both are polar.
Differences. Oxygen is more electronegative than sulfur so water is capable of hydrogen
bonding, which is stronger than dipole-dipole interactions of hydrogen sulfide.
Boiling Point
Boiling point of water is higher than that of hydrogen sulfide due to the hydrogen bonding.
23.a.
Marking Criteria
Marks
Correct Element chosen and corresponding reason
2
Correct element but incorrect reason
OR
Incorrect element but correct reason
1
Suggested Answer:
Either B or C – because they are malleable and conduct electricity
23.b.
Marking Criteria
Marks
Correct element and reason
2
Correct element but incorrect reason
OR
Incorrect element but correct reason
1
Suggested Answer:
D as is melting point is -101
C.
All other elements are solid at room temperature
23.c.
Marking Criteria
Marks
Correct balanced equation and correctly refers to it to give
volume of hydrogen gas required
2
Correct balanced equation
OR
Correct volume of hydrogen stated
1
Suggested Answer:
N
2(g)
+
3H
2(g)
2NH
3(g)
From stoichiometry of equation 300 mL of hydrogen is required
24.a.
Marking Criteria
Marks
Correctly calculates mass of Mg and O
Correctly calculates moles
Determines empirical formula
3
Correctly calculates two of above
2
Correctly calculates one of above
1
Suggested Answer:
Mass of Mg =
32.63
-
32.14
=
0.49 g
Mass of MgO
=
32.95
-
32.14
=
0.81
2
Mass of O = 0.81
-
0.49
=
0.32
Mg
:
O
Mass
0.49
:
0.32
Moles
0.49/24.31
:
0.32/16
0.020156
:
0.02
Simplest
1
:
1
Empirical formula is MgO
24b.
Marking Criteria
Marks
Recognises oxygen in air is O
2
Calculates mass correctly
2
Uses mass of O calculated above
1
Suggested Answer
Mass of O atoms = 0.32 therefore the mass of O
2
=
0.32/2
= 0.16g
25.a.
Marking Criteria
Marks
Correct description of trend with reference to Na and Ar.
2
Correct description of trend
Or compares Na and Ar only
1
Suggested Answer:
Ionisation energy is the energy required to remove an electron from a gaseous atom of an
element. The first ionisation energy generally increases across a period from left to right.
Thus Na has the lowest value and Ar has the highest value.
25.b
Marking Criteria
Marks
Explains the trend down group VII with reference to elements
3
Describes the trend down group VII with reference to elements
2
Identifies trend Or gives examples
1
Suggested Answer:
Electronegativity is a measure of the ability of an atom to attract bonding electrons towards
itself and form compounds.
Electronegativity decreases down a group
because
each element going down has another
electron shell.
This greater distance between the protons and the outer electrons decreases the
ability to attract electrons.
Therefore F is more electronegative than iodine.
26.
3
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Marking Criteria
Marks
Defines a decomposition reaction and describes two examples of
this type of reaction the student has observed, including the
energy needed to decompose the compound.
Includes a relevant chemical equation.
3
Defines a decomposition reaction and describes one example of
this type of reaction the student has observed, including the
energy needed to decompose the compound.
2
Defines a decomposition reaction OR
Describes an example of this type of reaction the student has
observed, including the energy needed to decompose the
compound
OR includes a relevant chemical equation of a decomposition
reaction.
1
Decomposition reactions involve breaking a more complex chemical into simpler
components. Two ways that this can be done are by strongly heating a compound or by
electrical energy:
(or exposing to uv light)
Thermal decomposition
Heat 1g copper(II) carbonate in a test tube with a Bunsen burner. It decomposed into CuO
and CO
2
:
CuCO
3
(s)
CuO (s) + CO
2
(g)
Electrolytic Decomposition
We also used electrolysis to decompose water into hydrogen and oxygen in a voltameter. This
process uses electricity to break the chemical bonds in the water.
2H
2
O (l)
2H
2
(g) + O
2
(g)
Photolytic decomposition
Silver chloride was prepared by adding 5mL 0.1 mol/L silver nitrate to 5mL 0.1 mol/L
potassium chloride. Silver chloride precipitated was exposed to UV light and it turned dark
grey as silver was deposited.
2AgCl(s)
2Ag(s)
+
Cl
2
(g)
(NOTE: Outline a method usually means numbered steps with substance, quantities and
equipment.
As this was only worth 3 marks, the marking was more lenient)
27.
Marking Criteria
Marks
Gives reasons why Al should be recycled AND
Gives a judgement
2
Gives reasons why Al should be recycled OR
Gives judgement
1
Suggested Answer:
Recycling helps conserve valuable metal resources and avoids the environmental damage
resulting from mining and the discharge of pollutants to the atmosphere. Aluminium requires
5 times more energy to mine than is does to obtain the same mass of metal by recycling.
Judgement:
Therefore Al and other metals should be recycled.
CARRINGTON
28 a.
4
Marking Criteria
Marks
Identifies process
1
Suggested Answer:
Fractional distillation
28b.
Marking Criteria
Marks
Correctly describes filtration and distillation with the
addition of water
2
Correctly describes filtration or distillation with the
addition of water
1
Suggested Answer:
1.
Enough water was added to cover the mixture containing X(solid), Y (liquid) and Z
(solid)
2.
The mixture was poured through a folded filter paper that was placed in a filter funnel
that was supported in a filter ring attached to a retort stand.
3.
The residue was collected and dried
4.
The filtrate containing X(solution) and Y (liquid) was then separated using the process
of distillation.
29.
Marking Criteria
Marks
Explains the difference between two properties of diamond and
graphite in terms of structure and bonding.
3
Explains the difference between one property of diamond and
graphite in terms of structure and bonding, and outlines one
other difference.
2
Outlines the difference between two properties of diamond and
graphite in terms of structure and bonding.
1
Suggested Answer:
Diamond and graphite have different electrical conductivity and hardness because of their
structure and bonding. In diamond each C atom is covalently bonded to 4 others in a
tetrahedral arrangement, forming 6 membered rings in a 3D giant covalent lattice. All of the
valence electrons are involved in forming bonds. Because of the strength of the covalent
bonding throughout the lattice, the substance is extremely strong, and finds application in
industrial drills and saws. The lack of electrical conductivity is because there are no
delocalised, mobile electrons in the structure to carry an electric charge. Graphite on the other
hand is composed of 2D layers of carbon atoms arranged in 6 membered rings, and there is
one electron per carbon atom not involved in bonding. These are delocalised between the
layers, and mobile, and this is what results in the electrical conductivity of graphite. Graphite
is softer than diamond because the 2D layers can slide over each other, and because not all of
the atoms in the structure are connected to the entire lattice. Only the atoms in the 2D layers
are connected by covalent bonds.
5
30a.
Marking Criteria
Marks
Identifies observations and correctly identifies the gas
produced
2
Identifies the gas or one observation
1
Suggested Answer:
Hydrogen gas was produced and small bubbles of gas were produced and there was twice as
much volume of gas produced as compared to the other electrode.
The test used was the hydrogen pop test, where a flame was brought close to the gas being
tested and a distinctive “pop” is heard.
30b.
Marking Criteria
Marks
Identifies observations and correctly identifies the gas
produced
2
Identifies the gas or one observation
1
Suggested Answer:
Oxygen gas was produced and large bubbles of gas were produced and there was half as
much volume of gas produced as compared to the other electrode.
The test used was the glowing splint test, where a piece of wood that is quickly extinguished
was brought close to the gas being tested and it is readily ignited
31a.
Marking Criteria
Marks
Identifies X,Y and Z
2
Identifies X,Y or Z
1
Suggested Answer:
X: Pb(NO)
3
Y: CaCl
2
..........................................
Z: HCl
31b.
Marking Criteria
Marks
Correctly writes the
NET
ionic equation
1
Suggested Answer:
Pb
2+
+ 2Cl
-
PbCl
2(s)
6
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NOYES
32.a.
Marking Criteria
Marks
Accurately plots data for both compounds
Draws 2 line graphs, including axes titles, suitable scales and a
key.
4
Draws a satisfactory graph of the data, with one or two errors in
the presentation of the graph.
2-3
Makes a limited attempt at graphing the data, including at least
ONE correct feature of the graph.
1
Suggested Answer:
(NOTE: the line of best fit should be a smooth line)
32.b.
Marking Criteria
Marks
Explains why the acid took longer to react.
2
Identifies the acid was less concentrated and took longer to react.
1
Suggested Answer
The less concentrated acid took longer to react and produce the 30 mL of CO
2
(g). This is
because there are less acid particles available to react and therefore less chance of collisions
and product (gas) being formed.
33.a
.
Marking Criteria
Marks
Correct answer
1
but-1-ene
7
33.b.
Marking Criteria
Marks
Discusses the benefits and limitations of the model (two of
each),
identifies how it can be used to derive the correct name of the
compound
Writes a judgement
3
Discusses at least one benefit and one limitation of the model,
and uses it to derive the correct name of the compound.
OR
Discusses the benefits or limitations of the model (two).
OR
Writes a Judgement
2
Identifies one benefit or limitation of the model.
OR
Writes a judgement
1
Judgement:
The model shown in Figure 2 is very useful because it allows the molecule to be visualised
despite its size.
One of the main benefits of the 3D model is that it can be flipped over, so that the student
can see that the molecule is really 1-butene, and not 3-butene. It shows the difference
between a double bond and a single bond, and shows how the single bonded carbon has a
tetrahedral structure, whereas the double bonded carbon has a planar structure. It also shows
that the double C=C bond does not rotate, but the single C-C bond does. The model has some
limitations though, such as the relative sizes of H and C not being accurate, and the electrons
in the bonds are not visualised.
34.a.
Marking Criteria
Marks
Correct balanced equation with states
1
Correct balanced equation with no states
0.5
Suggested Answer:
States are always marked in combustion, precipitation and redox!
C
2
H
6
(g) + 7/2 O
2
(g)
2CO
2
(g)
+ 3H
2
O(l)
34.b.
Marking Criteria
Marks
Identifies a problem
1
Suggested Answer:
Toxic CO(g) is produced
(Harmful is a motherhood statement & must be backed up with toxic or pollutant)
35.a.
Marking Criteria
Marks
Identifies endothermic reaction
1
8
Suggested Answer:
Endothermic
35.b.
Marking Criteria
Marks
Correct value of E
A
read off graph
1
Suggested Answer:
30 kJ
23.c.
Marking Criteria
Marks
Line drawn to show lower E
A
1
Suggested Answer:
.
9
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0.0154 M
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This is a required question
0.0393 M
0.0131 M
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1-32. A bottle of concentrated aqueous sulfuric acid, labeled 98.0
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(a) How many milliliters of reagent should be diluted to 1.000 L to
give 1.00 M H₂SO4?
(b) Calculate the density of 98.0 wt% H₂SO4-
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- Suppose that you heated the hydrated copper (II) sulphate in a test tube, instead of a beaker. How might this affect your results? 4 MAY 19 ... MacBook Pro & * %23 $ 2 3 4 5 6 7 E Y U G H J K C V M MOSISO command option command レーarrow_forwardRosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition reactions in the table. Reactants Products 2NACIO, 2NaCI + 302 302 + 2KCI 2KCIOз 2LICIO3 What products should she record in the last row of the table? O 2 LICI + 302 3LICI + 202 O 2 LiO + 3CI2 O 3LIO+ 2Cl2 Mark this and return Save and Exit Submit ntentViewers/AssessmentViewer/Activit.arrow_forwardPart B BH? Express your answer as a chemical formula. Fo ΑΣΦ 0 ? A chemical reaction does not occur for this question. Submit Request Answerarrow_forward
- Supply the missing information in the table. (Given in Blue). Answers in scientific notation should be in this sample format >>> 1.0 x 10-14arrow_forwardCalculate the moles of KHP titrated in each trial = M x L = 0.5 M x 0.025 L= Calculate the moles of NaOH using stoichiometry of the reactionarrow_forwardSee Figure 3-2. The two compounds in A ar The two compounds in B ar ✓ [Select] the same molecule skeletal isomers functional group isomers different molecules The two compounds in C are [Select] The two compounds in D are [Select ]arrow_forward
- Which of the following KT graphs corresponds to this chemical reaction: 4NH3(g) +50₂(g) = 4NO(g) + 6H₂O(l)? HomeworK 6 K Search 1 a b ll с Y 1 F7 ça H Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. ||| d IV Unanswered. 2 attempts left 1 & 7 T F8 U PRE F9 * 00 KA 8 1 || F10 ( 9 T O Fll K L K ) 0 1 F12 P III 4+ EPIC GAMES T Prt Sc ScrLk + 11 KA 1 Insert IV T Submit Delete Backspace Enter 7 Home 4arrow_forward! A Escape Chemistry 106! → C Type here to search X + https://docs.google.com/forms/d/e/1FAIpQLSfdH4Cb3Jih0g_TXnrExG4Oh2E11 120 1 2 3 4 Your answer Back 0.0154 M 0.0154 M 0.0308 M 0.0154 M This is a required question 0.0393 M 0.0131 M 0.0393 M 0.0393 M A decomposition reaction is determined to be zero order. The initial concentration of the reactant is 0.500 M. The rate constant for the reaction is 0.0000273 M/s. How long, in seconds, will it take for the concentration of the reactant to reach 0.378 M? Next Never submit passwords through Google Forms. 2:11 a 28 NuVCU4MS9 120% W 0.114 M 0.228 M 0.228 M 0.228 M 6.62 x 10-4 7.36 x 10-5 1.32 x 10-3 6.62 x 10-4 88 Ⓒ↓ |111\ Clear form 67°F J ABP 10:04 PM 5/11/2023arrow_forwardPls pls pls solve this accurate pls it's very very important so pls solve accuratearrow_forward
- CHCASE Dashboard Item 3 A student modek four types of land use in a city. Each model has the same amounts of soil, pebbles, and gravel. A bottle is placed under each model to represent an aquifer, as showWn. Item 4 Item 5 Item 6 Item 7 Aqulfer Aquifer Item 8 Model P Model Q Item 9 Item 1 Item Item Aquifer Aquifer Model R Model S Which model represents land use that will recharge groundwater in a city the most, and why? O Model P; it has green spaces with grass and plants. O Model Q; it has neighborhoods with large front yards. O Model R; it has buildings near paved roads and parking lots. O Model S; it has houses near large trees with deep roots.arrow_forwardI need help calculating and setting up questions 4 or 5. thank you for your help!arrow_forward9. r. S. H₂CRO4 A d= & OH NO₂ H₂ Pd/C NO₂ 6 = iq= HNO3 H₂, Pd/C H₂SO4arrow_forward
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