Chapter SH, Problem 13.6EP

To determine

To prove:

The each expression into trigonometric form

Explanation of Solution

Given:

  $\sec \theta \cot \theta =\csc \theta$

Concept used:

Trigonometric ratios: - Atrigonometric ratio are the ratios between edges of a right triangle.

Calculation:

Trigonometric ratio is

  $\begin{array}{l}\sec \theta \cot \theta =\csc \theta \\ \frac{1}{\cos \theta }\times \frac{\cos \theta }{\sin \theta }=\frac{1}{\sin \theta }\\ \frac{1}{\sin \theta }=\frac{1}{\sin \theta }\end{array}$