Chapter SH, Problem 13.4EP

To determine

To find:

The each expression into trigonometric form

Answer to Problem 13.4EP

The exact value of $\tan \theta =\frac{5}{2\sqrt{5}}$

Explanation of Solution

Given:

  $\csc \theta =\frac{3\sqrt{5}}{5};0^0<\theta <{90}^0$

Concept used:

Trigonometric ratios: - Atrigonometric ratio are the ratios between edges of a right triangle.

Calculation:

Trigonometric ratio is

  $\begin{array}{l}\csc \theta =\frac{3\sqrt{5}}{5};0^0<\theta <{90}^0\\ \tan \theta =\frac{\text{opposite}\text{side}}{\text{adjacent}\text{side}}\\ \tan \theta =\frac{5}{2\sqrt{5}}\end{array}$