PRECALCULUS:...COMMON CORE ED.-W/ACCESS
PRECALCULUS:...COMMON CORE ED.-W/ACCESS
10th Edition
ISBN: 9780134781839
Author: Demana
Publisher: PEARSON
Expert Solution & Answer
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Chapter P.5, Problem 59E
Solution

What are the dimensions of the soccer field?

The dimensions of the soccer field are-

L=110 yd

B=80 yd

Given:

Several world cup ‘94 soccer matches were played in Stanford University stadium in Menlo Park, California. The field is 30yd longer than it is wide, and the area of the field is 8800  yd2.

Concept Used:

  • Use factorization method to solve.
  • To reduce the algebraic or quadratic equation into its simpler form.
  • The equations are represented as the product of factors instead of expanding the brackets.

Calculation:

According to question-

The length of the soccer field is = L

The width of the soccer field is = B

The field is 30yd longer than it is wide

  So L=30+B

The area of the field is 8800  yd2.

Area of the field is = L⋅B = 8800  yd2.

  (30+B)⋅B=880030B+B2=8800B2+30B−8800=0B2+(110−80)B−8800=0B2+110B−80B−8800=0B(B+110)−80(B+110)=0(B−80)⋅(B+110)=0(B+110)=0B=−110  not possiblewidth would not be in negative(B−80)=0B=80So L=30+BSo L=30+80L=110

So the length of the soccer field is = L=110 yd

So the width of the soccer field is = B=80 yd

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Chapter P.5, Problem 58E
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Chapter P.5, Problem 60E

Chapter P Solutions

PRECALCULUS:...COMMON CORE ED.-W/ACCESS

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