PRECALCULUS:GRAPHICAL,...-W/ACCESS
10th Edition
ISBN: 9780134781945
Author: Demana
Publisher: PEARSON
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Concept explainers
Expert Solution & Answer
Chapter P.1, Problem 58E
Solution
To write the number
Given:
The electric charge, in coulombs, of an electron is about
Concept Used:
- A number in scientific notation contains a nonzero integer followed by a decimal and some nonzero integer exponent over 10.
- If the decimal point moved to the left side, raise the exponent of 10 by the positive integer digit by which the decimal moved to left.
- If the decimal point moved to the right side, raise the exponent of 10 by the negative integer digit by which the decimal moved to left.
Calculation:
In order to write the number
Note that there are 19 digits before the first nonzero integer, so move the decimal 19 digits right and raise the exponent of 10 by
Therefore, the number in scientific notation is
Chapter P Solutions
PRECALCULUS:GRAPHICAL,...-W/ACCESS
Ch. P.1 - Prob. 1QRCh. P.1 - Prob. 2QRCh. P.1 - Prob. 3QRCh. P.1 - Prob. 4QRCh. P.1 - Prob. 5QRCh. P.1 - Prob. 6QRCh. P.1 - Prob. 7QRCh. P.1 - Prob. 8QRCh. P.1 - Prob. 9QRCh. P.1 - Prob. 10QR
Ch. P.1 - Prob. 1ECh. P.1 - Prob. 2ECh. P.1 - Prob. 3ECh. P.1 - Prob. 4ECh. P.1 - Prob. 5ECh. P.1 - Prob. 6ECh. P.1 - Prob. 7ECh. P.1 - Prob. 8ECh. P.1 - Prob. 9ECh. P.1 - Prob. 10ECh. P.1 - Prob. 11ECh. P.1 - Prob. 12ECh. P.1 - Prob. 13ECh. P.1 - Prob. 14ECh. P.1 - Prob. 15ECh. P.1 - Prob. 16ECh. P.1 - Prob. 17ECh. P.1 - Prob. 18ECh. P.1 - Prob. 19ECh. P.1 - Prob. 20ECh. P.1 - Prob. 21ECh. P.1 - Prob. 22ECh. P.1 - Prob. 23ECh. P.1 - Prob. 24ECh. P.1 - Prob. 25ECh. P.1 - Prob. 26ECh. P.1 - Prob. 27ECh. P.1 - Prob. 28ECh. P.1 - Prob. 29ECh. P.1 - Prob. 30ECh. P.1 - Prob. 31ECh. P.1 - Prob. 32ECh. P.1 - Prob. 33ECh. P.1 - Prob. 34ECh. P.1 - Prob. 35ECh. P.1 - Prob. 36ECh. P.1 - Prob. 37ECh. P.1 - Prob. 38ECh. P.1 - Prob. 39ECh. P.1 - Prob. 40ECh. P.1 - Prob. 41ECh. P.1 - Prob. 42ECh. P.1 - Prob. 43ECh. P.1 - Prob. 44ECh. P.1 - Prob. 45ECh. P.1 - Prob. 46ECh. P.1 - Prob. 47ECh. P.1 - In Exercises 4752, simplify the expression. Assume...Ch. P.1 - In Exercises 4752, simplify the expression. Assume...Ch. P.1 - Prob. 50ECh. P.1 - Prob. 51ECh. P.1 - Prob. 52ECh. P.1 - Prob. 53ECh. P.1 - Prob. 54ECh. P.1 - Prob. 55ECh. P.1 - Prob. 56ECh. P.1 - Prob. 57ECh. P.1 - Prob. 58ECh. P.1 - Prob. 59ECh. P.1 - Prob. 60ECh. P.1 - Prob. 61ECh. P.1 - Prob. 62ECh. P.1 - Prob. 63ECh. P.1 - In Exercises 63 and 64, use scientific notation to...Ch. P.1 - Prob. 65ECh. P.1 - Prob. 66ECh. P.1 - Prob. 67ECh. P.1 - Prob. 68ECh. P.1 - Prob. 69ECh. P.1 - Prob. 70ECh. P.1 - Prob. 71ECh. P.1 - Prob. 72ECh. P.1 - Prob. 73ECh. P.1 - Prob. 74ECh. P.1 - Prob. 75ECh. P.1 - Prob. 76ECh. P.2 - Prob. 1QRCh. P.2 - Prob. 2QRCh. P.2 - Prob. 3QRCh. P.2 - Prob. 4QRCh. P.2 - Prob. 5QRCh. P.2 - Prob. 6QRCh. P.2 - Prob. 7QRCh. P.2 - Prob. 8QRCh. P.2 - Prob. 9QRCh. P.2 - Prob. 10QRCh. P.2 - Prob. 1ECh. P.2 - Prob. 2ECh. P.2 - Prob. 3ECh. P.2 - Prob. 4ECh. P.2 - Prob. 5ECh. P.2 - Prob. 6ECh. P.2 - Prob. 7ECh. P.2 - Prob. 8ECh. P.2 - Prob. 9ECh. P.2 - Prob. 10ECh. 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P.6 - Prob. 53ECh. P.6 - Prob. 54ECh. P.6 - Prob. 55ECh. P.6 - Prob. 56ECh. P.6 - Prob. 57ECh. P.7 - Prob. 1QRCh. P.7 - Prob. 2QRCh. P.7 - Prob. 3QRCh. P.7 - Prob. 4QRCh. P.7 - Prob. 5QRCh. P.7 - Prob. 6QRCh. P.7 - Prob. 7QRCh. P.7 - Prob. 8QRCh. P.7 - Prob. 9QRCh. P.7 - Prob. 10QRCh. P.7 - Prob. 1ECh. P.7 - Prob. 2ECh. P.7 - Prob. 3ECh. P.7 - Prob. 4ECh. P.7 - Prob. 5ECh. P.7 - Prob. 6ECh. P.7 - Prob. 7ECh. P.7 - Prob. 8ECh. P.7 - Prob. 9ECh. P.7 - Prob. 10ECh. P.7 - Prob. 11ECh. P.7 - Prob. 12ECh. P.7 - Prob. 13ECh. P.7 - Prob. 14ECh. P.7 - Prob. 15ECh. P.7 - Prob. 16ECh. P.7 - Prob. 17ECh. P.7 - Prob. 18ECh. P.7 - Prob. 19ECh. P.7 - Prob. 20ECh. P.7 - Prob. 21ECh. P.7 - Prob. 22ECh. P.7 - Prob. 23ECh. P.7 - Prob. 24ECh. P.7 - Prob. 25ECh. P.7 - Prob. 26ECh. P.7 - Prob. 27ECh. P.7 - Prob. 28ECh. P.7 - Prob. 29ECh. P.7 - Prob. 30ECh. P.7 - Prob. 31ECh. P.7 - Prob. 32ECh. P.7 - Prob. 33ECh. P.7 - Prob. 34ECh. P.7 - Prob. 35ECh. P.7 - Prob. 36ECh. P.7 - Prob. 37ECh. P.7 - Prob. 38ECh. P.7 - Prob. 39ECh. P.7 - Prob. 40ECh. P.7 - Prob. 41ECh. P.7 - Prob. 42ECh. P.7 - Prob. 43ECh. P.7 - Prob. 44ECh. P.7 - Prob. 45ECh. P.7 - Prob. 46ECh. P.7 - Prob. 47ECh. P.7 - Prob. 48ECh. P - Prob. 1RECh. P - Prob. 2RECh. P - Prob. 3RECh. P - Prob. 4RECh. P - In Exercises 5 and 6, simplify the expression....Ch. P - Prob. 6RECh. P - Prob. 7RECh. P - Prob. 8RECh. P - Prob. 9RECh. P - Prob. 10RECh. P - Prob. 11RECh. P - Prob. 12RECh. P - Prob. 13RECh. P - Prob. 14RECh. P - Prob. 15RECh. P - Prob. 16RECh. P - Prob. 17RECh. P - Prob. 18RECh. P - Prob. 19RECh. P - Prob. 20RECh. P - Prob. 21RECh. P - Prob. 22RECh. P - Prob. 23RECh. P - Prob. 24RECh. P - Prob. 25RECh. P - Prob. 26RECh. P - Prob. 27RECh. P - Prob. 28RECh. P - Prob. 29RECh. P - Prob. 30RECh. P - Prob. 31RECh. P - Prob. 32RECh. P - Prob. 33RECh. P - Prob. 34RECh. P - Prob. 35RECh. P - Prob. 36RECh. P - Prob. 37RECh. P - Prob. 38RECh. P - Prob. 39RECh. P - Prob. 40RECh. P - Prob. 41RECh. P - Prob. 42RECh. P - Prob. 43RECh. 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After making the substitution x = = tan 0, the definite integral 2 2 3 a) ៖ ស្លឺ sin s π - dᎾ 16 0 cos20 b) 2/4 10 cos 20 π sin30 6 - dᎾ c) Π 1 cos³0 3 · de 16 0 sin20 1 x²√x²+4 3 (4x²+9)2 π d) cos²8 16 0 sin³0 dx d) x = tan 0 dx simplifies to: de 6. In order to evaluate (tan 5xsec7xdx, which would be the most appropriate strategy? a) Separate a sec²x factor b) Separate a tan²x factor c) Separate a tan xsecx factor 7. Evaluate 3x x+4 - dx 1 a) 3x+41nx + 4 + C b) 31n|x + 4 + C c) 3 ln x + 4+ C d) 3x - 12 In|x + 4| + C x+4arrow_forward1. Abel's Theorem. The goal in this problem is to prove Abel's theorem by following a series of steps (each step must be justified). Theorem 0.1 (Abel's Theorem). If y1 and y2 are solutions of the differential equation y" + p(t) y′ + q(t) y = 0, where p and q are continuous on an open interval, then the Wronskian is given by W (¥1, v2)(t) = c exp(− [p(t) dt), where C is a constant that does not depend on t. Moreover, either W (y1, y2)(t) = 0 for every t in I or W (y1, y2)(t) = 0 for every t in I. 1. (a) From the two equations (which follow from the hypotheses), show that y" + p(t) y₁ + q(t) y₁ = 0 and y½ + p(t) y2 + q(t) y2 = 0, 2. (b) Observe that Hence, conclude that (YY2 - Y1 y2) + P(t) (y₁ Y2 - Y1 Y2) = 0. W'(y1, y2)(t) = yY2 - Y1 y2- W' + p(t) W = 0. 3. (c) Use the result from the previous step to complete the proof of the theorem.arrow_forward2. Observations on the Wronskian. Suppose the functions y₁ and y2 are solutions to the differential equation p(x)y" + q(x)y' + r(x) y = 0 on an open interval I. 1. (a) Prove that if y₁ and y2 both vanish at the same point in I, then y₁ and y2 cannot form a fundamental set of solutions. 2. (b) Prove that if y₁ and y2 both attain a maximum or minimum at the same point in I, then y₁ and Y2 cannot form a fundamental set of solutions. 3. (c) show that the functions & and t² are linearly independent on the interval (−1, 1). Verify that both are solutions to the differential equation t² y″ – 2ty' + 2y = 0. Then justify why this does not contradict Abel's theorem. 4. (d) What can you conclude about the possibility that t and t² are solutions to the differential equation y" + q(x) y′ + r(x)y = 0?arrow_forwardQuestion 4 Find an equation of (a) The plane through the point (2, 0, 1) and perpendicular to the line x = y=2-t, z=3+4t. 3t, (b) The plane through the point (3, −2, 8) and parallel to the plane z = x+y. (c) The plane that contains the line x = 1+t, y = 2 − t, z = 4 - 3t and is parallel to the plane 5x + 2y + z = 1. (d) The plane that passes through the point (1,2,3) and contains the line x = 3t, y = 1+t, and z = 2-t. (e) The plane that contains the lines L₁: x = 1 + t, y = 1 − t, z = 2t and L2 : x = 2 − s, y = s, z = 2.arrow_forwardPlease find all values of x.arrow_forward3. Consider the initial value problem 9y" +12y' + 4y = 0, y(0) = a>0: y′(0) = −1. Solve the problem and find the value of a such that the solution of the initial value problem is always positive.arrow_forward5. Euler's equation. Determine the values of a for which all solutions of the equation 5 x²y" + axy' + y = 0 that have the form (A + B log x) x* or Ax¹¹ + Bä” tend to zero as a approaches 0.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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