Concept explainers
a.
To write the student loan debt in 2010 in scientific notation.
Given:
The table,
Time (years) | Student Loan Debt (Billions of $) |
2010 | 803.5 |
2011 | 866.3 |
2012 | 959.9 |
2013 | 1071.0 |
2014 | 1155.5 |
Concept Used:
- A number in scientific notation contains a nonzero integer followed by a decimal and some nonzero integer exponent over 10.
- If the decimal point moved to the left side, raise the exponent of 10 by the positive integer digit by which the decimal moved to left.
- If the decimal point moved to the right side, raise the exponent of 10 by the negative integer digit by which the decimal moved to left.
Calculation:
From the given table, note that the student loan debt in 2010 is
Thus, the student loan debt in 2010 in scientific notation is
b.
To write the student loan debt in 2011 in scientific notation.
Given:
The table,
Time (years) | Student Loan Debt (Billions of $) |
2010 | 803.5 |
2011 | 866.3 |
2012 | 959.9 |
2013 | 1071.0 |
2014 | 1155.5 |
Concept Used:
- A number in scientific notation contains a nonzero integer followed by a decimal and some nonzero integer exponent over 10.
- If the decimal point moved to the left side, raise the exponent of 10 by the positive integer digit by which the decimal moved to left.
- If the decimal point moved to the right side, raise the exponent of 10 by the negative integer digit by which the decimal moved to left.
Calculation:
From the given table, note that the student loan debt in 2011 is
Thus, the student loan debt in 2011 in scientific notation is
c.
To write the student loan debt in 2012 in scientific notation.
Given:
The table,
Time (years) | Student Loan Debt (Billions of $) |
2010 | 803.5 |
2011 | 866.3 |
2012 | 959.9 |
2013 | 1071.0 |
2014 | 1155.5 |
Concept Used:
- A number in scientific notation contains a nonzero integer followed by a decimal and some nonzero integer exponent over 10.
- If the decimal point moved to the left side, raise the exponent of 10 by the positive integer digit by which the decimal moved to left.
- If the decimal point moved to the right side, raise the exponent of 10 by the negative integer digit by which the decimal moved to left.
Calculation:
From the given table, note that the student loan debt in 2012 is
Thus, the student loan debt in 2012 in scientific notation is
d.
To write the student loan debt in 2013 in scientific notation.
Given:
The table,
Time (years) | Student Loan Debt (Billions of $) |
2010 | 803.5 |
2011 | 866.3 |
2012 | 959.9 |
2013 | 1071.0 |
2014 | 1155.5 |
Concept Used:
- A number in scientific notation contains a nonzero integer followed by a decimal and some nonzero integer exponent over 10.
- If the decimal point moved to the left side, raise the exponent of 10 by the positive integer digit by which the decimal moved to left.
- If the decimal point moved to the right side, raise the exponent of 10 by the negative integer digit by which the decimal moved to left.
Calculation:
From the given table, note that the student loan debt in 2013 is
Thus, the student loan debt in 2013 in scientific notation is
e.
To write the student loan debt in 2014 in scientific notation.
Given:
The table,
Time (years) | Student Loan Debt (Billions of $) |
2010 | 803.5 |
2011 | 866.3 |
2012 | 959.9 |
2013 | 1071.0 |
2014 | 1155.5 |
Concept Used:
- A number in scientific notation contains a nonzero integer followed by a decimal and some nonzero integer exponent over 10.
- If the decimal point moved to the left side, raise the exponent of 10 by the positive integer digit by which the decimal moved to left.
- If the decimal point moved to the right side, raise the exponent of 10 by the negative integer digit by which the decimal moved to left.
Calculation:
From the given table, note that the student loan debt in 2014 is
Thus, the student loan debt in 2014 in scientific notation is
Chapter P Solutions
PRECALCULUS:GRAPHICAL,...-W/ACCESS
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- Problem 4. Let f(x, y) = { Find P(X <1/2|Y = 1/2). c(x + y²) 0arrow_forwardQize f(x) x + 2x2 - 2 x² + 4x² - 4 Solve the equation using Newton Raphsonarrow_forwardSolve please thanks!arrow_forwardSolve please and thank youarrow_forwardAccording to Newton's law of universal gravitation, the force F between two bodies of constant mass GmM m and M is given by the formula F = , where G is the gravitational constant and d is the d² distance between the bodies. a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to distance d. F' (d) 2GmM b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation, rounding to 2 decimal places. -6.67x10 N/m syntax incomplete.arrow_forwardSolve please and thank youarrow_forwardmv2 The centripetal force of an object of mass m is given by F (r) = rotation and r is the distance from the center of rotation. ' where v is the speed of r a. Find the rate of change of centripetal force with respect to the distance from the center of rotation. F(r) b. Find the rate of change of centripetal force of an object with mass 500 kilograms, velocity of 13.86 m/s, and a distance from the center of rotation of 300 meters. Round to 2 decimal places. N/m (or kg/s²) F' (300)arrow_forwardSolve work shown please and thanks!arrow_forwardGiven the following graph of the function y = f(x) and n = = 6, answer the following questions about the area under the curve from x graph to enlarge it.) 1 (Round your answer to within two decimal places if necessary, but do not round until your final computation.) a. Use the Trapezoidal Rule to estimate the area. Estimate: T6 G b. Use Simpson's Rule to estimate the area. Estimate: S6 - ID = 0 to x = 6. (Click on aarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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