EBK FINITE MATHEMATICS WITH APPLICATION
EBK FINITE MATHEMATICS WITH APPLICATION
12th Edition
ISBN: 9780134776361
Author: MULLINS
Publisher: VST
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Textbook Question
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Chapter P, Problem 1PST

Find the most simplified answer for the given problems involving fractions:

5 2 6 =

Expert Solution & Answer
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To determine

To find:

The most simplified answer for the problem “526=” involving fractions.

Answer to Problem 1PST

Solution:

The simplified answer is 72.

Explanation of Solution

Definition:

For all expressions P, Q, R, with Q0, PQ+RQ=P+RQ and PQRQ=PRQ.

If the fractions have different denominators, find the common denominator and then proceed as indicated above.

Calculation:

The given expression is 526.

The number 6 can be written in fraction as 61.

Rewriting the given expression, 5261.

Here 2 is the common denominator, because it has each of 2, 1 as factors.

526=5261=526(2)1(2)=52122=5122=72526=72

Hence, the simplified answer for the given problem is 72.

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