
Concept explainers
(a)
Interpretation:
For the given compound, the IUPAC name is to be assigned.
Concept introduction:
In naming organic compounds, the
(b)
Interpretation:
For the given compound, the IUPAC name is to be assigned.
Concept introduction:
In naming organic compounds, the functional groups other than highest priority functional groups are treated as substituents. The root name is established by identifying the longest carbon chain or a ring containing functional group. Remove the “e” from the normal ‘ane’, ‘ene’, or ‘yne’ ending and add the suffix that corresponds to the highest-priority functional group. If ‘amide’ is present as the highest priority group attached directly to the ring, both the ring and the functional group establish the root name. The ring is named first followed by ‘carboxamide’.
Number the carbon chain in a way that the functional group and the substituents attached get the lowest number. The position of the functional group and substituents on the parent chain or ring is indicated by the respective locant number just before the suffix. The substituent groups are written in alphabetical order when writing the IUPAC name.
(c)
Interpretation:
For the given compound, the IUPAC name is to be assigned.
Concept introduction:
In naming organic compounds, the functional groups other than highest priority functional groups are treated as substituents. The root name is established by identifying the longest carbon chain or a ring containing functional group. Remove the “e” from the normal ‘ane’, ‘ene’, or ‘yne’ ending and add the suffix that corresponds to the highest-priority functional group. If the highest priority group is present twice then no need to remove ‘e’ from‘ane’, ‘ene’, or ‘yne’ ending and prefixes are used to denote number of identical functional groups. Number the carbon chain in a way that the functional group and the substituents attached gets lowest number. The position of the functional group and substituents on parent chain or ring is indicated by the respective locant number just before the suffix. The substituent groups are written in alphabetical order when writing the IUPAC name.
(d)
Interpretation:
For the given compound, the IUPAC name is to be assigned.
Concept introduction:
In naming organic compounds, the functional groups other than highest priority functional groups are treated as substituents. The root name is established by identifying the longest carbon chain or a ring containing functional group. Remove the “e” from the normal ‘ane’, ‘ene’, or ‘yne’ ending and add the suffix that corresponds to the highest-priority functional group. If the highest priority group is present twice then no need to remove ‘e’ from‘ane’, ‘ene’, or ‘yne’ ending and prefixes are used to denote number of identical functional groups. Number the carbon chain in a way that the functional group and the substituents attached get the lowest number. The position of the functional group and substituents on the parent chain or ring is indicated by the respective locant number just before the suffix. The substituent groups are written in alphabetical order when writing the IUPAC name.

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Chapter F Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
- If 10 mL of a commercial sodium silicate solution is added, the water required to obtain a 20% solids solution (SiO2+Na2O) is added. Indicate the final grams of Na2SiO3.arrow_forwardPlease help me figure out the mechanism with arrows of the following reactionarrow_forwardOrganic Functional Groups Predicting the reactants or products of acetal hydrolysis termine the structures of the missing organic molecules in the following reaction: H* H* + H₂O Y ☑ Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structures of the missing organic molecules X, Y, and Z. You may draw that you like, so long as they aren't touching. Molecule X shows up in multiple steps, but you only have to draw its structure Explanation Check @2 W Click and drag to start drawing a structure. #4 # 3 LU E % 67 olo 5 66 R T Y & 7 AcGraw Hill LLC. All Rights R Xarrow_forward
- 8. (16 pts) Provide the stepwise mechanism for the synthesis of the following compound via an enaminearrow_forwardDraw the titration curve of (i) weak acid vs. strong base; (ii) weak acid vs. weakbase; (iii) diprotic acid with strong base (iii) triprotic acid with strong base.arrow_forwardComplete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. my ㄖˋ + 1. Na O Me Click and drag to start drawing a structure. 2. H +arrow_forward
- Predict the intermediate 1 and final product 2 of this organic reaction: NaOMe H+ + 1 2 H H work up You can draw 1 and 2 in any arrangement you like. Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center. Click and drag to start drawing a structure. X $ dmarrow_forwardPredict the major products of this organic reaction: 1. NaH (20°C) 2. CH3Br ? Some notes: • Draw only the major product, or products. You can draw them in any arrangement you like. • Be sure to use wedge and dash bonds where necessary, for example to distinguish between major products that are enantiomers. • If there are no products, just check the box under the drawing area. No reaction. Click and drag to start drawing a structure. G Crarrow_forwardPredict the major products of this organic reaction: 1. LDA (-78°C) ? 2. Br Some notes: • Draw only the major product, or products. You can draw them in any arrangement you like. . • Be sure to use wedge and dash bonds where necessary, for example to distinguish between major products that are enantiomers. • If there are no products, just check the box under the drawing area. No reaction. Click and drag to start drawing a structure. Xarrow_forward
- Please draw the structuresarrow_forwardDraw the missing intermediates 1 and 2, plus the final product 3, of this synthesis: 0 1. Eto 1. Eto- 1 2 2. MeBr 2. EtBr H3O+ A 3 You can draw the three structures in any arrangement you like. Explanation Check Click and drag to start drawing a structure.arrow_forwardDraw the missing intermediate 1 and final product 2 of this synthesis: 1. MeO- H3O+ 1 2 2. PrBr Δ You can draw the two structures in any arrangement you like. Click and drag to start drawing a structure.arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning


