ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE
ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE
2nd Edition
ISBN: 9780393666144
Author: KARTY
Publisher: NORTON
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Chapter D, Problem D.1P
Interpretation Introduction

Interpretation:

The orbital interaction that represents hyperconjugation in CF3CH2+ is to be drawn. The hyperconjugation lead to greater stabilization in this CF3CH2+ or in CH3CH2+ would expect is to be explained.

Concept introduction:

Relative stabilities of carbocations are explained by hyperconjugation. In the case of primary carbocations like RCH2+, ρ AO is aligned with one of the C-H bonds in the adjacent R group, which represents a pair of electrons occupying a C-Hσ bonding orbital. The empty ρ AO and the σ bonding orbital therefore interact. In this case, constructive interference results in a new orbital that is more stable than the σ bonding orbital. The two electrons from the σ bonding MO end up in the lower-energy of the two new orbitals and are thus stabilized. The mixing of these orbitals effectively transfers some electron density from the alkyl group into the empty ρ AO.

Expert Solution & Answer
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Answer to Problem D.1P

The orbital interaction that represents hyperconjugation in CF3CH2+ is,

ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE, Chapter D, Problem D.1P , additional homework tip  1

The hyperconjugation leads to greater stabilization for the CH3CH2+ ion.

Explanation of Solution

In CF3CH2+ ion, the filled σ bonding orbital is of the adjacent C-F bond of CF3 which can interact with the empty ρ AO of CH2+ as the empty ρ AO overlaps with σ bonding orbital of the C-F bond. It is shown below:

ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE, Chapter D, Problem D.1P , additional homework tip  2

Also, in CH3CH2+, the empty ρ AO overlaps with σ bonding orbital of CH3 bond of CH3, so the two orbitals can interact. The two electrons from the σ bonding MO end up in the lower-energy of the two new orbitals and are thus stabilized.

The orbital interactions for both CF3CH2+ and CH3CH2+ are shown below,

ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE, Chapter D, Problem D.1P , additional homework tip  3

The F atom is more electronegative than H, therefore the C-Fσ bonding orbital is in lower energy than that of the CH3 bond of CH3CH2+. Therefore, the ΔE for the overlap of the empty ρ AO with C-Fσ bonding orbital is smaller than that for overlap of the empty ρ AO and CH3σ bonding orbital. Thus, hyperconjugation leads to greater stabilization for the CH3CH2+ ion.

Conclusion

The cation in which hyperconjugation would leads to greater stabilization is determined on the basis of orbital interactions shown above.

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Choose the Lewis structure for the compound below: H2CCHOCH2CH(CH3)2 HH H :d H H H C. Η H H HH H H H H. H H H HH H H H H H- H H H C-H H H HHHH
Each of the highlighted carbon atoms is connected to hydrogen atoms.
く Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. Explanation Check O + G 1. Na O Me Click and drag to start drawing a structure. 2. H + 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 000 Ar P
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