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(a)
Interpretation:
The structure for each of the given name is to be drawn.
Concept introduction:
In case of rings containing seven or less than seven carbon atoms, the Z/E configuration is usually omitted for double bonds which are a part of the ring. The E configuration about the double bond is not stable due to ring strain. It is understood that the double bonded carbon atoms have a configuration such that they are cis to each other. In case of rings consisting of more than seven carbon atoms, the double bond, which is a part of the ring, can have E or Z configuration.
If the higher priority groups, attached to the double bonded carbon atoms, are on the same side of the double bond, the
(b)
Interpretation:
The structure for each of the given name is to be drawn.
Concept introduction:
In case of rings containing seven or less than seven carbon atoms, the Z/E configuration is usually omitted for the double bonds which are a part of the ring. The E configuration about the double bond is not stable due to ring strain. It is understood that the double bonded carbon atoms have a configuration such that they are cis to each other. In case of rings consisting of more than seven carbon atoms, the double bond, which is a part of the ring, can have E or Z configuration.
If the higher priority groups, attached to the double bonded carbon atoms, are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups, attached to the double bonded carbon atoms, are on the opposite side of the double bond, the alkene is assigned E configuration.
(c)
Interpretation:
The structure for each of the given name is to be drawn.
Concept introduction:
In case of rings containing seven or less than seven carbon atoms, the Z/E configuration is usually omitted for the double bonds which are a part of the ring. The E configuration about the double bond is not stable due to ring strain. It is understood that the double bonded carbon atoms have a configuration such that they are cis to each other. In case of rings consisting of more than seven carbon atoms, the double bond which is a part of the ring can have E or Z configuration.
If the higher priority groups, attached to the double bonded carbon atoms, are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups, attached to the double bonded carbon atoms, are on the opposite side of the double bond, the alkene is assigned E configuration.
(d)
Interpretation:
The structure for each of the given name is to be drawn.
Concept introduction:
In case of rings containing seven or less than seven carbon atoms, the Z/E configuration is usually omitted for the double bonds which are a part of the ring. The E configuration about the double bond is not stable due to ring strain. It is understood that the double bonded carbon atoms have a configuration such that they are cis to each other. In case of rings consisting of more than seven carbon atoms, the double bond which is a part of the ring can have E or Z configuration.
If the higher priority groups, attached to the double bonded carbon atoms, are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups, attached to the double bonded carbon atoms, are on the opposite side of the double bond, the alkene is assigned E configuration.
(e)
Interpretation:
The structure for the given name is to be drawn.
Concept introduction:
In case of rings containing seven or less than seven carbon atoms, the Z/E configuration is usually omitted for the double bonds which are a part of the ring. The E configuration about the double bond is not stable due to ring strain. It is understood that the double bonded carbon atoms have a configuration such that they are cis to each other. In case of rings consisting of more than seven carbon atoms, the double bond which is a part of the ring can have E or Z configuration.
If the higher priority groups, attached to the double bonded carbon atoms, are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups, attached to the double bonded carbon atoms, are on the opposite side of the double bond, the alkene is assigned E configuration.
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Chapter C Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- Draw and name the cis and trans (or Z and E) isomers of those that do.(a) hex-3-ene (b) buta-1,3-diene (c) hexa-2,4-dienearrow_forward(a) (CH3)3CBr classify the compound as a methyl, primary, secondary, or tertiary halide.arrow_forwardDraw the structures for each of the following molecules. (a) 2-fluorotoluene; (b) 4-ethoxytoluene; (c) 2-ethoxyanisole;(d) 1,3-diphenylheptane; (e) 4,4-diphenyl-1-octene; (f) benzylbenzenearrow_forward
- (b) 3-Chloro-1,4-hexadiene (R), (Z) isomer name: (S), (Z) isomer name: (R), (E) isomer name: (S), (E) isomer name:arrow_forwardPlease explain how to solve problemarrow_forwardIn each of the following groups of compounds, identify the one with the largest heat of combustion and the one with the smallest. (a) Hexane, heptane, octane (b) 2-Methylpropane, pentane, 2-methylbutane (c) 2-Methylbutane, 2-methylpentane, 2,2-dimethylpropane (d) Pentane, 3-methylpentane, 3,3-dimethylpentane (e) Ethylcyclopentane, ethylcyclohexane, ethylcycloheptanearrow_forward
- Draw structures for the following molecules. (a) 3-bromo-2-nitropentane; (b) 2,2-dichloro-4,4,5-trinitroheptane;(c) 1,2,3,4-tetranitrobutane; (d) 6-iodo-1,2-difluorohexanearrow_forward(b) Draw the structural formula for each of the following compounds. Lukiskan formula struktur bagi setiap sebatian berikut. (i) 3-fluoro-2,4,4-trimethylpent-2-ene (ii) ethyl butanoate (ii) 2,4-dichloro-3-methylpentanoic acidarrow_forwardplease ensure its legiblearrow_forward
- Draw the most stable conformation of cis-1-tert-butyl-3-ethylcyclohexane. (a) (b) trans-1-tert-butyl-2-methylcyclohexane. (c) trans-1-tert-butyl-3-(1,1-dimethylpropyl)cyclohexane.arrow_forward(a) (R)-1,1,2-trimethylcyclohexane, draw any enantiomer.arrow_forwardGive detailed Solution with explanation needed..don't give Handwritten answerarrow_forward
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