Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
9th Edition
ISBN: 9781259989452
Author: Hayt
Publisher: Mcgraw Hill Publishers
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Chapter A5.2, Problem 4P
(a)
To determine
The value of
(b)
To determine
The value of
(c)
To determine
The value of
(d)
To determine
The value of
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MY code is experiencing a problem as I want to show both the magnitude ratio on low pass, high pass, and bandbass based on passive filters:
Code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2*pi*f; % Angular frequency
% Parameters for the filters (you can modify these)
R = 1e3; % Resistance in ohms (1 kOhm)
C = 1e-6; % Capacitance in farads (1 uF)
L = 10e-3; % Inductance in henries (10 mH)
% Transfer function for Low-pass filter: H_low = 1 / (1 + jωRC)
H_low = 1 ./ (1 + 1i*w*R*C);
% Transfer function for High-pass filter: H_high = jωRC / (1 + jωRC)
H_high = 1i*w*R*C ./ (1 + 1i*w*R*C);
% Transfer function for Band-pass filter: H_band = jωRC / (1 + jωL/R + jωRC)
H_band = 1i*w*R*C ./ (1 + 1i*w*L/R + 1i*w*R*C);
% Plot magnitude responses
figure;
subplot(3,1,1);
semilogx(f, 20*log10(abs(H_low))); % Low-pass filter
title('Magnitude Response of Low-pass Filter');
xlabel('Frequency (Hz)');
ylabel('Magnitude (dB)');
grid…
*10. For the network of Fig. 7.83, determine:
a. Ip.
b. VDS.
c. VD.
d. Vs.
20 V
2.2 ΚΩ
ID
-4 V
IDSS
= 4.5 mA
VDS
Vp = -5V
0.68 ΚΩ
4. a. Determine VDs for VGS = 0 V and ID = 6 mA using the characteristics of Fig. 6.11.
b. Using the results of part (a), calculate the resistance of the JFET for the region ID = 0 to
6 mA for VGS = 0 V.
c. Determine VDs for VGS = -1 V and ID = 3 mA.
d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to
3 mA for VGS = -1 V.
e. Determine VDs for VGS = -2 V and ID = 1.5 mA.
f. Using the results of part (e), calculate the resistance of the JFET for the region ID
1.5 mA for VGS = -2 V.
g. Defining the result of part (b) as ro, determine the resistance for VGS
Eq. (6.1) and compare with the results of part (d).
= 0 to
= -1 V using
h. Repeat part (g) for VGS = -2 V using the same equation, and compare the results with part (f).
i. Based on the results of parts (g) and (h), does Eq. (6.1) appear to be a valid approximation?
Chapter A5 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
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