In Problems 35 - 42 , imagine that the indicated “solutions” were given to you by a student whom you were tutoring in this class. (A) Is the solution correct?. If the solution is incorrect, explain what is wrong and how it can be corrected. (B) Show a correct solution for each incorrect solution. x + x − 2 x 2 − 3 x + 2 = x + x − 2 x 2 − 3 x + 2 = 2 x − 2
In Problems 35 - 42 , imagine that the indicated “solutions” were given to you by a student whom you were tutoring in this class. (A) Is the solution correct?. If the solution is incorrect, explain what is wrong and how it can be corrected. (B) Show a correct solution for each incorrect solution. x + x − 2 x 2 − 3 x + 2 = x + x − 2 x 2 − 3 x + 2 = 2 x − 2
Solution Summary: The author explains that if the given solution is incorrect, it can be corrected by adding the denominator of the second tion.
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Chapter A Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences Plus NEW MyLab Math with Pearson eText -- Access Card Package (13th Edition)
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Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY