EBK USING MIS
10th Edition
ISBN: 9780134658919
Author: KROENKE
Publisher: YUZU
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Chapter 9.9, Problem 9.4ARQ
Explanation of Solution
Five Basic Reporting Operations:
Reporting Application:
In order to produce Business Intelligence, a reporting application combines data from various sources and apply reporting operations to those data.
- Reporting applies simple operations to reveal patterns in the data. The analysis of the data is modest.
- Data are sorted and grouped, and simple totals and averages are calculated using operations such as reporting applications use of five basic operations:
- Sorting – It arranges the data systematically as per requirement.
- Filtering – It cleans the data by clearing the errors.
- Grouping – It groups the data into data sets with a particular pattern.
- Calculating – It performs all the required calculations to the data sets in order to extract knowledge.
- Formatting- It formats all the calculated data in order to make the data ready for operational use.
Example of reporting:
The common examples of reporting is swimming, and totaling.
RFM analysis:
RFM stands for Recency, Frequency and Monetary. It is an analytical technique to determine which customers are best among all by checking recent purchase date (Recency), how often the customer purchases (frequency) and how much the customer spends (monetary).
A) Customers having a score of [5, 5, 5]
- A customer in the following group has the highest points in recency, frequency and monetary. It shows that he or she is a loyal and very important customer and deserves highest level of service to reward his or her loyalty.
B) Customers having a score of [1, 5, 5]
- A customer in the following group has the lowest points in recency, frequency and monetary and lies in the middle group. It shows that he or she is a loyal and very important customer and effort need to be made to find out the reasons for which he or she has not been a recent customer. Efforts need to be made to ask the customer for feedback for previous purchases and exclusive offer and combo deals for him or her can be send via email.
C) Customers having a score of [5, 5, 3]
- A customer in the following group has best points in recency and best points in frequency and average points in monetary and lies in the next to top group. It shows that he or she is a loyal customer but likes to spend less. This type of customer is best for upselling and efforts should be made to have various lucrative combined deals and combined packages to entice him or her to buy higher value items...
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Students have asked these similar questions
make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 9 Solutions
EBK USING MIS
Ch. 9.3 - Prob. 1EGDQCh. 9.3 - Prob. 2EGDQCh. 9.3 - Prob. 3EGDQCh. 9.3 - Prob. 4EGDQCh. 9.6 - Prob. 1BFSQCh. 9.6 - Prob. 2BFSQCh. 9.6 - Prob. 3BFSQCh. 9.6 - Prob. 4BFSQCh. 9.9 - Prob. 1SGDQCh. 9.9 - Prob. 2SGDQ
Ch. 9.9 - Prob. 3SGDQCh. 9.9 - Prob. 4SGDQCh. 9.9 - Prob. 5SGDQCh. 9.9 - Prob. 9.1ARQCh. 9.9 - Prob. 9.2ARQCh. 9.9 - Prob. 9.3ARQCh. 9.9 - Prob. 9.4ARQCh. 9.9 - Prob. 9.5ARQCh. 9.9 - Prob. 9.6ARQCh. 9.9 - Prob. 9.8ARQCh. 9.9 - Prob. 9.9ARQCh. 9 - Prob. 9.1UYKCh. 9 - Prob. 9.2UYKCh. 9 - Prob. 9.3UYKCh. 9 - Prob. 9.4UYKCh. 9 - Prob. 9.5UYKCh. 9 - Prob. 9.6UYKCh. 9 - Prob. 9.7UYKCh. 9 - Prob. 9.8UYKCh. 9 - Prob. 9.9CE9Ch. 9 - Prob. 9.1CE9Ch. 9 - Prob. 9.11CE9Ch. 9 - Prob. 9.12CE9Ch. 9 - Prob. 9.13CE9Ch. 9 - Prob. 9.14CE9Ch. 9 - Prob. 9.15CE9Ch. 9 - Prob. 9.16CS9Ch. 9 - Prob. 9.17CS9Ch. 9 - Prob. 9.18CS9Ch. 9 - Prob. 9.19CS9Ch. 9 - Prob. 9.22MML
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