Chapter 9.9, Problem 8OE

To determine

To find two ordered triplets -

  $3x+z=0$

Answer to Problem 8OE

Two ordered triplets are $\left(0,0,0\right)$ and $\left(1,0,-3\right)$ .

Explanation of Solution

Given:

  $3x+z=0$

Calculation:

Given:

  $3x+z=0$

Since the value of $y=0$ ;

Let $x=0$ and $z=0$

Thus, L.H.S. $=$$3x+z=3\times 0+0$

  $3x+z=0$

Thus, first ordered triplet is $\left(0,0,0\right)$ .

Now, Let $x=1$ and $z=-3$

Thus, L.H.S. $=$$3x+z=3\times 1+\left(-3\right)$

  $3x+z=3-3=0$

Thus, second ordered triplet is $\left(1,0,-3\right)$ .

Thus, two ordered triplets are $\left(0,0,0\right)$ and $\left(1,0,-3\right)$ .

Conclusion:

Two ordered triplets are $\left(0,0,0\right)$ and $\left(1,0,-3\right)$ .