Chapter 9.7, Problem 2E

To determine

Tofind:The angle with ratio $\frac{12}{5}$

Answer to Problem 2E

  $\angle A$

Explanation of Solution

Given information:

Concept Used:

In a right-angled triangle ABC, tangent for acute angle $\angle A$ is the ratio of length of side opposite to angle $\angle A$ to the length of side adjacent to $\angle A$

Calculation:

Basis definition we can say-

  $\begin{array}{l}\tan A=\frac{opposite}{adjacent}\\ \Rightarrow \tan A=\frac{BC}{AC}\\ \Rightarrow \tan A=\frac{12}{5}\end{array}$

Therefore, $\angle A$ has the ratio $\frac{12}{5}$