Chapter 9.5, Problem 15E

To determine

Tofind:Distance between given points

Answer to Problem 15E

  $d=2.5$

Explanation of Solution

Given information:

  $\begin{array}{l}\left(x_1,y_1\right)=\left(1.5,4\right)\\ \left(x_2,y_2\right)=\left(3,6\right)\end{array}$

Concept Used:

Distance between two points - $d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$

Calculation:

  $\begin{array}{l}d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}\\ \Rightarrow d=\sqrt{{\left(3-1.5\right)}^2+{\left(6-4\right)}^2}\\ \Rightarrow d=\sqrt{{\left(1.5\right)}^2+{\left(2\right)}^2}\\ \Rightarrow d=\sqrt{2.25+4}\\ \Rightarrow d=\sqrt{6.25}\\ \Rightarrow d=2.5\end{array}$