Explanation Given: The vectors are P ( 0 , 1 , 1 ) , Q ( 1 , 1 , 0 ) , R ( 1 , 0 , 1 ) . Concept Used: Area of triangle, A = 1 2 | P Q → × P R → | First we make two vector and apply into formula. P Q → = ( 1 − 0 ) i + ( 1 − 1 ) j + ( 0 − 1 ) k P Q → = i − k P R → = ( 1 − 0 ) i + ( 0 − 1 ) j + ( 1 − 1 ) k P R → = i − j Now calculate the cross product of both vector P Q → × P R → = | i

6th Edition

ISBN: 9781465208880

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 9.4, Problem 23PS

To determine

To find: The area of the triangle PQR, P(0,1,1),Q(1,1,0),R(1,0,1)

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Chapter 9.4, Problem 22PS

Chapter 9.4, Problem 24PS

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Chapter 9 Solutions

Calculus

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The area of the triangle PQR, P ( 0 , 1 , 1 ) , Q ( 1 , 1 , 0 ) , R ( 1 , 0 , 1 )

Solution Summary: The author explains how to find the area of the triangle PQR.

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To find: The area of the triangle PQR, P(0,1,1),Q(1,1,0),R(1,0,1)

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Chapter 9 Solutions