Calculus
Calculus
6th Edition
ISBN: 9781465208880
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
Question
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Chapter 9, Problem 1PE

(a)

To determine

To find:a vector

(a)

Expert Solution
Check Mark

Explanation of Solution

A Vector is a quantity that has both magnitude and direction. A vector PQ is represented as a directed line segment and an arrow with initial point P and terminal point Q .

  Calculus, Chapter 9, Problem 1PE , additional homework tip  1

A vector is indicated by writing an arrow over the designated points P and Q . The order of letters is important.

Vector PQ is the vector from P to Q and PQ is the vector from Q to P

Conclusion:

Therefore, a Vector is a quantity that has both magnitude and direction.

(b)

To determine

To find: a scalar.

(b)

Expert Solution
Check Mark

Explanation of Solution

A scalar is a quantity that has only magnitude, not direction. In context of vectors, a scalar is described as a real number.

For example, PQ is a scalar quantity.

Conclusion:

Therefore, a scalar is a quantity that has only magnitude, not direction.

(c)

To determine

To give: an algebraic and a geometric interpretation of multiplication of a vector by a scalar.

(c)

Expert Solution
Check Mark

Explanation of Solution

When a scalar number c is multiplied by a vector v , the scalar multiple cv will be parallel to the vector v and has length |c| times that of v .

The scalar multiple cv points in the same direction as v if c>0 and in opposite direction if c<0 .

Geometrically, assume that vector v has a magnitude of 3 units and its direction is from point P to point Q .

  Calculus, Chapter 9, Problem 1PE , additional homework tip  2

The scalar multiple 2v will have a magnitude of 2×3=6units and its direction will be parallel to the vector v .

  Calculus, Chapter 9, Problem 1PE , additional homework tip  3

  Calculus, Chapter 9, Problem 1PE , additional homework tip  4

Conclusion:

Therefore,when a scalar number c is multiplied by a vector v , the scalar multiple cv will be parallel to the vector v and has length |c| times that of v .

Geometrically, the scalar multiple 2v will have a magnitude of 2×3=6units and its direction will be parallel to the vector v .

(d)

To determine

To find: parallelogram rule for vector sums

(d)

Expert Solution
Check Mark

Explanation of Solution

The Parallelogram rule states that u+v is the diagonal of the parallelogram formed with sides u and v .

  Calculus, Chapter 9, Problem 1PE , additional homework tip  5

Conclusion:

Therefore, the Parallelogram rule states that u+v is the diagonal of the parallelogram formed with sides u and v .

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Chapter 9 Solutions

Calculus

Ch. 9.1 - Prob. 11PSCh. 9.1 - Prob. 12PSCh. 9.1 - Prob. 13PSCh. 9.1 - Prob. 14PSCh. 9.1 - Prob. 15PSCh. 9.1 - Prob. 16PSCh. 9.1 - Prob. 17PSCh. 9.1 - Prob. 18PSCh. 9.1 - Prob. 19PSCh. 9.1 - Prob. 20PSCh. 9.1 - Prob. 21PSCh. 9.1 - Prob. 22PSCh. 9.1 - Prob. 23PSCh. 9.1 - Prob. 24PSCh. 9.1 - Prob. 25PSCh. 9.1 - Prob. 26PSCh. 9.1 - Prob. 27PSCh. 9.1 - Prob. 28PSCh. 9.1 - Prob. 29PSCh. 9.1 - Prob. 30PSCh. 9.1 - Prob. 31PSCh. 9.1 - Prob. 32PSCh. 9.1 - Prob. 33PSCh. 9.1 - Prob. 34PSCh. 9.1 - Prob. 35PSCh. 9.1 - Prob. 36PSCh. 9.1 - Prob. 37PSCh. 9.1 - Prob. 38PSCh. 9.1 - Prob. 39PSCh. 9.1 - Prob. 40PSCh. 9.1 - Prob. 41PSCh. 9.1 - Prob. 42PSCh. 9.1 - Prob. 43PSCh. 9.1 - Prob. 44PSCh. 9.1 - Prob. 45PSCh. 9.1 - Prob. 46PSCh. 9.1 - Prob. 47PSCh. 9.1 - Prob. 48PSCh. 9.1 - Prob. 49PSCh. 9.1 - Prob. 50PSCh. 9.1 - Prob. 51PSCh. 9.1 - Prob. 52PSCh. 9.1 - Prob. 53PSCh. 9.1 - Prob. 54PSCh. 9.1 - Prob. 55PSCh. 9.1 - Prob. 56PSCh. 9.1 - Prob. 57PSCh. 9.1 - Prob. 58PSCh. 9.1 - Prob. 59PSCh. 9.1 - Prob. 60PSCh. 9.2 - 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Prob. 7PSCh. 9.7 - Prob. 8PSCh. 9.7 - Prob. 9PSCh. 9.7 - Prob. 10PSCh. 9.7 - Prob. 11PSCh. 9.7 - Prob. 12PSCh. 9.7 - Prob. 13PSCh. 9.7 - Prob. 14PSCh. 9.7 - Prob. 15PSCh. 9.7 - Prob. 16PSCh. 9.7 - Prob. 17PSCh. 9.7 - Prob. 18PSCh. 9.7 - Prob. 19PSCh. 9.7 - Prob. 20PSCh. 9.7 - Prob. 21PSCh. 9.7 - Prob. 22PSCh. 9.7 - Prob. 23PSCh. 9.7 - Prob. 24PSCh. 9.7 - Prob. 25PSCh. 9.7 - Prob. 26PSCh. 9.7 - Prob. 27PSCh. 9.7 - Prob. 28PSCh. 9.7 - Prob. 29PSCh. 9.7 - Prob. 30PSCh. 9.7 - Prob. 31PSCh. 9.7 - Prob. 32PSCh. 9.7 - Prob. 33PSCh. 9.7 - Prob. 34PSCh. 9.7 - Prob. 35PSCh. 9.7 - Prob. 36PSCh. 9.7 - Prob. 37PSCh. 9.7 - Prob. 38PSCh. 9.7 - Prob. 39PSCh. 9.7 - Prob. 40PSCh. 9.7 - Prob. 41PSCh. 9.7 - Prob. 42PSCh. 9.7 - Prob. 43PSCh. 9.7 - Prob. 44PSCh. 9.7 - Prob. 45PSCh. 9.7 - Prob. 46PSCh. 9.7 - Prob. 47PSCh. 9.7 - Prob. 48PSCh. 9.7 - Prob. 49PSCh. 9.7 - Prob. 50PSCh. 9.7 - Prob. 51PSCh. 9.7 - Prob. 52PSCh. 9.7 - Prob. 53PSCh. 9.7 - Prob. 54PSCh. 9.7 - Prob. 55PSCh. 9.7 - Prob. 56PSCh. 9.7 - Prob. 57PSCh. 9.7 - 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